CH3CHBrCH2CHClCH3 is the generalized representation of what number of stereoisomers?
Understand the Problem
The question is asking for the number of stereoisomers that can be derived from the compound represented as CH3CHBrCH2CHClCH3. This involves determining the chiral centers in the molecule and calculating the resulting stereoisomers based on the formula for stereoisomers.
Answer
4
Answer for screen readers
The number of stereoisomers is ( 4 ).
Steps to Solve
- Identify Chiral Centers
A chiral center is typically a carbon atom that has four different substituents. In the given compound $CH_3CHBrCH_2CHClCH_3$, we need to examine each carbon to see if any are chiral.
- Locate the Chiral Carbons
- The second carbon ($CHBr$) has bromine, a hydrogen, and two different groups (the first carbon chain and the third carbon) attached to it. This carbon is chiral.
- The fourth carbon ($CHCl$) has chlorine, a hydrogen, and two different carbon groups attached to it, making it chiral as well.
- Count the Chiral Centers
There are 2 chiral centers in the compound.
- Calculate the Number of Stereoisomers
The formula to determine the number of stereoisomers is given by $2^n$, where $n$ is the number of chiral centers.
We have: $$ n = 2 $$
Therefore: $$ \text{Number of stereoisomers} = 2^2 = 4 $$
The number of stereoisomers is ( 4 ).
More Information
The presence of chiral centers in a molecule allows for stereoisomerism, leading to distinct configurations that exhibit different physical properties. Each chiral center doubles the possible configurations of the molecule.
Tips
- Confusing chiral centers with non-chiral centers. Remember that only carbon atoms with four different substituents qualify as chiral centers.
- Misapplying the formula for calculating stereoisomers; make sure to use the correct exponent based on the number of chiral centers.
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