Orders of Reaction and Mechanisms PDF

ORDERS OF REACTION AND MECHANISMS At the end of this topic, students should be able to:  define Mechanism of reaction.  state the relationship between orders of reaction and mechanisms What is a reaction mechanism? In any chemical change, some bonds are broken and ne...

ORDERS OF REACTION AND MECHANISMS At the end of this topic, students should be able to:  define Mechanism of reaction.  state the relationship between orders of reaction and mechanisms What is a reaction mechanism? In any chemical change, some bonds are broken and new ones are made. Quite often, these changes are too complicated to happen in one simple stage. Instead, the reaction may involve a series of small changes one after the other. A reaction mechanism describes the one or more steps involved in the reaction in a way which makes it clear exactly how the various bonds are broken and made. The following example comes from organic chemistry. This is a reaction between 2-bromo-2-methylpropane and the hydroxide ions from sodium hydroxide solution: : The overall reaction replaces the bromine atom in the organic compound by an OH group. The first thing that happens is that the carbon-bromine bond in a small proportion of the organic compound breaks to give ions: Carbon-bromine bonds are reasonably strong, so this is a slow change. If the ions hit each other again, the covalent bond will reform. The curly arrow in the equation shows the movement of a pair of electrons. If there is a high concentration of hydroxide ions present, the positive ion stands a high chance of hitting one of those. This step of the overall reaction will be very fast. A new covalent bond is made between the carbon and the oxygen, using one of the lone pairs on the oxygen atom. Because carbon-oxygen bonds are strong, once the OH group has attached to the carbon atom, it tends to stay attached. The mechanism shows that the reaction takes place in two steps and describes exactly how those steps happen in terms of bonds being broken or made. It also shows that the steps have different rates of reaction - one slow and one fast. The rate determining step The overall rate of a reaction (the one which you would measure if you did some experiments) is controlled by the rate of the slowest step. In the example above, the hydroxide ion can't combine with the positive ion until that positive ion has been formed. The second step is in a sense waiting around for the first slow step to happen. The slow step of a reaction is known as the rate determining step. As long as there is a lot of difference between the rates of the various steps, when you measure the rate of a reaction, you are actually measuring the rate of the rate determining step. Example 1 Here is the mechanism we have already looked at. How do we know that it works like this? By doing rate of reaction experiments, you find this rate equation: The reaction is first order with respect to the organic compound, and zero order with respect to the hydroxide ions. The concentration of the hydroxide ions isn't affecting the overall rate of the reaction. If the hydroxide ions were taking part in the slow step of the reaction, increasing their concentration would speed the reaction up. Since their concentration doesn't seem to matter, they must be taking part in a later fast step. Increasing the concentration of the hydroxide ions will speed up the fast step, but that won't have a noticeable effect on the overall rate of the reaction. That is governed by the speed of the slow step. Example 2 At first sight this reaction seems identical with the last one. A bromine atom is being replaced by an OH group in an organic compound. However, the rate equation for this apparently similar reaction turns out to be quite different. That means that the mechanism must be different. The reaction this time is first order with respect to both the organic compound and the hydroxide ions. Both of these must be taking part in the slow step of the reaction. The reaction must happen by a straightforward collision between them. The carbon atom which is hit by the hydroxide ion has a slight positive charge on it and the bromine a slight negative one because of the difference in their electronegativities. As the hydroxide ion approaches, the bromine is pushed off in one smooth action.