Physics 1210: Mechanics Quiz
5 Questions
0 Views

Choose a study mode

Play Quiz
Study Flashcards
Spaced Repetition
Chat to lesson

Podcast

Play an AI-generated podcast conversation about this lesson

Questions and Answers

The time rate of change of linear momentum of a body is equal to:

  • applied force (correct)
  • displacement
  • inertia
  • speed
  • MLT represents the dimension of:

  • pressure
  • frequency
  • density
  • momentum (correct)
  • A car slows down its motion from 10 m/s to 6 m/s in 2 seconds. How far did the car travel during this time interval?

  • 35 m
  • 9 m
  • 16 m (correct)
  • 54 m
  • A moving object slows down from 12 m/s to rest at a distance of 20 m. What is the acceleration of the object?

    <p>-5.1 m/s²</p> Signup and view all the answers

    The gravitational constant G is used to calculate which of the following?

    <p>the force between two masses</p> Signup and view all the answers

    Study Notes

    Physics 1210: Mechanics

    • Constants:
      • Gravity (g) = 10.0 m/s²
      • Gravitational Constant (G) = 6.67 x 10⁻¹¹ Nm²/kg²

    Question 1: Time Rate of Change of Linear Momentum

    • The time rate of change of linear momentum of a body is equal to the applied force.
      • Linear momentum is the product of an object's mass and velocity.
      • The change in momentum is calculated as the mass times the change in velocity.

    Question 2: Dimensional Formula MLT

    • Momentum has the dimensional formula MLT.
      • M = mass, L = length, T = time.
      • Momentum is calculated as mass times velocity.

    Question 3: Constant Acceleration

    • A car decelerates from 10 m/s to 6 m/s in 2 seconds.
    • Determining the acceleration (a) using the formula: a = (vf - vi) / t = (6 - 10) / 2 = -2 m/s².
    • Calculating the distance traveled (s) using the formula: s = vi*t + (1/2)at² = 10 * 2 + (1/2) * -2 * 2² = 16 meters.

    Question 4: Constant Acceleration

    • An object decelerates from 12 m/s to rest (vf = 0 m/s) over 20 meters.
    • Calculating the acceleration (a) using the formula: a = (vf² - vi²) / 2s = ( 0² - 12²) / (2 * 20) = -3.6 m/s².

    Question 5, 6, 7, 8, 9, 10, 11, 12, 13-24

    • Please provide the full question details and the related text because the full questions are needed for an accurate analysis and note-taking.

    Studying That Suits You

    Use AI to generate personalized quizzes and flashcards to suit your learning preferences.

    Quiz Team

    Description

    Test your understanding of the fundamental concepts in Mechanics covered in Physics 1210. This quiz includes questions about linear momentum, dimensional formulas, and constant acceleration calculations. Challenge yourself and solidify your knowledge of these essential physics principles.

    More Like This

    Use Quizgecko on...
    Browser
    Browser