Percent Composition and Empirical Formulas Quiz
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Questions and Answers

What is the main purpose of calculating percent composition in chemistry?

  • To identify the chemical structure of a substance
  • To determine the molecular weight of a compound
  • To balance a chemical equation
  • To find out the percentage of each element in a compound (correct)
  • In the compound CuBr2, bromine contributes more to the mass percent than copper.

    True

    What is the empirical formula for glucose, C6H12O6?

    CH2O

    The percent composition of nitrogen in (NH4)2S is _________.

    <p>21.2%</p> Signup and view all the answers

    Match the compounds with their percent composition by mass of nitrogen:

    <p>NH3 = 82.2% CO(NH2)2 = 40% (NH4)2SO4 = 21.2%</p> Signup and view all the answers

    Which of the following compounds has the highest percentage of mass of nitrogen?

    <p>NH3</p> Signup and view all the answers

    The calculation of percent composition is only needed for ionic compounds.

    <p>False</p> Signup and view all the answers

    How do you determine the percent composition of a compound?

    <p>Calculate the molar mass of each element and divide it by the molar mass of the compound, then multiply by 100.</p> Signup and view all the answers

    What is the empirical formula of C6H12O6?

    <p>C3H6O3</p> Signup and view all the answers

    An empirical formula can show the exact number of atoms of each element in a compound.

    <p>False</p> Signup and view all the answers

    What is the molecular formula of a compound with an empirical formula of C2OH4 and a molecular mass of 88 g/mol?

    <p>C4O2H8</p> Signup and view all the answers

    A sample contains 0.3374g of P, 0.0220g of H, and the remainder is O. The empirical formula is __________.

    <p>H3PO4</p> Signup and view all the answers

    Match the following compounds with their corresponding empirical formulas:

    <p>C2H2 = CH C8H14 = C4H7 C12H22O11 = C12H22O11 C8H18 = C4H9</p> Signup and view all the answers

    How many moles of oxygen (O2) are needed to react with 3.24 moles of ammonia (NH3) in the reaction: _NH3 + _O2 → _NO + _H2O?

    <p>5.00 moles</p> Signup and view all the answers

    If 145.7 grams of manganese (IV) oxide (MnO2) are reacted, how many grams of hydrochloric acid (HCl) are required to completely react with it?

    <p>Requires stoichiometric calculation based on balanced reaction.</p> Signup and view all the answers

    The molar mass of lead (II) nitrate (Pb(NO3)2) is essential for calculating the grams needed to produce a given mass of sodium nitrate (NaNO3).

    <p>True</p> Signup and view all the answers

    What is the percent yield of the reaction if 75.0 g of P4 yields 111.0 g of PCl3?

    <p>65.4%</p> Signup and view all the answers

    In the reaction of Fe(OH)2 with H3PO4, both reactants will yield the same amount of product.

    <p>False</p> Signup and view all the answers

    What is the limiting reagent when 3.20 g of Fe(OH)2 reacts with 2.50 g of H3PO4?

    <p>Fe(OH)2</p> Signup and view all the answers

    When octane (C8H18) is burned, _____ and water are produced.

    <p>carbon dioxide</p> Signup and view all the answers

    Match the following reactions with their expected yields:

    <p>P4 + 6 Cl2 → 4 PCl3 = Mass of PCl3 Fe + CuSO4 → FeSO4 + Cu = Mass of Cu C8H18 + O2 → CO2 + H2O = Mass of H2O produced</p> Signup and view all the answers

    How many grams of water can be produced from the complete combustion of 320 g of octane?

    <p>392 g</p> Signup and view all the answers

    If 98.03 g of Magnesium hydroxide decomposes, no water will be produced.

    <p>False</p> Signup and view all the answers

    How many grams of Fe3(PO4)2 precipitate can be formed from the reaction of Fe(OH)2 and H3PO4?

    <p>Calculated based on limiting reagent and stoichiometry.</p> Signup and view all the answers

    What is the empirical formula for a compound containing 18.7g of C and 6.28g of H?

    <p>C2H7</p> Signup and view all the answers

    Multiple compounds can have different empirical formulas.

    <p>False</p> Signup and view all the answers

    What is needed to determine the true formula of a compound aside from the empirical formula?

    <p>Molar mass</p> Signup and view all the answers

    The ____ reactions tell you how many molecules and/or atoms of each reactant are needed to make the products.

    <p>chemical equations</p> Signup and view all the answers

    Match the following compounds with their respective formulas:

    <p>Sodium Oxide = Na2O Sodium Hydroxide = NaOH Sodium Phosphate = Na3PO4 Glucose = C6H12O6</p> Signup and view all the answers

    In converting element masses to moles, what can be determined?

    <p>Empirical ratio</p> Signup and view all the answers

    The balanced chemical equation for aluminum reacting with oxygen produces aluminum chloride.

