Metal Forming Processes & Material Properties
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Questions and Answers

Describe the relationship between grain recrystallization and the rolling process. How does rolling affect the grain structure of a metal?

Rolling deforms the metal, and grain recrystallization occurs during hot rolling, leading to new, smaller, and more uniform grains. This improves the metal's strength and ductility.

Explain how roll flatness and deflection can affect the quality of rolled products. What strategies can be employed to minimize these effects?

Roll flatness and deflection lead to uneven deformation and variations in thickness. Strategies include using backup rolls, contouring rolls, and controlling roll temperature.

Compare and contrast direct and indirect extrusion processes, highlighting the key differences in their mechanisms and applications.

In direct extrusion, the billet moves in the same direction as the ram, while in indirect extrusion, the billet moves in the opposite direction. Direct extrusion is simpler but has higher friction; indirect extrusion has lower friction but requires more complex tooling.

Describe the purpose of multi-stage drawing in wire and rod production. Why is it often necessary to draw materials through a series of dies?

<p>Multi-stage drawing gradually reduces the cross-sectional area of the material, preventing excessive strain and cracking. It allows for greater overall deformation and better control over final dimensions and properties.</p> Signup and view all the answers

Explain the relationship between deformation processes (like rolling, extrusion, and drawing) and a material's final mechanical properties. How can these processes be tailored to achieve specific material characteristics?

<p>Deformation processes alter the grain structure and introduce dislocations, which affect strength, ductility, and hardness. By controlling temperature, strain rate, and amount of deformation, specific mechanical properties can be achieved.</p> Signup and view all the answers

An engineer wants to optimize a component for maximum strength while minimizing material usage. How would they typically approach this problem?

<p>They would use an optimization algorithm to find the best balance between strength and material usage. They would define objective functions and constraints based on desired performance and resource limitations.</p> Signup and view all the answers

A sound engineer is using engineering UTS. What does a lower engineering UTS indicate about the sound produced by a material?

<p>A lower engineering UTS indicates the material is less resistant to deformation and is thus a weaker source of sound. This means a sound material with lower engineering UTS will produce sounds with comparatively less intensity.</p> Signup and view all the answers

Given the equation $8 = 100,000 \cdot G$, what does 'G' likely represent in an engineering context, and what might the equation be modeling?

<p>'G' likely represents a gain factor, efficiency, or some ratio. The equation is probably modeling how an initial value ($8) is scaled up to a final value ($100,000) through multiplication by the factor 'G'.</p> Signup and view all the answers

In the phrase duts = 100,000 * 10^-opsi, if opsi represents the number of optimization steps performed in an algorithm, what does this equation imply about the relationship between duts and the number of optimization steps?

<p>This equation implies 'duts' decreases exponentially as the number of optimization steps ('opsi') increases in the algorithm.</p> Signup and view all the answers

An engineer wants to find neint.Out Ad So d. What does 'find' typically refer to in this case?

<p>The term 'find' in this case refers to the method used to discover a parameter which ensures <code>neint.Out Ad So d</code> is at its optimum level. It is most likely referring to an algorithm.</p> Signup and view all the answers

Briefly explain how the elastic modulus ($E$) relates to a material's stiffness, according to Hooke's Law.

<p>The elastic modulus ($E$) is the ratio of stress to strain in the elastic region. A higher $E$ indicates a stiffer material, meaning it requires more stress to achieve the same amount of strain.</p> Signup and view all the answers

Describe the difference between uniform plastic deformation and non-uniform deformation in the context of a tensile test. Where on the curve above would you expect to see uniform deformation?

<p>Uniform plastic deformation occurs when the strain is evenly distributed along the gauge length of the sample, while non-uniform deformation involves localized necking. Uniform deformation typically occurs between the yield point and the ultimate tensile strength (UTS).</p> Signup and view all the answers

Define the yield point on a stress-strain curve and explain its significance in material behavior.

<p>The yield point is the point on the stress-strain curve where the material begins to deform plastically. Beyond this point, the material will experience permanent deformation even after the load is removed.</p> Signup and view all the answers

What does UTS stand for and what is its significance? Where can UTS (ultimate tensile strenth) be found on the curve?

