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Questions and Answers
The equilibrium constant Keq for the isomerisation of glucose-6-phosphate to fructose-6-phosphate at 25 °C is 0.528.
False
If the initial concentration of G6P is 0.1 M, the concentration of F6P at equilibrium will be greater than 0.1 M.
False
At equilibrium, the concentration of F6P and G6P will always be equal.
False
An equilibrium constant (Keq) value less than 1 indicates that at equilibrium, there are more reactant molecules than product molecules.
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The isomerisation of glucose-6-phosphate to fructose-6-phosphate can occur without any G6P being converted to F6P at equilibrium.
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Study Notes
Equilibrium Constant
- The equilibrium constant (Keq) is a constant that describes the ratio of products to reactants at equilibrium for a given reaction.
- Keq for the isomerisation of glucose-6-phosphate (G6P) to fructose-6-phosphate (F6P) at 25°C is 0.428.
- The equilibrium constant (Keq) is defined as the ratio of the product of the concentrations of the products raised to their stoichiometric coefficients to the product of the concentrations of the reactants raised to their stoichiometric coefficients.
Calculating [F6P] at Equilibrium
- The initial concentration of [G6P] is 0.1 M.
- The concentration of [F6P] can only be formed from [G6P] molecules.
- The equilibrium constant can be calculated using the following equation: Keq = [F6P]/[G6P].
- Solving for [F6P] we get: [F6P] = Keq * [G6P] = 0.428 * 0.1 M = 0.0428 M.
- The concentration of [F6P] at equilibrium at 25°C is 0.0428 M.
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Description
This quiz covers the concept of the equilibrium constant (Keq) with a focus on the isomerisation of glucose-6-phosphate (G6P) to fructose-6-phosphate (F6P). Participants will learn how to calculate the equilibrium concentration of F6P based on the initial concentration of G6P and the value of Keq. Test your understanding of these critical concepts in chemical equilibrium.
