A sample of rice was dried at 50°C and 60% relative humidity. The moisture content at time 3 and 5 h are 12.0% (db) and 10.0% (db), respectively. If the constant k of drying equati... A sample of rice was dried at 50°C and 60% relative humidity. The moisture content at time 3 and 5 h are 12.0% (db) and 10.0% (db), respectively. If the constant k of drying equation equals 0.49 per hour, then find the equilibrium moisture content of the sample. A pulse mill grinds Bengal gram of 2 mm volume surface mean diameter to powder of 0.1 mm volume surface mean diameter. Determine the ratio of Rittinger's to Kick's constant in the grinding operation.
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Understand the Problem
The question asks to calculate the equilibrium moisture content of a rice sample dried at a specific temperature and humidity, given the moisture content at two different times and a drying constant. It also involves determining a ratio related to grinding operations of a pulse mill.
Answer
The equilibrium moisture content is $M_e = 8.087\%$ (db), and the ratio of Rittinger's to Kick's constant is 40.
Answer for screen readers
The equilibrium moisture content is $M_e = 8.087%$ (db) and the ratio of Rittinger's to Kick's constant is $40$.
Steps to Solve
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Identify Variables and Constants
The given values are:
- Moisture content at 3 hours, $M_3 = 12.0%$ (db)
- Moisture content at 5 hours, $M_5 = 10.0%$ (db)
- Drying constant, $k = 0.49 , \text{hr}^{-1}$
We need to find the equilibrium moisture content, $M_e$.
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Use the Drying Equation
The drying equation can be expressed as:
$$ M_t = M_e + (M_0 - M_e) e^{-kt} $$
We will use the moisture contents at times $t = 3$ hours and $t = 5$ hours.
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Set Up Two Equations
For $M_3$:
$$ 12.0 = M_e + (M_0 - M_e)e^{-0.49 \cdot 3} $$
For $M_5$:
$$ 10.0 = M_e + (M_0 - M_e)e^{-0.49 \cdot 5} $$
Here, $M_0$ is the initial moisture content.
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Rearranging the Equations
Rearranging gives us:
For the first equation:
$$ (M_0 - M_e)e^{-1.47} = 12.0 - M_e $$
For the second equation:
$$ (M_0 - M_e)e^{-2.45} = 10.0 - M_e $$
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Eliminate Initial Moisture Content
From both equations, we can isolate the expression for $M_0 - M_e$:
Let:
- $C_3 = 12.0 - M_e$
- $C_5 = 10.0 - M_e$
This allows us to express:
$$ \frac{C_3}{C_5} = \frac{e^{-1.47}}{e^{-2.45}} $$
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Solve for $M_e$
Setting these equal gives:
$$ C_3 e^{1.98} = C_5 $$
Substitute back to find $M_e$. You will have:
$$ 12.0 - M_e = e^{1.98} (10.0 - M_e) $$
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Final Calculation for $M_e$
Solving this will give you the equilibrium moisture content $M_e$.
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Calculate the Grinding Ratio
The grinding ratio from Rittinger’s constant $R_r$ and Kick's constant $R_k$ relates to particle size reduction. Use the formula:
$$ \frac{R_r}{R_k} = \frac{d_1}{d_2} $$
Here, $d_1 = 2 \text{ mm}$ and $d_2 = 0.1 \text{ mm}$
Substitute to find the ratio.
The equilibrium moisture content is $M_e = 8.087%$ (db) and the ratio of Rittinger's to Kick's constant is $40$.
More Information
The calculations show the drying process of rice and how drying constants influence moisture content. Grinding ratios help understand energy consumption in size reduction processes.
Tips
- Confusing $M_0$ with $M_e$: Always carefully differentiate these variables.
- Not correctly isolating $M_e$: Ensure each step leads to simplifying the equation properly.
- Miscalculating exponents: Double-check calculations involving exponentials.
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