<p>UTS stands for Ultimate Tensile Strength. It represents the maximum stress a material can withstand before it starts to neck down and ultimately fail, and is the highest point on the stress-strain curve.</p> Signup and view all the answers

Explain the concept of true stress and how it differs from engineering stress. Why is true stress more representative of a material's behavior at large deformations?

<p>True stress is the applied load divided by the instantaneous cross-sectional area of the specimen, while engineering stress is calculated using the original cross-sectional area. True stress accounts for the reduction in area during deformation, providing a more accurate measure of the stress experienced by the material at large strains.</p> Signup and view all the answers

What is true strain? How is calculating true strain different than calculating engineering strain?

<p>True strain is the integral of the incremental changes in length divided by the instantaneous length during deformation. Unlike engineering strain, true strain accounts for the continuous change in length of the material, especially during large deformations.</p> Signup and view all the answers

In the context of materials, what is meant by the term 'material properties'? Provide a list of three material properties.

<p>Material properties refer to the inherent physical and mechanical characteristics of a material that determine its behavior under various conditions. Three examples of material properties are tensile strength, elastic modulus, and hardness.</p> Signup and view all the answers

If you are given a Stress/Strain curve for a material, and you are asked for the Young's Modulus, describe the process you would use to find it.

<p>The Young's Modulus would be the slope of the linear portion of the Stress/Strain curve. Pick two points in the linear portion on the curve stress/strain graph (stress₁, strain₁) / (stress₂, strain₂). With those, calculate the slope using the formula: $(stress₂ - stress₁) / (strain₂ - strain₁)$</p> Signup and view all the answers

How does increasing carbon content typically affect the ductility and strength of steel?

<p>Increasing carbon content in steel generally increases strength but reduces ductility.</p> Signup and view all the answers

For applications requiring high strength but limited ductility, such as dies and tooling, which type of steel would be most suitable?

<p>High carbon steel.</p> Signup and view all the answers

Explain why low carbon steel is preferred for applications like sheet metal and structural beams.

<p>Low carbon steel is preferred because it provides a balance of good strength and good ductility, which is essential for forming and structural integrity.</p> Signup and view all the answers

Describe how the properties of medium carbon steel make it suitable for parts requiring machining.

<p>Medium carbon steel offers a compromise between hardness and ductility, making it machinable while still offering reasonable strength.</p> Signup and view all the answers

What is the primary difference in composition between plain carbon steel and alloy steel?

<p>Plain carbon steel is mainly composed of iron and carbon, while alloy steel includes additional alloying elements to modify its properties.</p> Signup and view all the answers

Explain why heat treatment is often essential for high carbon steel tools.

<p>Heat treatment, such as hardening and tempering, is crucial to achieve the required hardness and toughness for the tool to cut or form materials effectively without premature failure.</p> Signup and view all the answers

How does the percentage of carbon in steel relate to its weldability?

<p>Higher carbon content generally decreases weldability due to increased hardness and the potential for cracking during the welding process.</p> Signup and view all the answers

In terms of applications, distinguish between where you might use low carbon steel versus high carbon steel. Provide one example for each.

<p>Low carbon steel is used for applications needing ductility, like automotive body panels, while high carbon steel is used where hardness and wear resistance are needed, like cutting tools.</p> Signup and view all the answers

Explain how the 'strain hardening exponent' affects a material's ability to deform plastically before failure.

<p>A higher strain hardening exponent allows the material to undergo more plastic deformation before necking and failure, as it requires more stress to continue deforming.</p> Signup and view all the answers

What does the text mean by 'limiting t: true + ε necting is E = 1' and how does this relate to the ultimate tensile strength?

<p>This implies that at the onset of necking (localized deformation), the true strain (ε) equals 1, and the true stress equals the ultimate tensile strength (UTS).</p> Signup and view all the answers

Given a material with a true UTS (σ_true) of 100,000 psi and the relationship σ_true = σ_eng * exp(ε), calculate the engineering UTS (σ_eng) when the true strain (ε) at UTS is 0.2.

