Mass of moisture removed in drying 30 tonnes of wheat from 22% to 13% (wet basis) moisture content is:

Understand the Problem
The question is asking to calculate the mass of moisture removed when drying 30 tonnes of wheat, given that the initial moisture content is 22% and it is reduced to 13% on a wet basis. This involves applying the concept of moisture content and performing calculations based on the weight of the wheat.
Answer
$2700 \, \text{kg}$
Answer for screen readers
The mass of moisture removed when drying 30 tonnes of wheat is $2700 , \text{kg}$.
Steps to Solve
- Calculate initial moisture content To find the mass of moisture in the wheat at the initial moisture content of 22%, use the formula: $$ \text{Initial Moisture Mass} = \text{Total Mass} \times \frac{\text{Moisture Content}}{100} $$
For 30 tonnes (or 30,000 kg) of wheat: $$ \text{Initial Moisture Mass} = 30000 , \text{kg} \times \frac{22}{100} = 6600 , \text{kg} $$
- Calculate final moisture content Next, calculate the mass of moisture at the final moisture content of 13%: $$ \text{Final Moisture Mass} = \text{Total Mass} \times \frac{\text{Final Moisture Content}}{100} $$
For the same 30 tonnes of wheat: $$ \text{Final Moisture Mass} = 30000 , \text{kg} \times \frac{13}{100} = 3900 , \text{kg} $$
- Calculate mass of moisture removed Now, subtract the final moisture mass from the initial moisture mass to find the mass of moisture removed: $$ \text{Moisture Removed} = \text{Initial Moisture Mass} - \text{Final Moisture Mass} $$
Substituting the calculated values: $$ \text{Moisture Removed} = 6600 , \text{kg} - 3900 , \text{kg} = 2700 , \text{kg} $$
The mass of moisture removed when drying 30 tonnes of wheat is $2700 , \text{kg}$.
More Information
This calculation illustrates how to determine moisture content and loss during drying operations in a practical context, essential in food processing and agricultural management.
Tips
- Confusing wet and dry basis moisture content.
- Failing to convert units correctly (e.g., tonnes to kilograms).
- Incorrectly applying the percentage formula for moisture content.
AI-generated content may contain errors. Please verify critical information