What is the speed of the bob at the lowest point of its swing? (Use g = 9.8 m/s²)

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Understand the Problem

The question is asking for the calculation of the speed of a pendulum bob at the lowest point of its swing, given its mass and the height from which it was released. This involves applying principles of energy conservation, particularly converting potential energy into kinetic energy.

Answer

The speed of the bob at the lowest point of its swing is $7 \, \text{m/s}$.
Answer for screen readers

The speed of the bob at the lowest point of its swing is $7 , \text{m/s}$.

Steps to Solve

  1. Identify Given Values

The mass of the pendulum bob, $m = 2 , \text{kg}$, and the height from which it was released, $h = 2.5 , \text{m}$. The acceleration due to gravity is given as $g = 9.8 , \text{m/s}^2$.

  1. Calculate Potential Energy at the Starting Height

The potential energy (PE) at the height can be calculated using the formula: $$ \text{PE} = m \cdot g \cdot h $$

Substituting the given values: $$ \text{PE} = 2 , \text{kg} \cdot 9.8 , \text{m/s}^2 \cdot 2.5 , \text{m} $$

  1. Calculate the Potential Energy

Now, let's compute the potential energy: $$ \text{PE} = 2 \cdot 9.8 \cdot 2.5 = 49 , \text{J} $$

  1. Apply Conservation of Energy Principle

At the lowest point, all potential energy converts to kinetic energy (KE). Thus, we have: $$ \text{KE} = \text{PE} $$

  1. Set Kinetic Energy Formula

The kinetic energy is defined as: $$ \text{KE} = \frac{1}{2} m v^2 $$

Where (v) is the speed we want to find.

  1. Equate Kinetic Energy and Potential Energy

From the conservation of energy: $$ \frac{1}{2} m v^2 = \text{PE} $$

Substituting the potential energy we calculated: $$ \frac{1}{2} m v^2 = 49 , \text{J} $$

  1. Solve for the Speed (v)

Rearranging the equation to solve for (v): $$ v^2 = \frac{2 \cdot 49}{m} $$

Substituting (m = 2 , \text{kg}): $$ v^2 = \frac{2 \cdot 49}{2} = 49 $$

Then taking the square root: $$ v = \sqrt{49} = 7 , \text{m/s} $$

The speed of the bob at the lowest point of its swing is $7 , \text{m/s}$.

More Information

The conservation of energy principle states that the total mechanical energy remains constant if only conservative forces, like gravity, are acting. This is why the potential energy converts entirely to kinetic energy at the lowest point of the pendulum swing.

Tips

  • Forgetting to convert units: Always ensure that height is in meters, mass in kilograms, and acceleration due to gravity in the appropriate units.
  • Neglecting energy losses: In practical scenarios like air resistance, energy may not convert perfectly, but here we assume ideal conditions.

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