1. (a) Electric charges are uniformly distributed in a small volume. The flux of electric field through a spherical surface of radius 2 cm surrounding the total charge is 10 V × m.... 1. (a) Electric charges are uniformly distributed in a small volume. The flux of electric field through a spherical surface of radius 2 cm surrounding the total charge is 10 V × m. The flux over a sphere of radius 4 cm will be? (Provide options: (A) 10V × m, (B) 20 V × m, (C) 40V × m, (D) 80 V × m). (b) A moving charge produces: (A) electric field only, (B) magnetic field only, (C) both electric and magnetic fields, (D) none of the above. (c) An electromagnetic wave propagating through vacuum is described by E = E0 sin(kx - ωt), B = B0 sin(kx - ωt). Then: (A) E0k = B0ω, (B) E0B0 = ωk, (C) E0ω = B0k, (D) E0B0 = √(ωk). (d) A double convex lens is made of a material having refractive.
Understand the Problem
The question is asking for concepts related to physics, including electric charges, electric fields, electromagnetic waves, and optics. It has multiple parts on topics like Gauss's Law, the behavior of light, and comparisons between types of materials.
Answer
(a) 10 V×m, (b) both fields, (c) E0k = B0ω.
(a) The flux over a sphere of radius 4 cm will be 10 V×m, (b) A moving charge produces both electric and magnetic fields, (c) E0k = B0ω.
Answer for screen readers
(a) The flux over a sphere of radius 4 cm will be 10 V×m, (b) A moving charge produces both electric and magnetic fields, (c) E0k = B0ω.
More Information
Gauss's law states that the electric flux through a closed surface depends only on the charge enclosed, so the radius change does not affect the flux if all other factors remain the same. A moving charge generates both electric and magnetic fields. For an electromagnetic wave, E0k = B0ω ensures wave propagation.
Tips
A common mistake is assuming that changing the size of the sphere affects the flux when the charge enclosed does not change. Remember, flux depends only on the enclosed charge.
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