    <p>False</p> Signup and view all the answers

    If 24 atoms of aluminum are present, how many molecules of aluminum oxide will be produced?

    <p>12 molecules</p> Signup and view all the answers

    How many moles of calcium carbonate are formed when 0.50 moles of calcium oxide reacts with 0.40 moles of carbon dioxide?

    <p>0.40 moles</p> Signup and view all the answers

    The theoretical yield of ammonia (NH3) can exceed 10.5 g when 15.0 g of nitrogen gas reacts with hydrogen gas.

    <p>False</p> Signup and view all the answers

    If 0.996 g of aluminum hydroxide is recovered from a reaction involving 2.80 g of aluminum nitrate, what is the actual yield of aluminum hydroxide?

    <p>0.996 g</p> Signup and view all the answers

    To produce 30.0 g of aluminum phosphate with a % yield of 73.7%, the theoretical mass of aluminum needed is _____ g.

    <p>40.7</p> Signup and view all the answers

    What information is crucial when calculating the percent yield of a chemical reaction?

    <p>Theoretical yield and actual yield</p> Signup and view all the answers

    Match the chemical reaction types with their appropriate description:

    <p>Combination = Two or more substances combine to form one product Decomposition = A single compound breaks down into two or more products Single Replacement = One element replaces another in a compound Double Replacement = Exchange of ions between two compounds</p> Signup and view all the answers

    The limiting reactant in a chemical reaction is always the reactant with the smallest amount in moles.

    <p>False</p> Signup and view all the answers

    What do you calculate first when determining the mass of reactants needed to produce a desired mass of products?

    <p>Theoretical yield using molar ratios</p> Signup and view all the answers

    What is the balanced chemical equation for the reaction of nitrogen and hydrogen to form ammonia?

    <p>N2 + 3H2 → 2NH3</p> Signup and view all the answers

    The limiting reactant is the reactant that is left over after a reaction has taken place.

    <p>False</p> Signup and view all the answers

    What is percent yield?

    <p>The ratio of actual yield to theoretical yield, expressed as a percentage.</p> Signup and view all the answers

    In a chemical reaction, the full amount of product produced is called __________ yield.

    <p>theoretical</p> Signup and view all the answers

    If a student obtained 6.5 g of NH3 from the reaction of 6.0 g of N2 and 18.0 g of H2, what is the formula to calculate the percent yield?

    <p>Percent yield = (Actual yield / Theoretical yield) * 100</p> Signup and view all the answers

    In the reaction of nitrogen and hydrogen, how do you determine the limiting reactant using masses?

    <p>By calculating the moles of each reactant and determining which one produces the least amount of product.</p> Signup and view all the answers

    Match the following terms with their definitions:

    <p>Limiting reactant = The reactant that is entirely consumed in a reaction Excess reactant = The reactant that remains after the reaction is complete Theoretical yield = The amount of product expected from a reaction under ideal conditions Actual yield = The amount of product actually obtained from a reaction</p> Signup and view all the answers

    The percent yield can be calculated using the formula: Percent yield = __________ yield / Theoretical yield * 100.

    <p>Actual</p> Signup and view all the answers

    Study Notes

    Unit 7: Stoichiometry

    • Learning Objectives: Apply first-semester learning to convert word equations into balanced chemical equations. Include identifying ionic and covalent compounds, diatomic elements, polyatomic ions, and naming/balancing chemical equations.

    • Percent Composition: Calculate the percent composition of each element in a molecule.

    • Empirical Formula: Calculate the empirical formula of a substance using mass quantities or percent composition.

    • Molecular Formula: Calculate the molecular formula using mass quantities, percent composition, and molar mass.

    • Mole Ratios: Given balanced chemical equations, determine the theoretical yield and find the limiting reagent.

    • Limiting Reactant: Identify the reactant fully consumed in a reaction.

    • Excess Reactant: Determine the amount of reactant left over when a reaction has reached completion.

    • Percent Yield:

      • Calculate experimentally determined actual yield vs theoretical yield
      • Measure percentage using the ratio of actual yield to theoretical yield and 100 as the denominator.

    Worksheet Contents

    • WS#1: Percent Composition
    • WS#2: Percentage Composition and Empirical Formula
    • WS#3: Reaction Stoichiometry
    • WS#4: Limiting and Excess Reactant Stoichiometry
    • WS#5: Limiting Reactant and Percent Yield Practice
    • WS#6: Word Equations and Stoichiometry
    • U7 Lecture Notes: (Pages 12-18- not graded)

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    ChemH Unit 7 Packet 2025 PDF

    Description

    Test your knowledge on the calculation of percent composition and empirical formulas in chemistry. This quiz includes questions on compounds such as CuBr2 and glucose, and challenges you to match compounds with their corresponding mass percent of nitrogen. Dive deep into the essential concepts of chemistry related to molecular and empirical formulas.

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