Solve the system of equations 2x + 5y = -9 and 3x + 4y = 4 by combining the equations.
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Understand the Problem
The question asks to solve a system of equations by combining them. Specifically, we need to find the values of x and y that satisfy both equations: 2x + 5y = -9 and 3x + 4y = 4.
Answer
The solution is \( x = 8, y = -5 \).
Answer for screen readers
The solution to the system of equations is $x = 8$ and $y = -5$.
Steps to Solve
- Multiply to align coefficients
To eliminate one variable, we need the coefficients of either $x$ or $y$ in both equations to match. Here, we will eliminate $y$.
Multiply the first equation, $2x + 5y = -9$, by $4$ and the second equation, $3x + 4y = 4$, by $5$:
[ 4(2x + 5y) = 4(-9) \quad \longrightarrow \quad 8x + 20y = -36 ]
[ 5(3x + 4y) = 5(4) \quad \longrightarrow \quad 15x + 20y = 20 ]
- Subtract the equations
Now, we subtract the modified first equation from the modified second equation to eliminate $y$:
[ (15x + 20y) - (8x + 20y) = 20 - (-36) ]
This simplifies to:
[ 7x = 56 ]
- Solve for (x)
Divide both sides by $7$:
[ x = \frac{56}{7} = 8 ]
- Substitute (x) back into one of the original equations
Now, we substitute $x = 8$ back into the first original equation, $2x + 5y = -9$:
[ 2(8) + 5y = -9 ]
- Solve for (y)
This simplifies to:
[ 16 + 5y = -9 ]
Now, isolate $y$:
[ 5y = -9 - 16 ] [ 5y = -25 ] [ y = \frac{-25}{5} = -5 ]
The solution to the system of equations is $x = 8$ and $y = -5$.
More Information
The values of $x$ and $y$ indicate the point at which the two lines given by the equations intersect on a Cartesian plane. The process used here is called elimination, which is one of the methods to solve systems of linear equations.
Tips
- Misalignment of coefficients when multiplying equations can lead to incorrect results; ensure you multiply correctly.
- Forgetting to simplify the equations before solving can make the final answer look complicated.
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