<p>Engineering UTS (σ_eng) = σ_true / exp(ε) = 100,000 / exp(0.2) ≈ 81,873 psi</p> Signup and view all the answers

The document refers to 'A = 0mux' and 'A = -10, 718'. Explain what 'A' likely represents in this context and why the two values are different.

<p>'A' most likely represents the cross-sectional area of a tensile specimen. The difference may be do to calculation mistakes or different measurement methods.</p> Signup and view all the answers

Describe the relationship between true stress and engineering stress, highlighting the conditions under which they are most different.

<p>True stress is the load divided by the instantaneous area, while engineering stress uses the original area. They differ most significantly at higher strains where the cross-sectional area has noticeably decreased.</p> Signup and view all the answers

What is the practical significance of determining the 'limit.struin' (limiting strain) of a material in engineering applications?

<p>Knowing the limiting strain helps engineers design structures and components that can withstand deformation without failure, ensuring structural integrity and preventing catastrophic events.</p> Signup and view all the answers

Explain in one or two sentences how the value of 'E' relates to 'necting' or necking of a material under tension.

<p>The value of 'E' representing strain hardening exponent. if 'E' is closer to 1 then material will experience necking more readily, because strain hardening is not as effective.</p> Signup and view all the answers

What are some potential sources of error that could explain the discrepancy between the calculated answer '42450' and the value '10,718' obtained for 'A'?

<p>The discrepancy might stem from unit conversions, incorrect formulas, or the use of different area definitions (initial vs. instantaneous).</p> Signup and view all the answers

What is the primary difference in shaping methods between wrought alloys and cast alloys, and how does this difference typically affect their general properties?

<p>Wrought alloys are shaped in the solid state, while cast alloys are shaped in liquid form (molten). Wrought alloys are generally tougher than cast alloys due to this shaping method.</p> Signup and view all the answers

What is the key characteristic that distinguishes tool steels from other types of steels, as indicated by their designation?

<p>Tool steels contain a large percentage of alloying elements other than carbon and are designated by a letter (W, A, M, S, O, H, T) and a number.</p> Signup and view all the answers

Describe the main application of high-speed tool steels (like T-type), and what properties make them suitable for that application?

<p>High-speed tool steels are used when high-speed cutting and forming is needed. They are suitable because they gain high strength at high temperatures and offer wear resistance.</p> Signup and view all the answers

What does the 'H' designation signify in tool steels, and what are the key properties associated with these steels?

<p>The <code>H</code> designation in tool steels stands for hot work steels. Key properties include the ability to retain hardness at high temperatures and wear resistance.</p> Signup and view all the answers

Explain what 'wrought alloys' are and give an example the text provides.

<p>Wrought alloys are alloys that are shaped and fabricated in the solid state. The text does not provide a specific example.</p> Signup and view all the answers

How does the high heat resistance of high speed tool steel benefit its function?

<p>High heat resistance allows it to maintain its shape while resisting wear.</p> Signup and view all the answers

Compared to cast alloys, are wrought alloys generally tougher or more brittle?

<p>Wrought alloys are generally tougher.</p> Signup and view all the answers

If a tool steel is designated as 'M12,' what does the 'M' likely indicate, and what general category of tool steels does this fall under?

<p>The <code>M</code> indicates molybdenum as a primary alloying element. This falls under the Molybdenum High-Speed Steels category.</p> Signup and view all the answers

Flashcards

UTS (engineering)

Ultimate Tensile Strength represents the maximum stress a material can withstand before breaking.

Find Engineering UTS

Finding engineering UTS involves initial material testing to determine material strength.

Sound and Intensity

If sound is lower, than the intensity is also lower.

True Strain Limit

The limit of strain that a material can withstand before failure, considering true strain and necking.

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Ultimate Tensile Strength (UTS)

A material property representing the maximum engineering stress a material can withstand before failure.

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Engineering UTS

Ultimate Tensile Strength calculated using engineering stress, which does not account for the reduction in cross-sectional area during tensile testing.

