Potential of a Uniformly Charged Disk
50 Questions
0 Views

Choose a study mode

Play Quiz
Study Flashcards
Spaced Repetition
Chat to Lesson

Podcast

Play an AI-generated podcast conversation about this lesson

Questions and Answers

What is the potential on the axis of a uniformly charged disk?

  • $2k\sigma\pi|z| [\sqrt{1 + \frac{R^2}{z^2}} - 1]$
  • $kQ/|z|^2$ (correct)
  • $kQ^2/|z|$
  • $2k\sigma\pi|z|$

For $|z| >> R$, which potential function should $V$ approach?

  • Infinity, due to the large distance.
  • Zero, since the distance is very large.
  • The potential function of a point charge $Q$ at the origin. (correct)
  • The potential function of a uniformly charged disk.

What approximation is used for $|z| >> R$?

  • Fourier transform
  • Binomial expansion (correct)
  • Taylor series
  • Laplace transform

What is the simplified potential $V(z)$ when $|z| >> R$?

<p>$\frac{kQ}{|z|}$ (D)</p> Signup and view all the answers

What does $Q$ represent in the context of the potential of a charged disk?

<p>The total charge on the disk. (C)</p> Signup and view all the answers

What is the purpose of using approximations like the binomial expansion when calculating electric potential?

<p>To simplify complex equations for easier calculation. (C)</p> Signup and view all the answers

In the equation $V(z) = 2k\sigma\pi|z| [\sqrt{1 + \frac{R^2}{z^2}} - 1]$, what does $\sigma$ represent?

<p>Charge density (A)</p> Signup and view all the answers

What happens to the electric potential as $|z|$ becomes much larger than $R$?

<p>It approaches the potential of a point charge. (D)</p> Signup and view all the answers

What is the area element $dA$ of the ring in Figure (8)?

<p>$dA = 2\pi a ,da$ (C)</p> Signup and view all the answers

What is the expression for the charge $dq$ of the ring?

<p>Both B and C (A)</p> Signup and view all the answers

What does $\sigma$ represent in the context of the charged ring?

<p>Surface charge density (A)</p> Signup and view all the answers

What is the formula for the surface charge density, $\sigma$, in terms of total charge $Q$ and radius $R$?

<p>$\sigma = \frac{Q}{\pi R^2}$ (A)</p> Signup and view all the answers

What is the potential $dV$ at point $P$ due to the charged ring?

<p>$dV = \frac{k dq}{\sqrt{z^2 + a^2}}$ (C)</p> Signup and view all the answers

Over what range of $a$ do we integrate in order to find the total potential due to the charged disk?

<p>From $a = 0$ to $a = R$ (A)</p> Signup and view all the answers

What is the form of the integral used to find the total potential $V$?

<p>$\int u^n du$ (C)</p> Signup and view all the answers

What are the limits of integration for $u$ when integrating with respect to $u$?

<p>From $u = z^2$ to $u = z^2 + R^2$ (A)</p> Signup and view all the answers

If a charge distribution possesses spherical symmetry, the electric field is a function of what?

<p>The radial distance $r$ (A)</p> Signup and view all the answers

What is the formula to obtain the electric field $\vec{E}$ if $V(r)$ is known?

<p>$\vec{E} = - \frac{dV}{dr} \hat{r}$ (C)</p> Signup and view all the answers

What is the electric potential $V(r)$ due to a point charge $q$?

<p>$V(r) = \frac{1}{4 \pi \epsilon_0} \frac{q}{r}$ (C)</p> Signup and view all the answers

What is the electric field $\vec{E}(r)$ due to a point charge q?

<p>$\vec{E}(r) = \frac{1}{4 \pi \epsilon_0} \frac{q}{r^2} \hat{r}$ (A)</p> Signup and view all the answers

If the electric potential is $V(x) = 100 , V - (25 , V/m)x$, what is the $x$-component of the electric field, $E_x$?

<p>$E_x = 25 , V/m$ (A)</p> Signup and view all the answers

If the electric potential does not vary with $y$ or $z$, what are the values of $E_y$ and $E_z$?

<p>$E_y = E_z = 0$ (A)</p> Signup and view all the answers

What is $dV$ equal to in a spherically symmetrical charge distribution?

<p>$dV = -E_r dr$ (C)</p> Signup and view all the answers

The electric field, $\vec{E}$, is related to the potential $V$ by which mathematical operation?

<p>The derivative (A)</p> Signup and view all the answers

What does $dV$ represent in the equation $dV = -\vec{E} \cdot d\vec{s}$?

<p>A small change in electric potential (C)</p> Signup and view all the answers

In Cartesian coordinates, what is the vector form of the differential displacement $d\vec{s}$?

