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If in an interference pattern, the ratio between maximum and minimum intensities is 36:1, find the ratio between the amplitude and intensities of the two interfering waves.
If in an interference pattern, the ratio between maximum and minimum intensities is 36:1, find the ratio between the amplitude and intensities of the two interfering waves.
7:5, 49:25
Two coherent sources of intensity ratio 9:1 interfere. Prove that in the interference pattern, (Imax - Imin) / (Imax + Imin) = ?
Two coherent sources of intensity ratio 9:1 interfere. Prove that in the interference pattern, (Imax - Imin) / (Imax + Imin) = ?
3/5
What is the wavelength (in nm) in the visible region (400 nm - 700 nm) that is strongly reflected by a glass plate of thickness 500 nm and refractive index 1.5?
What is the wavelength (in nm) in the visible region (400 nm - 700 nm) that is strongly reflected by a glass plate of thickness 500 nm and refractive index 1.5?
600 nm
Find the thickness of a soap film (refractive index = 1.5) that reflects white light showing a maximum at 600 nm and minima at 450 nm with no minimum in between.
Find the thickness of a soap film (refractive index = 1.5) that reflects white light showing a maximum at 600 nm and minima at 450 nm with no minimum in between.
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In Newton's rings experiment, the diameter of the 4th and 12th dark rings are 0.400 cm and 0.700 cm respectively. What is the diameter of the 20th dark ring?
In Newton's rings experiment, the diameter of the 4th and 12th dark rings are 0.400 cm and 0.700 cm respectively. What is the diameter of the 20th dark ring?
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If in a Newton’s rings experiment, the air in the interspace is replaced by a liquid of refractive index 1.33, in what proportion would the diameters of the rings change?
If in a Newton’s rings experiment, the air in the interspace is replaced by a liquid of refractive index 1.33, in what proportion would the diameters of the rings change?
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If nth dark ring due to wavelength λ1 coincides with (n+1)th dark ring due to λ2, prove that the radius of nth dark ring of wavelength λ1 is equal to what?
If nth dark ring due to wavelength λ1 coincides with (n+1)th dark ring due to λ2, prove that the radius of nth dark ring of wavelength λ1 is equal to what?
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Calculate the angular position of the second and third minima on either side of the central maximum for light of wavelength 5500 Å falling normally on a slit of width 22 × 10^-5 cm.
Calculate the angular position of the second and third minima on either side of the central maximum for light of wavelength 5500 Å falling normally on a slit of width 22 × 10^-5 cm.
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A 10 cm long tube containing 48 cm³ of sugar solution rotates the plane of polarization by 5.5°. If the specific rotation of sugar is 66°, calculate the mass of sugar in solution.
A 10 cm long tube containing 48 cm³ of sugar solution rotates the plane of polarization by 5.5°. If the specific rotation of sugar is 66°, calculate the mass of sugar in solution.
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A sugar solution in a tube of length 40 cm produces optical rotation of 16°. If the solution is diluted to one-third of its previous concentration, find the optical rotation produced by a 60 cm long tube containing the dilute solution.
A sugar solution in a tube of length 40 cm produces optical rotation of 16°. If the solution is diluted to one-third of its previous concentration, find the optical rotation produced by a 60 cm long tube containing the dilute solution.
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Study Notes
Interference of Waves
- The ratio of maximum to minimum intensity in an interference pattern is directly related to the ratio of the amplitudes of the two interfering waves.
- For interference patterns with an intensity ratio of 36:1, the amplitude ratio of the interfering waves is 7:5.
- In interference patterns, the intensity ratio between maximum and minimum intensities is related to the amplitude ratio of the interfering waves.
- If two coherent sources have an intensity ratio of 9:1, the ratio of the difference to sum of maximum and minimum intensities (Imax-Imin)/(Imax+Imin) is 3/5.
Thin Film Interference
- Thin films can cause interference of reflected light due to the path difference introduced by the multiple reflections within the film.
- The wavelength of light reflected from a thin film depends on the thickness of the film and the refractive index of the material.
- For a glass plate with a thickness of 500 nm and a refractive index of 1.5, the wavelength of light in the visible region (400 nm - 700 nm) that is strongly reflected is 600 nm.
- The color of reflected light from a soap film depends on the thickness and refractive index of the film.
- A soap film with a refractive index of 1.5 showing a maximum at 600 nm and a minimum at 450 nm with no minima in between has a thickness of 3 x 10^-7 m.
Newton's Rings
- Newton's rings are an interference phenomenon observed when a plano-convex lens is placed on a flat glass plate.
- The diameter of the dark rings in Newton's rings experiment is proportional to the square root of the ring order.
- The diameter of the 4th, 12th, and 20th dark rings in a Newton's rings experiment are 0.400 cm, 0.700 cm, and 0.906 cm respectively.
- The diameter of the dark rings in Newton's rings experiments are altered by the medium in the interspace.
- Replacing air with a liquid of refractive index 1.33 in a Newton's rings experiment will reduce the diameters of the rings by a factor of 0.867.
Diffraction
- Diffraction occurs when a wave passes through an opening or around an obstacle.
- The angular position of the minima in a single-slit diffraction pattern is determined by the wavelength of light and the width of the slit.
- For a slit of width 22 x 10^-5 cm and light of wavelength 5500 Å, the angular position of the second and third minima are 30° and 48.6°.
Polarization
- Polarization refers to the direction of the electric field vector in an electromagnetic wave.
- Plane polarized light can be rotated by passing it through a solution of an optically active substance like sugar.
- The angle of rotation depends on the concentration of the solution, the path length, and the specific rotation of the substance.
- A sugar solution with a specific rotation of 66° rotates the plane of polarization by 5.5° when passed through a 10 cm long tube containing 48 cm³ of solution.
- The mass of sugar in the solution is 4 grams.
- The amount of optical rotation produced by a solution is directly proportional to the concentration of the solution and the path length.
- A 40 cm long tube containing a sugar solution produces an optical rotation of 16°. If the solution is diluted to one-third of its concentration, the optical rotation produced by a 60 cm long tube containing the diluted solution is 8°.
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Description
Explore the fascinating concepts of wave interference and thin film effects through this quiz. Understand the relationships between intensity ratios, amplitude ratios, and the influence of thin films on light reflection. Test your knowledge of these fundamental topics in physics!
