What is the equation of a line parallel to 2x - 3y = 3 that contains the point (3, -5)?

Question image

Understand the Problem

The question asks for the equation of a line that is parallel to the given line and passes through a specific point. To find the equation, we need to determine the slope of the given line and use it to derive the new equation that passes through the point (3, -5).

Answer

$y = \frac{2}{3}x - 7$
Answer for screen readers

The equation of the line is $y = \frac{2}{3}x - 7$.

Steps to Solve

  1. Convert the given line equation to slope-intercept form

    The given line is $2x - 3y = 3$. We will solve for $y$ to find the slope.

    Rearranging the equation: $$ -3y = -2x + 3 $$ Dividing by -3: $$ y = \frac{2}{3}x - 1 $$ The slope ($m$) of the given line is $\frac{2}{3}$.

  2. Use the point-slope form of a line

    Since we want a line parallel to the given line, it will have the same slope. We will use the point-slope form, which is $y - y_1 = m(x - x_1)$, where $(x_1, y_1)$ is the given point $(3, -5)$.

    Plugging in the values: $$ y - (-5) = \frac{2}{3}(x - 3) $$

  3. Simplify the point-slope equation

    Distributing the slope: $$ y + 5 = \frac{2}{3}x - 2 $$ Now, isolate $y$: $$ y = \frac{2}{3}x - 2 - 5 $$ Simplifying further: $$ y = \frac{2}{3}x - 7 $$

The equation of the line is $y = \frac{2}{3}x - 7$.

More Information

This equation represents a line that is parallel to the original line $2x - 3y = 3$ and passes through the point (3, -5). Since parallel lines have the same slope, we maintained the slope of $\frac{2}{3}$ while incorporating the new point.

Tips

  • Misunderstanding parallel lines: A common mistake is to use the slope of the point instead of the slope of the existing line. Remember that parallel lines have equal slopes.
  • Incorrectly manipulating the equation: Ensure you follow the algebraic steps carefully to avoid mistakes when isolating $y$.

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