Light – Reflection and – 23 PDF

Magnification The magnification produced by a lens, similar to that for spherical mirrors, is defined as the ratio of the height of the image and the height of the object. Magnification is represented by the letter m. If h is the height of the object and h ′ is the height of...

Magnification The magnification produced by a lens, similar to that for spherical mirrors, is defined as the ratio of the height of the image and the height of the object. Magnification is represented by the letter m. If h is the height of the object and h ′ is the height of the image given by a lens, then the magnification produced by the lens is given by, Height of the Image h ′ m= = (9.9) Height of the object h Magnification produced by a lens is also related to the object-distance u, and the image-distance v. This relationship is given by Magnification (m ) = h′/h = v/u (9.10) Example 9.3 A concave lens has focal length of 15 cm. At what distance should the object from the lens be placed so that it forms an image at 10 cm from the lens? Also, find the magnification produced by the lens. Solution A concave lens always forms a virtual, erect image on the same side of the object. Image-distance v = –10 cm; Focal length f = –15 cm; Object-distance u = ? 1 1 1 Since − = v u f 1 1 1 or, = – u v f 1 1 1 1 1 = – =– + u –10 ( –15) 10 15 1 −3 + 2 1 = = u 30 −30 or, u = – 30 cm Thus, the object-distance is 30 cm. Magnification m = v/u −10 cm 1 m= = ; + 0.33 − 30 cm 3 The positive sign shows that the image is erect and virtual. The image is one-third of the size of the object. Example 9.4 A 2.0 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 10 cm. The distance of the object from the lens is 15 cm. Find the nature, position and size of the image. Also find its magnification. 156 Science 2024-25