Si 2= 1, ¿cuánto es 2+2+2+2+2+2+2+2?

Understand the Problem

La pregunta establece una condición inusual (2 = 1) y luego pide calcular la suma de ocho doses (2+2+2+2+2+2+2+2). Debido a la condición inicial, cada '2' puede ser reemplazado por '1', simplificando el cálculo a una suma de ochos unos.

Answer

8
Answer for screen readers

8

Steps to Solve

  1. Substitute 1 for 2

Since we are given that $2 = 1$, we can substitute every instance of 2 with 1.

  1. Rewrite the expression

So, $2 + 2 + 2 + 2 + 2 + 2 + 2 + 2$ becomes $1 + 1 + 1 + 1 + 1 + 1 + 1 + 1$.

  1. Calculate the sum

Adding eight ones together yields: $1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 = 8$.

8

More Information

Given the condition that $2 = 1$, the solution highlights how mathematical operations change when unconventional constraints are introduced.

Tips

A common mistake is to ignore the initial condition ($2=1$) and directly calculate $2+2+2+2+2+2+2+2=16$.

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