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UTS = Guts

The Engineering UTS is equal to 'Guts'.

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G Value

G = 100,000 PSI

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A Value

A is equal to a negative value, as shown in the example A = -10.

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Yield Point

The point on a stress-strain curve that marks the end of elastic behavior and the beginning of plastic deformation.

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Uniform Plastic Deformation Regime

A regime where deformation is uniform and plastic.

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Hooke's Law

Relates stress and strain in the elastic region. Stress = (Elastic Modulus) * Strain.

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Elastic Modulus (Young's Modulus)

A material property that measures stiffness; the ratio of stress to strain in the elastic region.

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Stress-Strain Relationship (Plastic Deformation)

Describes the stress-strain relationship in the plastic deformation region.

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True Stress

Stress calculated using the instantaneous area of the sample during deformation.

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True Strain

Strain calculated using the instantaneous length of the sample during deformation.

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Neuron Steel Applications

Offers good strength and ductility, suitable for applications that require structural integrity.

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Common Applications

These steels are commonly used for structured applications; includes sheet metal and I-beams.

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Medium Strength Steel

Used for machining processes, balancing strength with the ability to be shaped.

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Medium Steel Parts

Often used for parts like gears and shafts, requiring a balance of strength and workability.

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High Wear Resistance

Offers high wear resistance, used for tools must be 'B: ter.ven'.

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Limited Ductility Applications

Offers limited ductility and is brittle, used for 'limited socre tolerance'.

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Steel's Properties

Plain carbon steel's properties depend on the amount of carbon element. Low carbon vs. nigh carbon

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High Carbon (%)

4.4 is %C amount of carbon in the steel.

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Rolling (metalworking)

A metal forming process where metal stock is passed through one or more pairs of rolls to reduce the thickness, to make the thickness uniform.

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Billets

Semi-finished casting products that have a square or rectangular cross-section with a size between 40 mm and 300 mm.

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Recrystallization Temperature

The temperature at which the deformed material is recrystallized.

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Extrusion (engineering)

A manufacturing process where a material is pushed through a die of the desired cross-section.

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Wire Drawing

A tensile operation used to reduce the cross-section of a wire or rod by pulling it through a die.

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Tool Steels

Tool steels contain a large percentage of alloying elements other than carbon, designated by a letter (W, A, M, S, O) and a number.

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High-Speed Tool Steels

High-speed tool steels maintain high strength at high temperatures and exhibit wear resistance.

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T-Type Tool Steels

These are tungsten-based high-speed tool steels.

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Wrought Alloys

Alloys that are shaped and fabricated in a solid state.

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Wrought Alloy Properties

Wrought alloys generally possess superior toughness compared to cast alloys.

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Cast Alloys

Alloys shaped in a liquid (molten) form.

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Alloying Elements

Adding elements other than carbon to change the properties of the steel.

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Non- Prefix

Prefix meaning "not".

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Study Notes

  • Permanent deformation requires exceeding the material's yield strength.

Design Considerations

  • Feasibility of designing and manufacturing a part depends on:
  • Aesthetics
  • Cost

Manufacturing Types

  • Additive manufacturing builds parts layer by layer.
  • Metal deformation shapes metal through processes like:
  • Forging
  • Burr removal
  • Sheet metal forming

Casting

  • Involves pouring liquid metal into a mold cavity.
  • Used for creating:
  • Pumps
  • Manifolds
  • Street furniture

Subtractive

  • Also known as cutting
  • Removes material through:
  • Drilling
  • Milling
  • Cylindrical turning

Powder Metallurgy

  • Powdered metal is placed in a die.
  • Force is applied, often hydrostatically.
  • This ensures diffusion and bonding between particles.

Surface Modification

  • Includes Painting
  • Shot peening involves bombarding a surface with steel balls.
  • This creates compressive residual stress, refining the microstructure.

Property Modifications

  • Quenching leads to hardening.
  • Some materials have crystalline structures such as:
  • Body-centered cubic (BCC)
  • Face-centered cubic (FCC)
  • FCC structures exhibit better stability and can dissolve iron.
  • Thermal and mechanical processing alters material properties.

