Arrange the three isomers of alkane with molecular formula C5H12 in increasing order of boiling points and write their IUPAC names.
Understand the Problem
The question is asking to arrange the three isomers of the alkane with the formula C₅H₁₂ in order of their boiling points and to provide their IUPAC names.
Answer
2,2-dimethylpropane, 2-methylbutane, n-pentane.
The increasing order of boiling points is: 2,2-dimethylpropane (neopentane), 2-methylbutane (isopentane), n-pentane.
Answer for screen readers
The increasing order of boiling points is: 2,2-dimethylpropane (neopentane), 2-methylbutane (isopentane), n-pentane.
More Information
Boiling points decrease with increased branching: n-pentane (straight chain) has the highest boiling point, while 2,2-dimethylpropane, with the most branching, has the lowest.
Tips
A common mistake is assuming more branched isomers have higher boiling points due to higher molecular weight, but branching lowers boiling points.
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