An object with a mass of 25 kg hangs from the ceiling. It is pulled sideways until the string forms an angle of 30° with the ceiling. Use a scale drawing or calculation and determi... An object with a mass of 25 kg hangs from the ceiling. It is pulled sideways until the string forms an angle of 30° with the ceiling. Use a scale drawing or calculation and determine the tension in the string as well as the applied force with which it is pulled sideways.
Understand the Problem
The question is asking to determine the tension in a string from which a 25 kg object is hanging, when the string is pulled to form a 30° angle with the ceiling. The solution may involve calculations or scale drawings.
Answer
The tension in the string is approximately $283.67 \, \text{N}$.
Answer for screen readers
The tension in the string is approximately $283.67 , \text{N}$.
Steps to Solve
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Identify the Forces and Draw a Diagram
The object has a mass of $25 , \text{kg}$. The gravitational force (weight) acting on it can be calculated using the equation:
$$ F_g = m \cdot g $$
where $g$ is the acceleration due to gravity ($9.81 , \text{m/s}^2$).
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Calculate the Weight (Gravitational Force)
Plugging in the values we have:
$$ F_g = 25 , \text{kg} \cdot 9.81 , \text{m/s}^2 = 245.25 , \text{N} $$
This is the downward force acting on the object.
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Resolve the Tension in the String
When the string is pulled to form a $30^\circ$ angle with the ceiling, the tension ($T$) in the string can be resolved into two components:
- Vertical component: $T_y = T \cdot \cos(30^\circ)$
- Horizontal component: $T_x = T \cdot \sin(30^\circ)$
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Set Up the Equation for Vertical Forces
In equilibrium, the vertical component of tension must balance the weight of the object:
$$ T_y = F_g $$
Therefore,
$$ T \cdot \cos(30^\circ) = 245.25 , \text{N} $$
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Calculate Tension in the String
From the previous equation, solve for tension $T$:
$$ T = \frac{245.25 , \text{N}}{\cos(30^\circ)} $$
Use the value $\cos(30^\circ) = \frac{\sqrt{3}}{2} \approx 0.866$.
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Final Calculation of Tension
Substitute the values:
$$ T = \frac{245.25 , \text{N}}{0.866} \approx 283.67 , \text{N} $$
The tension in the string is approximately $283.67 , \text{N}$.
More Information
This calculation demonstrates the principles of forces in equilibrium and vector resolution. The tension must counteract both the gravitational force acting on the mass and the angle created by the pulling force.
Tips
- Not Considering Angles: Forgetting to resolve the tension into components is a common error.
- Using Incorrect Trigonometric Values: Make sure to use the correct trigonometric function for the angle given.
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