What will be the output of the following code: int i = 1, j = 10; do { if(i > j) { break; } j--; } while (++i < 5); System.out.println("i = " + i + " and j = " + j);

Steps to Solve

1. Initialize Variables Set the initial values: $i = 1$ and $j = 10$.

2. First Iteration of the Loop The code enters the do-while loop. Since $i \leq j$, the break statement is not executed.

• Decrement $j$: $j = j - 1 \Rightarrow j = 9$
• Increment $i$: $i = i + 1 \Rightarrow i = 2$

3. Second Iteration of the Loop The loop runs again with $i = 2$ and $j = 9$.

• No break; continue to decrement $j$: $j = 8$
• Increment $i$: $i = 3$

4. Third Iteration of the Loop Now $i = 3$ and $j = 8$.

• No break; decrement $j$: $j = 7$
• Increment $i$: $i = 4$

5. Fourth Iteration of the Loop With $i = 4$ and $j = 7$.

• Still no break; decrement $j$: $j = 6$
• Increment $i$: $i = 5$

6. Fifth Iteration of the Loop The loop checks with $i = 5$ and $j = 6$.

• The break is not reached yet. Decrement $j$: $j = 5$
• Increment $i$: $i = 6$

7. Exit Loop Now on the next check, $i = 6$ and $j = 5$.

• Here, $i > j$, which triggers the break statement, exiting the loop.

8. Final Output Finally, print the values of $i$ and $j$:

System.out.println("i = " + i + " and j = " + j);