Statistics Chapter 10 Flashcards

sample estimate ± multiplier X Standard error

1.96 which is rounded to 2

Sample size, confidence level, the natural variability among individual units.

<p>An interval of 2 values computed from sample data that is likely to include the unknown value of a population parameter.</p> Signup and view all the answers

<p>The likelihood that the procedure used will give an interval that contains the unknown value of the population parameter, most common is 95%.</p> Signup and view all the answers

<p>p̂ ± 2 X √p̂(1-p)/n</p> Signup and view all the answers

<p>The proportion of a population with a certain trait, opinion, or characteristic.</p> Signup and view all the answers

<p>1.65 for 90%, 1.96 for 95%, 2.33 for 98%, 2.58 for 99%</p> Signup and view all the answers

<p>The confidence interval is 53.46% to 58.46%.</p> Signup and view all the answers

<p>p̂ ± z*√p̂(1-p̂)/n</p> Signup and view all the answers

<p>The sample is randomly selected from the population, and both np̂ and n(1-p̂) should be at least 10 (some say at least 5).</p> Signup and view all the answers

<p>If the data can be considered to be representative with regard to the question(s) of interest.</p> Signup and view all the answers

<p>The sample proportion p̂ must reflect the frequency of the specific outcome in repeated trials, and both np̂ and n(1-p̂) should be at least 10 (some say at least 5).</p> Signup and view all the answers

<p>sample estimate ± margin of error</p> Signup and view all the answers

<p>margin of error = 2√p̂(1-p̂)/n</p> Signup and view all the answers

<p>s.e.(p̂₁ - p̂₂) = z*√(p̂₁(1-p̂₁)/n₁ + p̂₂(1-p̂₂)/n₂)</p> Signup and view all the answers