Find the equation of Line 4 & Line 5.

Question image

Understand the Problem

The question is asking to find the equations of two lines: Line 4, which is perpendicular to the line segment connecting points C and D and passes through its midpoint, and Line 5, which is parallel to Line 4 and passes through the point (-3, -4). We will need to calculate the midpoint of CD, determine the slope of CD to find the slope of Line 4 (which is its negative reciprocal), and then formulate the equations for both lines.

Answer

Line 4: $y = -4x + 12$; Line 5: $y = -4x - 16$
Answer for screen readers

The equations of the lines are:

Line 4: $y = -4x + 12$

Line 5: $y = -4x - 16$

Steps to Solve

  1. Calculate the Midpoint of Segment CD

To find the midpoint, use the midpoint formula:

$$ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) $$

Substituting points C and D where $C(-4, -6)$ and $D(12, -2)$:

$$ M = \left( \frac{-4 + 12}{2}, \frac{-6 - 2}{2} \right) = \left( \frac{8}{2}, \frac{-8}{2} \right) = (4, -4) $$

  1. Determine the Slope of Line Segment CD

The slope of a line through two points is calculated as:

$$ m = \frac{y_2 - y_1}{x_2 - x_1} $$

Using points C and D:

$$ m_{CD} = \frac{-2 - (-6)}{12 - (-4)} = \frac{4}{16} = \frac{1}{4} $$

  1. Find the Slope of Line 4 (Perpendicular to CD)

For a line perpendicular to another, the slope is the negative reciprocal:

$$ m_{Line4} = -\frac{1}{m_{CD}} = -\frac{1}{\frac{1}{4}} = -4 $$

  1. Write the Equation of Line 4 Using Point-Slope Form

Point-slope form is given by:

$$ y - y_1 = m(x - x_1) $$

Using point $(4, -4)$ and slope $-4$:

$$ y - (-4) = -4(x - 4) $$

This simplifies to:

$$ y + 4 = -4x + 16 $$

So,

$$ y = -4x + 12 $$

  1. Write the Equation of Line 5 (Parallel to Line 4)

Line 5 will have the same slope as Line 4, which is $-4$. Using point (-3, -4):

$$ y - y_1 = m(x - x_1) $$

Substituting:

$$ y - (-4) = -4(x - (-3)) $$

This simplifies to:

$$ y + 4 = -4(x + 3) $$

So,

$$ y + 4 = -4x - 12 $$

Thus,

$$ y = -4x - 16 $$

The equations of the lines are:

Line 4: $y = -4x + 12$

Line 5: $y = -4x - 16$

More Information

Line 4 is perpendicular to line segment CD and intersects it at its midpoint, while Line 5 runs parallel to Line 4 and passes through a specified point. This exercise illustrates how to derive equations of lines based on given points and relationships.

Tips

  • Failing to accurately calculate the midpoint.
  • Incorrectly finding the negative reciprocal for the perpendicular slope.
  • Confusing the point-slope form when substituting values.

AI-generated content may contain errors. Please verify critical information

Thank you for voting!
Use Quizgecko on...
Browser
Browser