Solve the system of equations 2x + 5y = -9 and 3x + 4y = 4 by combining the equations.

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Understand the Problem

The question asks to solve a system of equations by combining them. Specifically, we need to find the values of x and y that satisfy both equations: 2x + 5y = -9 and 3x + 4y = 4.

Answer

The solution is \( x = 8, y = -5 \).
Answer for screen readers

The solution to the system of equations is $x = 8$ and $y = -5$.

Steps to Solve

  1. Multiply to align coefficients

To eliminate one variable, we need the coefficients of either $x$ or $y$ in both equations to match. Here, we will eliminate $y$.

Multiply the first equation, $2x + 5y = -9$, by $4$ and the second equation, $3x + 4y = 4$, by $5$:

[ 4(2x + 5y) = 4(-9) \quad \longrightarrow \quad 8x + 20y = -36 ]

[ 5(3x + 4y) = 5(4) \quad \longrightarrow \quad 15x + 20y = 20 ]

  1. Subtract the equations

Now, we subtract the modified first equation from the modified second equation to eliminate $y$:

[ (15x + 20y) - (8x + 20y) = 20 - (-36) ]

This simplifies to:

[ 7x = 56 ]

  1. Solve for (x)

Divide both sides by $7$:

[ x = \frac{56}{7} = 8 ]

  1. Substitute (x) back into one of the original equations

Now, we substitute $x = 8$ back into the first original equation, $2x + 5y = -9$:

[ 2(8) + 5y = -9 ]

  1. Solve for (y)

This simplifies to:

[ 16 + 5y = -9 ]

Now, isolate $y$:

[ 5y = -9 - 16 ] [ 5y = -25 ] [ y = \frac{-25}{5} = -5 ]

The solution to the system of equations is $x = 8$ and $y = -5$.

More Information

The values of $x$ and $y$ indicate the point at which the two lines given by the equations intersect on a Cartesian plane. The process used here is called elimination, which is one of the methods to solve systems of linear equations.

Tips

  • Misalignment of coefficients when multiplying equations can lead to incorrect results; ensure you multiply correctly.
  • Forgetting to simplify the equations before solving can make the final answer look complicated.

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