A and B together can finish a piece of work in 11 1/9 days. B is 25% more efficient than A. If B starts working alone on the same piece of work and A joins him after 6 days, in how... A and B together can finish a piece of work in 11 1/9 days. B is 25% more efficient than A. If B starts working alone on the same piece of work and A joins him after 6 days, in how many days will the entire work be completed?

Question image

Understand the Problem

The question is asking to calculate the total time required to complete a piece of work when one worker (B) starts working alone for 6 days and then is joined by another worker (A). The problem requires an understanding of work rates and efficiency based on the given conditions.

Answer

The total time required is $\frac{124}{9}$ days, or approximately 13.78 days.
Answer for screen readers

The total time required to complete the entire work is $\frac{124}{9}$ days, or approximately 13.78 days.

Steps to Solve

  1. Calculate the combined work rate of A and B

Since A and B together can finish the work in $11 \frac{1}{9}$ days, we first convert this to an improper fraction: $$ 11 \frac{1}{9} = \frac{100}{9} \text{ days} $$ The work rate of A and B together is: $$ \text{Work rate} = \frac{1 \text{ work}}{\frac{100}{9} \text{ days}} = \frac{9}{100} \text{ work/day} $$

  1. Determine the work rates of A and B

Let the work rate of A be $x$. Since B is 25% more efficient than A, B's work rate is: $$ B = 1.25x $$ Thus, the combined work rate can be expressed as: $$ x + 1.25x = 2.25x $$ Setting this equal to the combined rate we found: $$ 2.25x = \frac{9}{100} $$ Now we solve for $x$: $$ x = \frac{9}{100 \times 2.25} = \frac{9}{225} = \frac{1}{25} \text{ work/day} $$ So, A’s work rate is $\frac{1}{25}$ and B’s work rate is: $$ B = 1.25 \times \frac{1}{25} = \frac{1}{20} \text{ work/day} $$

  1. Calculate the work done by B alone for 6 days

In 6 days, the work done by B alone would be: $$ \text{Work done} = \text{Rate of B} \times \text{Time} = \frac{1}{20} \times 6 = \frac{6}{20} = \frac{3}{10} $$

  1. Calculate the remaining work

The remaining work after B has worked for 6 days: $$ \text{Remaining work} = 1 - \frac{3}{10} = \frac{7}{10} $$

  1. Calculate the time for A and B to complete the remaining work together

The combined work rate of A and B is: $$ \text{Combined rate} = \frac{1}{25} + \frac{1}{20} $$ Finding a common denominator (LCM of 25 and 20 is 100): $$ \text{Combined rate} = \frac{4}{100} + \frac{5}{100} = \frac{9}{100} \text{ work/day} $$ Now, we calculate the time required to complete the remaining work: $$ \text{Time} = \frac{\text{Remaining work}}{\text{Combined rate}} = \frac{\frac{7}{10}}{\frac{9}{100}} = \frac{7 \times 100}{10 \times 9} = \frac{700}{90} = \frac{70}{9} \text{ days} $$

  1. Calculate the total time to complete the work

The total time required to complete the work is the 6 days that B worked alone plus the time A and B worked together: $$ \text{Total Time} = 6 + \frac{70}{9} = \frac{54}{9} + \frac{70}{9} = \frac{124}{9} \text{ days} \approx 13.78 \text{ days} $$

The total time required to complete the entire work is $\frac{124}{9}$ days, or approximately 13.78 days.

More Information

This problem demonstrates the concept of work rates and the impact of collaboration on work efficiency. It's common in time and work problems to establish variables representing rates, and then find the total time by breaking down individual contributions.

Tips

  • Forgetting to convert mixed numbers into improper fractions when calculating rates.
  • Not finding a common denominator when adding fractions.
  • Miscalculating the contributions of each worker over the given time frames.

AI-generated content may contain errors. Please verify critical information

Thank you for voting!
Use Quizgecko on...
Browser
Browser