Calculate the molar mass of ammonium carbonate.

Understand the Problem

The question is asking for the calculation of the molar mass of ammonium carbonate (NH₄)₂CO₃. To solve this, we need to identify the atomic masses of the constituent elements (nitrogen, hydrogen, carbon, and oxygen) and then sum their masses according to the chemical formula.

Answer

The molar mass of ammonium carbonate is $96.11 \, \text{g/mol}$.
Answer for screen readers

The molar mass of ammonium carbonate is $96.11 , \text{g/mol}$.

Steps to Solve

  1. Identify the elements and their counts in the formula

The chemical formula for ammonium carbonate is $(NH_4)_2CO_3$.

  • There are 2 nitrogen (N) atoms.
  • There are 8 hydrogen (H) atoms (4 from each of the 2 ammonium ions).
  • There is 1 carbon (C) atom.
  • There are 3 oxygen (O) atoms.
  1. Find the atomic masses of the elements

Next, we will look up the atomic masses of each element:

  • Nitrogen (N): approximately 14.01 g/mol
  • Hydrogen (H): approximately 1.01 g/mol
  • Carbon (C): approximately 12.01 g/mol
  • Oxygen (O): approximately 16.00 g/mol
  1. Calculate the total mass for each element

Now we will calculate the molar mass contributed by each element:

  • For Nitrogen: $$ 2 \times 14.01 , \text{g/mol} = 28.02 , \text{g/mol} $$

  • For Hydrogen: $$ 8 \times 1.01 , \text{g/mol} = 8.08 , \text{g/mol} $$

  • For Carbon: $$ 1 \times 12.01 , \text{g/mol} = 12.01 , \text{g/mol} $$

  • For Oxygen: $$ 3 \times 16.00 , \text{g/mol} = 48.00 , \text{g/mol} $$

  1. Sum all the contributions to find the molar mass

Finally, we add all these values together to get the total molar mass of ammonium carbonate:

$$ 28.02 , \text{g/mol} + 8.08 , \text{g/mol} + 12.01 , \text{g/mol} + 48.00 , \text{g/mol} = 96.11 , \text{g/mol} $$

The molar mass of ammonium carbonate is $96.11 , \text{g/mol}$.

More Information

The molar mass can be essential in various chemical applications, including stoichiometry calculations, formulation of chemical compounds, and determining the amounts of substances needed for reactions.

Tips

  • Failing to account for the number of atoms of each element properly when calculating their contributions.
  • Mixing up the atomic masses of different elements.

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