Chemical Reaction Yields
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Questions and Answers

What is theoretical yield in a chemical reaction?

  • The percentage of reactants converted into products
  • The mass of reactants before the reaction
  • The mass of product actually obtained from a reaction
  • The maximum possible mass of product that could be produced (correct)
  • Percentage yield is calculated by dividing actual yield by theoretical yield and multiplying by 100.

    True

    What is the actual yield if the process was 82% efficient and the theoretical yield is 100 g?

    82 g

    The formula for calculating percentage yield is __________.

    <p>actual yield/theoretical yield × 100%</p> Signup and view all the answers

    Match the following terms with their definitions:

    <p>Theoretical Yield = A measure of how efficiently reactants are converted to products Actual Yield = The mass of product actually obtained from a reaction Percentage Yield = The maximum possible mass of product in a reaction</p> Signup and view all the answers

    Study Notes

    Chemical Reaction Yields

    • Chemical reactions don't always produce the exact amount of product predicted by balanced equations.
    • Theoretical Yield: The maximum possible mass of product that could be produced.
    • Actual Yield: The actual mass of product obtained from a reaction.
    • Percentage Yield: A measure of how efficiently a reactant is converted to a product. Calculated as (actual yield / theoretical yield) * 100%.

    Example Calculation

    • Reaction: HBrO3 + 5HBr → 3Br2 + 3H2O

    • Given: 10.0 g of HBrO3 reacted with excess HBr; 26.3 g of Br2 produced.

    • i) Moles of Reactant:

      • Calculate molar mass of HBrO3 (128.91 g/mol)
      • Calculate moles of HBrO3 used (10.0 g / 128.91 g/mol = 0.0776 mol)
    • ii) Theoretical Yield:

      • Calculate moles of Br2 produced from moles of HBrO3 (0.0776 mol HBrO3 * (3 mol Br2 / 1 mol HBrO3) = 0.233 mol)
      • Calculate molar mass of Br2 (159.81 g/mol)
      • Calculate theoretical yield (0.233 mol * 159.81 g/mol = 37.2 g)
    • iii) Percentage Yield:

      • Calculate percentage yield (26.3 g / 37.2 g) * 100% = 70.7%
    • Additional Example: If the reaction was 82% efficient, the actual yield would be 30.5g.

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    Description

    Evaluate your understanding of chemical reaction yields, including theoretical and actual yields, as well as percentage yield. This quiz includes calculations and examples relevant to stoichiometry in chemical reactions.

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