In a trihybrid cross involving three independently assorting genes, is the expected proportion of offspring showing all three recessive traits 1/64, assuming each gene exhibits com... In a trihybrid cross involving three independently assorting genes, is the expected proportion of offspring showing all three recessive traits 1/64, assuming each gene exhibits complete dominance?

Understand the Problem

The question asks to determine if the expected proportion of offspring showing all three recessive traits in a trihybrid cross is 1/64, assuming each gene exhibits complete dominance. To determine the correctness we need to calculate the probability of each gene showing the recessive trait and then multiply those probabilities using the product rule.

Answer

Yes, the proportion is 1/64.

Yes, the expected proportion of offspring showing all three recessive traits in a trihybrid cross involving three independently assorting genes is 1/64, assuming complete dominance for each gene.

Answer for screen readers

Yes, the expected proportion of offspring showing all three recessive traits in a trihybrid cross involving three independently assorting genes is 1/64, assuming complete dominance for each gene.

More Information

In a trihybrid cross, we are dealing with three independently assorting genes. For each gene, the probability of an offspring inheriting two recessive alleles (and thus expressing the recessive trait) is 1/4. Since the genes assort independently, we multiply the probabilities for each gene: (1/4) * (1/4) * (1/4) = 1/64.

Tips

A common mistake is to only consider one or two genes. A trihybrid cross involves three genes, so all three must be accounted for.

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