What is the oxidation number of chromium in ammonium dichromate, (NH4)2Cr2O7?
Understand the Problem
The question is asking for the oxidation number of chromium in the compound ammonium dichromate, (NH4)2Cr2O7. To solve it, we will analyze the oxidation states of the different elements in the compound and apply the rules for determining oxidation numbers.
Answer
+6
The oxidation number of chromium (Cr) in ammonium dichromate, (NH4)2Cr2O7, is +6.
Answer for screen readers
The oxidation number of chromium (Cr) in ammonium dichromate, (NH4)2Cr2O7, is +6.
More Information
In ammonium dichromate, the oxidation number of chromium is determined by balancing the known oxidation numbers of other atoms in the compound, resulting in chromium having a +6 oxidation state.
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