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Questions and Answers
Which of the following is the expansion of $(a + b)^2$?
Which of the following is the expansion of $(a + b)^2$?
- $a^2 - b^2$
- $a^2 - 2ab + b^2$
- $a^2 + b^2$
- $a^2 + 2ab + b^2$ (correct)
What is the result of $(a + b)(a - b)$?
What is the result of $(a + b)(a - b)$?
- $a^2 + b^2$
- $a^2 - 2ab + b^2$
- $a^2 - b^2$ (correct)
- $a^2 + 2ab + b^2$
What is the expansion of $(a - b)^2$?
What is the expansion of $(a - b)^2$?
- $a^2 - b^2$
- $a^2 + 2ab + b^2$
- $a^2 - 2ab + b^2$ (correct)
- $a^2 + b^2$
What is the simplified form of $(a + 1/a)(a - 1/a)$?
What is the simplified form of $(a + 1/a)(a - 1/a)$?
What is the expansion of $(x + a)(x + b)$?
What is the expansion of $(x + a)(x + b)$?
Expand $(a + b + c)^2$.
Expand $(a + b + c)^2$.
What is $(a + b)^3$ equal to?
What is $(a + b)^3$ equal to?
Which expression equals $a^3 + b^3$?
Which expression equals $a^3 + b^3$?
If $a + b + c = 0$, what is the value of $a^3 + b^3 + c^3$?
If $a + b + c = 0$, what is the value of $a^3 + b^3 + c^3$?
Flashcards
(a + b)² expansion
(a + b)² expansion
The square of a binomial (a + b) equals the square of 'a' plus twice the product of 'a' and 'b' plus the square of 'b': (a + b)² = a² + 2ab + b²
(a - b)² expansion
(a - b)² expansion
The square of a binomial (a - b) equals the square of 'a' minus twice the product of 'a' and 'b' plus the square of 'b': (a - b)² = a² - 2ab + b²
(a + b)(a - b) expansion
(a + b)(a - b) expansion
The product of (a + b) and (a - b) equals the difference of the squares of 'a' and 'b': (a + b)(a - b) = a² - b²
(a + b)² + (a - b)²
(a + b)² + (a - b)²
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(a + b)³ expansion
(a + b)³ expansion
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(a - b)³ expansion
(a - b)³ expansion
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(a + b)(a² - ab + b²)
(a + b)(a² - ab + b²)
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(a - b)(a² + ab + b²)
(a - b)(a² + ab + b²)
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a³ + b³ + c³ when a+b+c = 0
a³ + b³ + c³ when a+b+c = 0
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Study Notes
- Deals with the wave equation and methods to solve it
Physical Context of Wave Equation
- Common situations include:
- Small vibrations of a stretched string
- Acoustics
- Electromagnetism
Mathematical Context of Wave Equation
- Wave Equation involves a scalar function of space and time: $u(x,t)$
- Wave Equation: $\frac{\partial^2 u}{\partial t^2} = c^2 \frac{\partial^2 u}{\partial x^2} $
- $c$ represents the wave speed
- It is a linear, second-order PDE (Partial Differential Equation)
Solution Methods for Wave Equations
- Can be solved with:
- Direct method, using d'Alembert's formula
- Separation of variables, leading to Fourier series
d'Alembert's Formula Derivation
- Define new variables: $\xi = x + ct$ and $\eta = x - ct$
- Partial derivatives transform as follows: $\frac{\partial}{\partial x} = \frac{\partial}{\partial \xi} + \frac{\partial}{\partial \eta}$ and $\frac{\partial}{\partial t} = c\frac{\partial}{\partial \xi} - c\frac{\partial}{\partial \eta}$
- Second-order partial derivatives transform as follows: $\frac{\partial^2}{\partial x^2} = (\frac{\partial}{\partial \xi} + \frac{\partial}{\partial \eta})^2 = \frac{\partial^2}{\partial \xi^2} + 2\frac{\partial^2}{\partial \xi \partial \eta} + \frac{\partial^2}{\partial \eta^2}$
- Second-order partial derivatives transform as follows: $\frac{\partial^2}{\partial t^2} = c^2(\frac{\partial}{\partial \xi} - \frac{\partial}{\partial \eta})^2 = c^2(\frac{\partial^2}{\partial \xi^2} - 2\frac{\partial^2}{\partial \xi \partial \eta} + \frac{\partial^2}{\partial \eta^2})$
- Wave equation transforms to: $\frac{\partial^2 u}{\partial \xi \partial \eta} = 0$
- Integrating with respect to $\xi$ gives: $\frac{\partial u}{\partial \eta} = b(\eta)$
- Integrating with respect to $\eta$ gives: $u(\xi, \eta) = \int b(\eta) d\eta + A(\xi) = B(\eta) + A(\xi)$
- General solution: $u(x,t) = A(x + ct) + B(x - ct)$
- The general solution Consists of two arbitrary functions
- $A(x + ct)$ representing a wave moving to the left
- $B(x - ct)$ representing a wave moving to the right
Finding Arbitrary Functions
- Initial conditions are necessary:
- Initial displacement: $u(x,0) = f(x)$
- Initial velocity: $\frac{\partial u}{\partial t}(x,0) = g(x)$
- From the initial displacement: $u(x,0) = A(x) + B(x) = f(x)$
- The partial derivative with respect to time is: $\frac{\partial u}{\partial t}(x,t) = cA'(x + ct) - cB'(x - ct)$
- Initial velocity condition yields: $\frac{\partial u}{\partial t}(x,0) = cA'(x) - cB'(x) = g(x)$
- Rearranging, $A'(x) - B'(x) = \frac{1}{c}g(x)$
- Integrating with respect to x: $A(x) - B(x) = \frac{1}{c}\int_0^x g(s) ds + k$
- Solve the system of equations:
- $A(x) + B(x) = f(x)$
- $A(x) - B(x) = \frac{1}{c}\int_0^x g(s) ds + k$
- Solving for A(x) and B(x):
- $A(x) = \frac{1}{2}f(x) + \frac{1}{2c}\int_0^x g(s) ds + \frac{k}{2}$
- $B(x) = \frac{1}{2}f(x) - \frac{1}{2c}\int_0^x g(s) ds - \frac{k}{2}$
- Substituting back into the general solution $u(x,t) = A(x + ct) + B(x - ct)$
- Substituting functions A and B, yields: $= \frac{1}{2}[f(x + ct) + f(x - ct)] + \frac{1}{2c}\int_0^{x+ct} g(s) ds - \frac{1}{2c}\int_0^{x-ct} g(s) ds$
d'Alembert's Formula
- $u(x,t) = \frac{1}{2}[f(x + ct) + f(x - ct)] + \frac{1}{2c}\int_{x-ct}^{x+ct} g(s) ds$
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