<p>$dx \hat{i} + dy \hat{j} + dz \hat{k}$ (C)</p> Signup and view all the answers

Given $V = V(x, y, z)$, which expression represents the total differential $dV$?

<p>$\frac{\partial V}{\partial x} dx + \frac{\partial V}{\partial y} dy + \frac{\partial V}{\partial z} dz$ (B)</p> Signup and view all the answers

What does the negative sign in the equation $\vec{E} = -(\frac{\partial V}{\partial x} \hat{i} + \frac{\partial V}{\partial y} \hat{j} + \frac{\partial V}{\partial z} \hat{k})$ indicate?

<p>The electric field points in the direction of decreasing electric potential. (B)</p> Signup and view all the answers

What is the relationship between the electric field $\vec{E}$ and the electric potential $V$?

<p>$\vec{E}$ is the negative gradient of $V$. (B)</p> Signup and view all the answers

In the equation $dV = E_x dx + E_y dy + E_z dz$, what does $E_x$ represent?

<p>The electric field component in the x-direction (D)</p> Signup and view all the answers

What does $\frac{\partial V}{\partial x}$ represent?

<p>The rate of change of electric potential with respect to x (D)</p> Signup and view all the answers

If the electric potential $V$ increases as a positive charge moves along the x-direction, what can be said about the x-component of the electric field, $E_x$?

<p>$E_x$ is negative (A)</p> Signup and view all the answers

What is the value of the potential $V$ everywhere on an equipotential surface?

<p>Constant (A)</p> Signup and view all the answers

If a test charge on an equipotential surface is given a small displacement $dl$ parallel to the surface, what is the value of $dV$?

<p>0 (C)</p> Signup and view all the answers

What is the relationship between electric field lines and equipotential surfaces?

<p>Normal (C)</p> Signup and view all the answers

For a point charge, what shape do equipotential surfaces form?

<p>Concentric spheres (D)</p> Signup and view all the answers

For a constant electric field, what shape do equipotential surfaces form?

<p>Planes (C)</p> Signup and view all the answers

What is the direction of the electric field with respect to equipotential surfaces?

<p>From higher to lower potential (D)</p> Signup and view all the answers

What does $E \cdot dl = 0$ imply when $dl$ is parallel to the surface?

<p>The electric field is normal to the surface (C)</p> Signup and view all the answers

Which of the following is true about equipotential surfaces?

<p>The potential is same everywhere on the surface (D)</p> Signup and view all the answers

What does $V(x)$ represent in the context of the electric potential due to a charged ring?

<p>The electric potential at a point P on the ring axis. (A)</p> Signup and view all the answers

What component(s) of the electric field exists along the symmetry axis of a charged ring?

<p>Only the x-component (D)</p> Signup and view all the answers

How is the electric field component $E_x$ related to the electric potential $V$?

<p>$E_x = -\frac{\partial V}{\partial x}$ (C)</p> Signup and view all the answers

In the equation for $E_x(x)$ for a charged ring, what does 'a' represent?

<p>The radius of the ring. (A)</p> Signup and view all the answers

If the electric potential $V(x, y, z) = A x^2 y^2 + B x y z$, how is $E_x$ calculated?

<p>$E_x = -\frac{\partial}{\partial x}(A x^2 y^2 + B x y z)$ (B)</p> Signup and view all the answers

Given $V(x, y, z) = A x^2 y^2 + B x y z$, what is the expression for $E_z$?

<p>$E_z = -B x y$ (D)</p> Signup and view all the answers

What are curves characterized by constant $V(x, y)$ called?

<p>Equipotential curves (D)</p> Signup and view all the answers

What does $\epsilon_0$ represent in the equation for electric potential?

<p>Permittivity of free space (D)</p> Signup and view all the answers

What is the electric field a measure of?

<p>The force per unit positive charge (C)</p> Signup and view all the answers

What is the relationship between electric potential and electric field?

<p>Electric field is the negative gradient of the electric potential. (D)</p> Signup and view all the answers

Flashcards

V(z) for a charged disk

Potential on the axis of a uniformly charged disk.

V(z) when |z| >> R

For distances much larger than the disk's radius, potential approaches that of a point charge.

Binomial expansion

Approximation used when |z| is much larger than R.

Approximated V(z) for |z| >> R

k(σπR^2) / |z|

Signup and view all the flashcards

σπR^2

σπR^2 represents the total charge on the disk.

Signup and view all the flashcards

k

Electric constant. Approximately 8.99 x 10^9 N⋅m^2/C^2

Signup and view all the flashcards

Electric Field from Potential

The relationship to calculate the electric field from the electric potential.