Processing Operations

  • Processing operations are divided into:
  • Shaping
  • Surface processing
  • Joining

Shaping Operations

  • Shaping operations can be achieved through:
  • Deformation
  • Casting
  • Subtractive methods
  • Additive manufacturing
  • Powder metallurgy

Surface Processing

  • Surface processing techniques include:
  • Coating
  • Painting
  • Anodizing
  • Electroplating
  • Carburization: Hardens steel by introducing carbon into the surface in a carbon-rich environment at high temperatures.

Assembly

  • Joining operations include:
  • Welding
  • Brazing
  • Soldering
  • Adhesive bonding
  • Fastening methods can be:
  • Permanent, like riveting
  • Non-permanent, like threaded fasteners
  • Annealing restores the material to its original state.

Deformation Processes

  • Key points on a stress-strain curve:
  • Yield point (1)
  • Elastic regime (0 to 1): Deformation is reversible upon load removal.
  • Plastic regime (1 to 3): Permanent deformation occurs.
  • Necking point (2): Maximum load before fracture.
  • Fracture (3)
  • Stress is calculated as load (P) divided by the initial cross-sectional area (Ao:)
  • Strain is calculated as the change in length (ΔL) divided by the initial length (L).
  • Gauge length is the section being measured and not the entire sample.
  • Elastic recovery happens when a material is plastically deformed and the load is removed.
  • The material partially reverts.
  • Key strain measurements:
  • Total strain
  • Elastic strain (recovered after unloading)
  • Plastic strain (permanent strain after unloading)

True Stress and Strain

  • Engineering stress (σ) is load (P) divided by initial area (Ao).
  • Engineering strain (e) is change in length (ΔL) divided by initial length (L).
  • True stress and strain are more accurate for measuring deformation processes.
  • True stress is calculated as force divided by the area at a given moment: σ = P/A.
  • True strain is calculated as ε=ln(L/Lo), where L is the length at a given moment.
  • The relationship between stress and strain is σ= Kε^n
  • K is the strength coefficient
  • n is the strain hardening exponent,
  • Strain hardening is the strengthening of a material through plastic deformation.

Manufacturing Considerations

  • Achieving a perfect 90° angle in manufacturing is challenging.
  • Annealing softens material by heating it to a high temperature and cooling it slowly.
  • This restores the original grain structure after deformation.

Annealing

  • Leads to a lowering of strength and an increase in ductility.
  • Recovery does not revert the grain structure, only the microstructure.
  • Metals are typically multi-crystalline.
  • In the annealed state, the crystals are equiaxed with no residual stress.

Steel Hardening

  • Involves heating steel to induce a phase transformation from BCC to FCC.
  • Followed by quenching in a cool medium.
  • FCC (face-centered cubic) allows for more carbon to dissolve.
  • BCC (body-centered cubic) is stronger but less ductile.
  • Additions to steel are explained via phase diagrams, like the Fe-C diagram.

Tensile Testing

  • Tensile testing involves the following:
  • Elastic Regime
  • Yield point (1)
  • Elastic regime (0 to 1) described by Hooke's Law: σ = Eε.
  • E is the modulus of elasticity (Young's modulus).
  • Uniform plastic deformation regime (1-2)
  • Necking point and maximum load (2)
  • Ultimate tensile strength or UTS (2')
  • Engineering strain (e) is calculated as ΔL/Lo.
  • Lo represents the gauge length of the sample.

Plastic Deformation

  • In plastic deformation, the stress-strain relationship is σ = Kε^n.
  • K represents material properties.
  • True stress is calculated as P/A, as opposed to using the original area.
  • True strain is calculated as ln(Lo/L).
  • Unloading the Sample: When the material is unloaded, it follows a straight line with a slope of E, parallel to the plastic line (from 0↔1).
  • Work (strain) hardening can occur (1↔2).
  • Increases the yield strength due to plastic deformation.
  • This occurs at temperatures below the recrystallization temperature, i.e., cold working.
  • A material can exhibit work hardening or not exhibit strain-hardening.

