The sum of three consecutive integers is 51. What are the numbers? A rectangle's length is 4 more than 6 times the width. The perimeter is 64 inches. Find the dimensions.

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Understand the Problem

The question is asking to find three consecutive integers that sum to 51 and the dimensions of a rectangle given specific conditions about its length and width, which relate to its perimeter of 64 inches.

Answer

The length is $28$ inches and the width is $4$ inches.
Answer for screen readers

The dimensions of the rectangle are:

  • Length: 28 inches
  • Width: 4 inches

Steps to Solve

  1. Identify Variables for Rectangle Dimensions
    Let ( x ) represent the width of the rectangle. Then, the length can be represented as ( 6x + 4 ).

  2. Set Up the Perimeter Equation
    The formula for the perimeter ( P ) of a rectangle is given by:
    $$ P = 2 \times (\text{length} + \text{width}) $$
    Substituting the known values, we have:
    $$ 2 \times ((6x + 4) + x) = 64 $$

  3. Simplify and Solve the Equation
    Distributing the 2:
    $$ 2 \times (7x + 4) = 64 $$
    This simplifies to:
    $$ 14x + 8 = 64 $$
    Now, subtract 8 from both sides:
    $$ 14x = 56 $$

  4. Divide to Find Width
    Divide each side by 14 to solve for ( x ):
    $$ x = \frac{56}{14} $$
    Thus,
    $$ x = 4 $$

  5. Calculate Length
    Now substitute ( x ) back to find the length:
    $$ \text{length} = 6x + 4 = 6(4) + 4 = 24 + 4 = 28 $$

The dimensions of the rectangle are:

  • Length: 28 inches
  • Width: 4 inches

More Information

The perimeter of a rectangle is directly related to its length and width. Knowing the relationship between these dimensions can help in various mathematical problems involving geometry.

Tips

  • Incorrectly applying the perimeter formula: Ensure the correct double multiplication of both dimensions.
  • Misinterpreting relationships: Make sure to clearly understand how width and length relate before forming conditions.

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