What is the total work done on the crate?

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Understand the Problem

The question asks for the total work done on a crate being pushed across a level floor. To solve it, we need to consider the constants provided, such as the mass of the crate, the distance moved, and the coefficient of kinetic friction.

Answer

The total work done on the crate is approximately $70.37 \, \text{J}$.
Answer for screen readers

The total work done on the crate is approximately $70.37 , \text{J}$.

Steps to Solve

  1. Identify the forces acting on the crate The main forces acting on the crate are the applied force (due to the worker pushing the crate) and the frictional force opposing the motion.

  2. Calculate the weight of the crate The weight ($W$) can be calculated using the formula: $$ W = m \cdot g $$ where $m = 28.9 , \text{kg}$ (mass of the crate) and $g = 9.81 , \text{m/s}^2$ (acceleration due to gravity).

  3. Calculate the normal force Since the crate is on a level floor, the normal force ($F_n$) is equal to the weight: $$ F_n = W $$

  4. Calculate the frictional force The frictional force ($F_f$) can be found using the formula: $$ F_f = \mu \cdot F_n $$ where $\mu = 0.26$ (coefficient of kinetic friction). Substitute in the normal force from the previous step.

  5. Calculate the total work done Since the crate is moving at a constant velocity, the work done ($W_d$) against friction is given by: $$ W_d = F_f \cdot d $$ where $d = 4.85 , \text{m}$ (distance).

  6. Final calculation Insert the values from the previous steps into the formula for work done to find the total work.

The total work done on the crate is approximately $70.37 , \text{J}$.

More Information

The work done calculation considers the frictional force opposing the movement of the crate over the specified distance. Since the crate moves at constant velocity, the applied force equals the frictional force, making it straightforward to compute the work done against friction.

Tips

  • Ignoring the direction of forces: Ensure to consider that work is done against friction, which opposes the motion.
  • Confusing mass with weight: Remember to use the mass to find the weight, and treat normal force correctly.

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