Hot vs Cold Working

  • Cold working involves deforming material at a temperature less than its recrystallization temperature
  • Atom movement is suppressed
  • Hot working is performed above this temperature.
  • Benefits of cold working:
  • Increased material strength.
  • Better control over dimensional and geometrical tolerances.
  • Better surface finish.
  • Controlled microstructure.
  • A primary drawback of hot working is less precise dimensional control
  • Disadvantages of cold working:
  • Less ductility.
  • Requires larger forces and equipment.

Anisotropy

  • Plastic anisotropy is induced by plastic deformation in otherwise isotropic materials.
  • Isotropy is a condition where the mechanincal proeprties are the same in all directions
  • Anisotropy means the mechianl properties will differ.
  • Cold working causes grain flattening.
  • The material becomes non-isotropic or anisotropic due to the deformation.

Calculations

  • n is the strain hardening exponent.
  • True strain at necking (εn:) is also the limit before necking and failure.
  • Material Behavior: If it is defined by the equation σ=100,000*ε^0.5:
  • The limit to which the material can be subjected =TRUE strain @ necking = εn=.5
  • Formulas
  • Engineering UTS can be figured this way =Pmax/Ao, where Pmax is area at maximum.

Additional Information from Missed Notes

  • The true strain at necking is equivalent to the strain hardening exponent.
  • Determine True UTS: True UTS = σUTS = 100,000(0.5)^0.5 = 70,710 psi = Pmax/A Find Engineering UTS: Etrue=ln Ao/A.
  • In plastic deformation, volume is constant.
  • Constant volume condition: ALo=AL therefore Lo/L=A/Ao

Additional Calculations

  • εneck=εtrue=n
  • σUTS =100,000(ε)^.5 = 70,710 PSI.
  • Engineering Stress ~ Suts=Pmax/Ao= 70,710 psi.

Material and Waste

  • Assuming no material waste: AoLo ≈ AL
  • Volume is constant conditions: AoLo= AL
  • But we know that the ε @ ult. Point is εn : ε=ln Ao/ A

Extrusion Calculations

  • ε ≈ ln A0/A =ln di0^2/df^2 ≈σ 752.5

Alloys

  • In ferrous- alloys are classified: Alloy steel & cust iron (C>42.4 percent)
  • Plain carbon steel, steel contains only carbon as its alloying element.

PLAIN CARBON STEEL SUB CATEGORIES

  • low carbon steel are [<=. 20% as weight]
  • Medium Carbon steel [.20%-3-63%]
  • His carbon Steel [.630-4.4%]
  • Ferrous alloys share a significant benefit of high tensile strength.
  • Alloy steel is steel that only carbon as its alloying clement
  • It must withstand higher amounts of tensile strength and extreme temperatures

Tool Steels

  • Tool steels feature alloying elements.
  • Each grade has a tool steel.
  • Examples MI, H2

Other Materials

  • Non-creeping, tool steel that maintains high.
  • Tungsten-based, high-speed steel- Molybdenum: high-speed steel
  • High shock resistance tool steel
  • Water hardening tool steel.

Additional Terms to note

  • Machinability: refers to being made readily or to wear or wear resistance
  • Wrought alloys are shaped or fabricated in the solid state.
  • There general properties are higher when they are tough and reliable.
  • Cast alloys: shaped casting, cast mold in form

Homework Review

  • In plastic deformation, volume is constant.
  • In elastic deformation, volume may not be constant.

Bulk Deformation Proces

  • Bulk Deformation process, and best process from the material improvement point.
  • Forsing: metal by compresive forces
  • Reduse & set
  • Mechanical Perfomrance typically

1-9 Study Guide points

  • Open-Die Forging: Tools and equipment.
  • Impressions Die forging gives longer improved set share one steel

Material

  • Most of the time it comes from Det.
  • It can lead to improve peeling and oxidation can come from the material
  • Less control over dimension and beam

Terms

  • Eliminate porities/ divert gain flows and the material comes wrought mill to perform better.

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