Signup and view all the flashcards

Eqn. (1)

Relates to the electric field and potential.

Signup and view all the flashcards

dA (Disk Area)

Infinitesimal area element on the disk.

Signup and view all the flashcards

Surface Charge Density (σ)

Charge per unit area on the disk's surface.

Signup and view all the flashcards

Total Potential V

Electric potential due to entire charged disk, integrated from center to edge.

Signup and view all the flashcards

V(z)

The potential (V) depends on the distance (z) from the disk.

Signup and view all the flashcards

kdq / √(z² + a²)

Contribution to potential from a ring of radius 'a'.

Signup and view all the flashcards

Potential of charged disk

V(z) = 2kσπ [√(z² + R²) − √z²]

Signup and view all the flashcards

dV = -E · ds

The change in electric potential (dV) equals the negative dot product of the electric field (E) and the displacement vector (ds).

Signup and view all the flashcards

E in Cartesian Coordinates

It expresses the electric field (E) in terms of its Cartesian components (Ex, Ey, Ez) along the x, y, and z axes.

Signup and view all the flashcards

ds in Cartesian Coordinates

It represents an infinitesimal displacement vector (ds) in Cartesian coordinates, broken down into its components along the x, y, and z axes.

Signup and view all the flashcards

dV in Cartesian coordinates

The differential change in electric potential (dV) is the sum of the products of the electric field components and their corresponding displacement components in Cartesian coordinates.

Signup and view all the flashcards

dV and Partial Derivatives

The total change in electric potential (dV) is related to the partial derivatives of the potential (V) with respect to each spatial coordinate (x, y, z).

Signup and view all the flashcards

Electric Field Components

The components of the electric field are the negative partial derivatives of the electric potential with respect to the corresponding spatial coordinates.

Signup and view all the flashcards

E as Gradient of V

Expresses the electric field (E) as the negative gradient of the electric potential (V), in vector form.

Signup and view all the flashcards

Negative Sign Significance

Electric field points in the direction of decreasing electric potential. A positive charge moves in the direction of the electric field, towards lower potential.

Signup and view all the flashcards

Spherical Symmetry & Electric Field

For spherically symmetric charge distributions, the electric field depends only on the radial distance.

Signup and view all the flashcards

dV in Spherical Symmetry

In spherical symmetry, the potential difference is related to the radial electric field by dV = −Er dr.

Signup and view all the flashcards

Electric Field from Potential (Spherical)

The electric field is the negative gradient of the electric potential: 𝑬 = −(dV/dr) 𝒓̂.

Signup and view all the flashcards

Potential of a Point Charge

The electric potential due to a point charge q at distance r.

Signup and view all the flashcards

Electric Field of a Point Charge (from V)

The electric field due to a point charge q, derived from the potential.

Signup and view all the flashcards

Ex from V(x)

The electric field component along the x-axis is the negative derivative of the potential with respect to x.

Signup and view all the flashcards

Potential Independent of y, z

If the electric potential does not vary with y or z, then Ey = Ez = 0.

Signup and view all the flashcards

E Field from V(x) Example

For a potential function V(x) = 100 V - (25 V/m)x, the x-component of the electric field is constant: Ex = 25 V/m.

Signup and view all the flashcards

Electric Field (Ex) Formula

The x-component of the electric field (Ex) is the negative rate of change of the electric potential (V) with respect to x.

Signup and view all the flashcards

Finding Ex

To find Ex, take the negative partial derivative of V(x, y, z) with respect to x.

Signup and view all the flashcards

Finding Ey

To find Ey, take the negative partial derivative of V(x, y, z) with respect to y.

Signup and view all the flashcards

Finding Ez

To find Ez, take the negative partial derivative of V(x, y, z) with respect to z.

Signup and view all the flashcards

Equipotential Surface

A surface where the electric potential (V) is constant at every point.

Signup and view all the flashcards

Equipotential Curves

Curves (in 2D) where the electric potential V(x, y) remains constant.

Signup and view all the flashcards

Electric Field Direction

The electric field points in the direction of the greatest decrease of electric potential.

Signup and view all the flashcards

Electric Field of a Ring

The electric field, Ex(x), due to a charged ring along its axis.

Signup and view all the flashcards

Electric Potential of a Ring

The formula to calculate electric potential (V) at a point P on the axis of a charged ring

Signup and view all the flashcards

Electric Field Vector

The electric field is a vector sum of its components in each direction.

Signup and view all the flashcards

dV on Equipotential Surface

The change in electric potential (dV) is zero when moving along an equipotential surface.

Signup and view all the flashcards

E-field and Equipotential

Electric field lines are always perpendicular (normal) to equipotential surfaces where they intersect.

