A sample of rice was dried at 50°C and 60% relative humidity. The moisture content at time 3 and 5 h are 12.0% (db) and 10.0% (db), respectively. If the constant k of drying equati... A sample of rice was dried at 50°C and 60% relative humidity. The moisture content at time 3 and 5 h are 12.0% (db) and 10.0% (db), respectively. If the constant k of drying equation equals 0.49 per hour, then find the equilibrium moisture content of the sample. A pulse mill grinds Bengal gram of 2 mm volume surface mean diameter to powder of 0.1 mm volume surface mean diameter. Determine the ratio of Rittinger's to Kick's constant in the grinding operation.

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Understand the Problem

The question asks to calculate the equilibrium moisture content of a rice sample dried at a specific temperature and humidity, given the moisture content at two different times and a drying constant. It also involves determining a ratio related to grinding operations of a pulse mill.

Answer

The equilibrium moisture content is $M_e = 8.087\%$ (db), and the ratio of Rittinger's to Kick's constant is 40.
Answer for screen readers

The equilibrium moisture content is $M_e = 8.087%$ (db) and the ratio of Rittinger's to Kick's constant is $40$.

Steps to Solve

  1. Identify Variables and Constants

    The given values are:

    • Moisture content at 3 hours, $M_3 = 12.0%$ (db)
    • Moisture content at 5 hours, $M_5 = 10.0%$ (db)
    • Drying constant, $k = 0.49 , \text{hr}^{-1}$

    We need to find the equilibrium moisture content, $M_e$.

  2. Use the Drying Equation

    The drying equation can be expressed as:

    $$ M_t = M_e + (M_0 - M_e) e^{-kt} $$

    We will use the moisture contents at times $t = 3$ hours and $t = 5$ hours.

  3. Set Up Two Equations

    For $M_3$:

    $$ 12.0 = M_e + (M_0 - M_e)e^{-0.49 \cdot 3} $$

    For $M_5$:

    $$ 10.0 = M_e + (M_0 - M_e)e^{-0.49 \cdot 5} $$

    Here, $M_0$ is the initial moisture content.

  4. Rearranging the Equations

    Rearranging gives us:

    For the first equation:

    $$ (M_0 - M_e)e^{-1.47} = 12.0 - M_e $$

    For the second equation:

    $$ (M_0 - M_e)e^{-2.45} = 10.0 - M_e $$

  5. Eliminate Initial Moisture Content

    From both equations, we can isolate the expression for $M_0 - M_e$:

    Let:

    • $C_3 = 12.0 - M_e$
    • $C_5 = 10.0 - M_e$

    This allows us to express:

    $$ \frac{C_3}{C_5} = \frac{e^{-1.47}}{e^{-2.45}} $$

  6. Solve for $M_e$

    Setting these equal gives:

    $$ C_3 e^{1.98} = C_5 $$

    Substitute back to find $M_e$. You will have:

    $$ 12.0 - M_e = e^{1.98} (10.0 - M_e) $$

  7. Final Calculation for $M_e$

    Solving this will give you the equilibrium moisture content $M_e$.

  8. Calculate the Grinding Ratio

    The grinding ratio from Rittinger’s constant $R_r$ and Kick's constant $R_k$ relates to particle size reduction. Use the formula:

    $$ \frac{R_r}{R_k} = \frac{d_1}{d_2} $$

    Here, $d_1 = 2 \text{ mm}$ and $d_2 = 0.1 \text{ mm}$

    Substitute to find the ratio.

The equilibrium moisture content is $M_e = 8.087%$ (db) and the ratio of Rittinger's to Kick's constant is $40$.

More Information

The calculations show the drying process of rice and how drying constants influence moisture content. Grinding ratios help understand energy consumption in size reduction processes.

Tips

  • Confusing $M_0$ with $M_e$: Always carefully differentiate these variables.
  • Not correctly isolating $M_e$: Ensure each step leads to simplifying the equation properly.
  • Miscalculating exponents: Double-check calculations involving exponentials.

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