Solid Disk Torque Quiz

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Questions and Answers

What is the equation for the torque on each particle of the rotating disk?

  • $\tau = \frac{1}{2} \omega m r$
  • $\tau = \omega m r$
  • $\tau = \omega m r^2$ (correct)
  • $\tau = \frac{1}{2} \omega m r^2$

What is the expression for the net torque on the disk?

  • $\sum \tau = \sum (\omega m r)$
  • $\sum \tau = \frac{1}{2} \sum (\omega m r)$
  • $\sum \tau = \sum (\omega m r^2)$ (correct)
  • $\sum \tau = \frac{1}{2} \sum (\omega m r^2)$

What is the moment of inertia, I, of the whole body in terms of the masses and distances of the particles?

  • $I = \sum (m_i r_i^2)$ (correct)
  • $I = \frac{1}{2} \sum (m_i r_i)$
  • $I = \frac{1}{2} \sum (m_i r_i^2)$
  • $I = \sum (m_i r_i)$

Why is the angular acceleration, a, not involved in the sum of individual torques on all the particles?

<p>Because all particles have the same angular acceleration due to the rigid nature of the disk (A)</p> Signup and view all the answers

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