Solid Disk Torque Quiz

$\tau = \frac{1}{2} \omega m r$

$\tau = \omega m r$

$\tau = \omega m r^2$ (correct)

$\tau = \frac{1}{2} \omega m r^2$

$\sum \tau = \sum (\omega m r)$

$\sum \tau = \frac{1}{2} \sum (\omega m r)$

$\sum \tau = \sum (\omega m r^2)$ (correct)

$\sum \tau = \frac{1}{2} \sum (\omega m r^2)$

$I = \sum (m_i r_i^2)$ (correct)

$I = \frac{1}{2} \sum (m_i r_i)$

$I = \frac{1}{2} \sum (m_i r_i^2)$

$I = \sum (m_i r_i)$

<p>Because all particles have the same angular acceleration due to the rigid nature of the disk</p> Signup and view all the answers