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Questions and Answers
How is the concentration of hydroxide ions ($OH^-$) determined from the equation $OH^- : N_1 V_1 = N_2 V_2$?
How is the concentration of hydroxide ions ($OH^-$) determined from the equation $OH^- : N_1 V_1 = N_2 V_2$?
The concentration of $OH^-$ is calculated using the equation by substituting known values for $N_2$ and $V_2$, allowing us to solve for $N_1$.
What value is approximated for $OH^-$ after calculating $ rac{1}{20} imes(2.7)$?
What value is approximated for $OH^-$ after calculating $ rac{1}{20} imes(2.7)$?
The value approximated for $OH^-$ is 0.01.
Using the formula given, how do you calculate the strength of carbonate ions ($CO_3^{2-}$) in parts per million (PPM)?
Using the formula given, how do you calculate the strength of carbonate ions ($CO_3^{2-}$) in parts per million (PPM)?
The strength of $CO_3^{2-}$ is calculated as $0.05 imes 30 imes 1000 = 1500$ PPM.
What role do the variables $N_1$, $V_1$, $N_2$, and $V_2$ play in the provided calculations?
What role do the variables $N_1$, $V_1$, $N_2$, and $V_2$ play in the provided calculations?
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Why might one use the approximation in calculations such as those for $OH^-$ and $CO_3^{2-}$?
Why might one use the approximation in calculations such as those for $OH^-$ and $CO_3^{2-}$?
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Study Notes
Calculations for OH⁻ and CO₃²⁻ Strength
-
OH⁻ Strength Calculation:
- Formula used: N₁V₁ = N₂V₂ where N is the normality and V is the volume
- N₁ = 1/20 (Normality of OH⁻)
- V₁ = 10 mL
- Calculated strength: 0.01
- Expressed as parts per million (PPM)
-
CO₃²⁻ Strength Calculation:
- Formula used: N₁V₁ = N₂V₂
- N₁= 1/20 (Normality of CO₃²⁻)
- V₁ = 10 mL
- V₂ = 2 mL
- Calculated strength : 0.05
- Expressed as parts per million (PPM)
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Description
This quiz will test your understanding of the calculations related to the strength of hydroxide (OH⁻) and carbonate (CO₃²⁻) ions. You will encounter normality and volume relationships using the formula N₁V₁ = N₂V₂. Prepare to apply your knowledge of chemical concentrations and unit conversions in a series of questions.
