Genetics Quiz: Hardy-Weinberg Principle
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Questions and Answers

What defines an allele in genetic terms?

  • The position of a gene on a chromosome
  • A variation of a gene (correct)
  • A specific type of chromosome
  • The overall genetic makeup of an organism
  • Which of the following is NOT an assumption of the Hardy-Weinberg model?

  • No natural selection happens
  • The population is large
  • There are frequent mutations (correct)
  • Random mating occurs
  • What does the equation $p + q = 1$ represent in the Hardy-Weinberg principle?

  • The ratio of dominant to recessive genotypes
  • The total number of genes in a population
  • The frequency of dominant and recessive alleles (correct)
  • The number of homozygous individuals
  • In a population, if the allele frequencies are $p = 0.46$ and $q = 0.54$, what is the frequency of heterozygous individuals?

    <p>0.4968</p> Signup and view all the answers

    If a population has 40 individuals with genotype HH, 45 with Hh, and 50 with hh, what is the frequency of the HH genotype?

    <p>0.30</p> Signup and view all the answers

    Using the Hardy-Weinberg principle, if 16% of the population is homozygous recessive (ss), what is the frequency of the homozygous dominant genotype (SS)?

    <p>0.64</p> Signup and view all the answers

    What is the chi-square value calculated for the observed genotype counts compared to expected values?

    <p>14.57</p> Signup and view all the answers

    If 9% of a population is homozygous recessive for a trait, what percentage will be heterozygous and more resistant to a disease?

    <p>42%</p> Signup and view all the answers

    If the total number of alleles in a population is calculated as 270, how is the frequency of allele H determined?

    <p>Calculating $2 imes$ number of HH individuals divided by total alleles</p> Signup and view all the answers

    Study Notes

    Definitions

    • Allele: Variations of genes that determine specific traits.
    • Locus: The specific location of a gene on a chromosome.

    Hardy-Weinberg Principle

    • Five Assumptions:
      • Random mating occurs within the population.
      • There are no mutations affecting alleles.
      • No migration into or out of the population changes allele frequencies.
      • Natural selection does not favor any particular genotype.
      • The population is sufficiently large to avoid genetic drift.

    Hardy-Weinberg Equilibrium

    • Equations:

      • Allele frequency: ( p + q = 1 )
        • ( p ): Frequency of the dominant allele
        • ( q ): Frequency of the recessive allele
      • Genotype frequency: ( p^2 + 2pq + q^2 = 1 )
        • ( p^2 ): Frequency of homozygous dominant genotype
        • ( 2pq ): Frequency of heterozygous genotype
        • ( q^2 ): Frequency of homozygous recessive genotype
    • Allele Frequency Calculation:

      • Total number of alleles = Total number of chromosomes x 2
      • Allelic frequencies calculated by dividing the number of dominant or recessive alleles by the total number of alleles.

    Genotype Frequency Calculation

    • Observed Genotypes:

      • HH: 40
      • Hh: 45
      • hh: 50
    • Total Genotypes: 135

    • Genotype Frequencies:

      • HH: ( 40/135 = 0.30 )
      • Hh: ( 45/135 = 0.33 )
      • hh: ( 50/135 = 0.37 )
    • Allele Frequencies:

      • Total alleles = ( 135 \times 2 = 270 )
      • ( f(H) = (2 \times 40 + 45)/270 = 0.46 )
      • ( f(h) = 0.54 ) (derived from ( p + q = 1 ))

    Expected Genotype Frequencies under H-W Equilibrium

    • Calculated from allele frequencies:
      • HH: ( 0.2116 \times 135 = 28.57 )
      • Hh: ( 0.4968 \times 135 = 67.07 )
      • hh: ( 0.2916 \times 135 = 39.37 )

    Chi-Square Test for H-W Equilibrium

    • Formula:
      ( \chi^2 = \frac{(O - E)^2}{E} )
      • O: Observed number of genotypes
      • E: Expected number of genotypes
    • Calculations:
      • For HH: ( \frac{(40 - 28.57)^2}{28.57} = 4.5 )
      • For Hh: ( \frac{(45 - 67.07)^2}{67.07} = 7.2 )
      • For hh: ( \frac{(50 - 39.37)^2}{39.37} = 2.8 )
    • ( \chi^2 = 4.5 + 7.2 + 2.8 = 14.57 )

    Sickle-Cell Anemia and Malaria Resistance

    • Scenario: 9% (0.09) of a population has severe sickle-cell anemia (genotype ss).

    • Calculating q:

      • ( q^2 = 0.09 \rightarrow q = 0.3 )
    • Calculating p:

      • ( p + q = 1 \rightarrow p = 0.7 )
    • Heterozygous Frequency:

      • ( 2pq = 2 \times 0.7 \times 0.3 = 0.42 \rightarrow 42% )
    • For a 16% (0.16) Population with ss:

      • ( q^2 = 0.16 \rightarrow q = 0.4 )
      • ( p + q = 1 \rightarrow p = 0.6 )

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    Description

    Test your understanding of the Hardy-Weinberg Principle and its assumptions. This quiz will cover key concepts like allele frequencies and genotype calculations. Perfect for students studying genetics or related fields.

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