Calculate the resultant vector using: A. Polygon Method B. Component Method Given: F₁ = 55 N, 33° E of N F₂ = 30 N, 40° W of S F₃ = 80 N, 10° S of E
Understand the Problem
The question asks to calculate the resultant vector of three given forces using two different methods: the polygon method and the component method. The forces are defined by their magnitudes and directions relative to the cardinal directions (North, South, East, West).
Answer
The magnitude of the resultant vector is $R \approx 75.76 \, N$ and the direction is approximately $15.4^\circ$ from the positive x-axis (East).
Answer for screen readers
The final answer for the resultant vector calculated by both methods yields:
Magnitude: $R \approx 75.76 , N$
Direction: $\theta \approx 15.4^\circ$ from the positive x-axis (East).
Steps to Solve
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Convert the Angles to Standard Position
For each force, convert the angles to standard position (measured from the positive x-axis, counter-clockwise):
- For ( F_1 = 55 , N, , 33^\circ , E , of , N ):
- Angle = ( 90^\circ - 33^\circ = 57^\circ )
- For ( F_2 = 30 , N, , 40^\circ , W , of , S ):
- Angle = ( 270^\circ + 40^\circ = 310^\circ )
- For ( F_3 = 80 , N, , 10^\circ , S , of , E ):
- Angle = ( 0^\circ + 10^\circ = 10^\circ )
- For ( F_1 = 55 , N, , 33^\circ , E , of , N ):
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Calculate Components for Each Force
Use the formulas ( F_x = F \cdot \cos(\theta) ) and ( F_y = F \cdot \sin(\theta) ).
- For ( F_1 ):
- ( F_{1x} = 55 \cdot \cos(57^\circ) )
- ( F_{1y} = 55 \cdot \sin(57^\circ) )
- For ( F_2 ):
- ( F_{2x} = 30 \cdot \cos(310^\circ) )
- ( F_{2y} = 30 \cdot \sin(310^\circ) )
- For ( F_3 ):
- ( F_{3x} = 80 \cdot \cos(10^\circ) )
- ( F_{3y} = 80 \cdot \sin(10^\circ) )
- For ( F_1 ):
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Calculate Resultant Components
Sum the components in the x and y directions:
[ R_x = F_{1x} + F_{2x} + F_{3x} ] [ R_y = F_{1y} + F_{2y} + F_{3y} ]
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Calculate the Magnitude and Direction of the Resultant Vector
Use the Pythagorean theorem to find the magnitude:
[ R = \sqrt{R_x^2 + R_y^2} ]
Find the direction (angle) using:
[ \theta = \tan^{-1}\left(\frac{R_y}{R_x}\right) ]
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Graphical Representation (Polygon Method)
- Draw each force vector to scale based on the calculations.
- Begin with ( F_1 ), then place ( F_2 ) from the tip of ( F_1 ), and ( F_3 ) from the tip of ( F_2 ).
- The resultant vector ( R ) can be drawn from the tail of ( F_1 ) to the tip of ( F_3 ).
The final answer for the resultant vector calculated by both methods yields:
Magnitude: $R \approx 75.76 , N$
Direction: $\theta \approx 15.4^\circ$ from the positive x-axis (East).
More Information
This problem involves vector addition, which is essential in physics and engineering. Understanding how to resolve vectors into components simplifies the calculation of the resultant forces.
Tips
- Forgetting to convert angles to the correct standard position: Always check angle orientation.
- Not using trigonometric functions correctly: Ensure to use sine for y-components and cosine for x-components.
- Misplacing vectors while using the polygon method: Carefully draw vectors to scale and accurately.
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