A mixture vapor of 10% mole of methanol and 90% mole of air stream feed to a single condenser at 180 °C and 1 atm. About 80% of the methanol is liquefied in this steady-state proce... A mixture vapor of 10% mole of methanol and 90% mole of air stream feed to a single condenser at 180 °C and 1 atm. About 80% of the methanol is liquefied in this steady-state process, while the remaining fraction exits with the air stream as a vapor product. Both exit streams are at 0 °C and 5 atm.
Understand the Problem
The question is asking for an analysis of a separation process involving a vapor mixture of methanol and air, specifically focusing on the behavior of the methanol under specified conditions in a condenser. The goal is to evaluate the amount of methanol that remains as vapor versus the amount that is condensed.
Answer
80% of methanol liquefied; 20% with air vapor.
80% of the methanol is liquefied in the condenser, while 20% remains in the vapor phase with air. The air composition remains unchanged in terms of moles.
Answer for screen readers
80% of the methanol is liquefied in the condenser, while 20% remains in the vapor phase with air. The air composition remains unchanged in terms of moles.
More Information
In separating methanol using condensation, only the methanol component undergoes phase change, while the air remains in the vapor state.
Tips
A common mistake is assuming air condenses as well. Air remains in the vapor state, only methanol condenses.
Sources
AI-generated content may contain errors. Please verify critical information