Signup and view all the flashcards

Equipotential of Point Charge

For a point charge, equipotential surfaces are concentric spheres centered on the charge.

Signup and view all the flashcards

Equipotential in Uniform E-field

For a constant electric field, equipotential surfaces are planes perpendicular to the field lines.

Signup and view all the flashcards

Direction of E-field

Electric field lines point from areas of higher electric potential to areas of lower electric potentials.

Signup and view all the flashcards

Conductor Potential

A conductor in electrostatic equilibrium has a constant potential throughout its volume.

Signup and view all the flashcards

Force and Equipotential

Equipotential surfaces are always perpendicular to the electric field lines, showing the direction of the electrical force.

Signup and view all the flashcards

Study Notes

  • The potential at a point P with continuous charge distribution is the sum of individual differential charge elements dq contributions
  • With infinity as a zero-potential reference the electric potential at P due to dq is dV = (1 / 4πε₀) * (dq / r)
  • The total potential over all differential elements is then V = ∫dV = ∫(1 / 4πε₀) * (dq / r)

Electric Potential on the Axis of a Charged Ring

  • For a uniformly charged ring of radius a and charge Q in the z = 0 plane, centered at the origin, the distance from a charge element dq to field point P on the ring's axis is r = √(z² + a²)
  • The potential at a point due to the ring is obtained by integrating: V = ∫(k * dq / r) = (k / r) ∫dq = kQ / r = kQ / √(z² + a²)
  • When |z| is much greater than a, the potential approaches kQ / |z|, similar to a point charge Q at the origin

Electric potential V for a Charged Disk

  • Potential on the axis of a disk with radius R and total charge Q distributed uniformly is found by treating the disk as rings
  • A ring with radius a and thickness da in Fig. (8) has an area of dA = 2πa da
  • The charge of the ring is dq = σdA = σ2πa da, where σ = Q / πR² (surface charge density)
  • Potential at point P due to ring charge is dV = kdq / √(z² + a²)
  • Integrate from a = 0 to a = R to find the total potential V = ∫₀ᑅ (kσ2πa da) / √(z² + a²) = kσπ[√(z² + R²) - |z|]
  • Rearranged, V(z) = 2kσπ|z| * [√(1 + R² / z²) - 1]
  • The potential on the axis of a uniformly charged disk is V(z) = 2kσπ|z| * [√(1 + R² / z²) - 1]

Electric field from Electric Potential

  • The relation between E and V for two points with small distance ds apart is dV = -E · ds
  • In Cartesian coordinates: E = Exî + Eyĵ + Ezk and ds = dx î + dy ĵ + dz k
  • Therefore: dV = -(Exî + Eyĵ + Ezk) · (dx î + dy ĵ + dz k) which simplifies to dV = Exdx + Eydy + Ezdz
  • Also: dV = (∂V/∂x)dx + (∂V/∂y)dy + (∂V/∂z)dz
  • Which means: Ex = -∂V/∂x, Ey = -∂V/∂y, Ez = -∂V/∂z
  • The electric field can be expressed: E = Exî + Eyĵ + Ezk = -(∂V/∂x)î - (∂V/∂y)ĵ - (∂V/∂z)k
  • Mathematically think of Electric Field as the negative gradient of the electric potential V
  • Physically, when V increases as a positive charge moves along x, there is a non-vanishing component of E in the x opposite direction (-Ex ≠ 0)
  • For charge distribution with spherical symmetry, E is a function of radial distance r: E = Eᵣr̂
  • In this case, dV = -Eᵣdr, and if V(r) known, E = Eᵣr̂ = -(dV/dr)r̂
  • Example: electric potential due to point charge q is V(r) = 1/(4πε₀) * (q/r), and E = 1/(4πε₀) * (q/r²)r̂

Examples

  • For a potential function V(x) = 100 V - (25 V/m)x, because V only depends on x, Ex = -dV(x)/dx = 25 V/m, and Ey = Ez = 0
  • For a ring with radius a and charge Q, potential at point P on the ring axis a distance x is V(x) = 1/(4πε₀) * (Q/√(x² + a²))
    • The x-component of the electric field is Ex = Qx / [4πε₀(x² + a²)³/²]
  • Electric potential due to a charge distribution can be written as V(x, y, z) = Ax²y² + Bxyz where A and B are constants
    • Electric field components are found by taking partial derivatives: Ex = -(2Axy² + Byz), Ey = -(2Ax²y + Bxz) and Ez = -Bxy
    • The electric field: E(x, y, z) = -(2Axy² - Byz)î - (2Ax²y + Bxz)ĵ - (Bxy)k

Equipotential Surfaces and Field Lines

  • A system in 2D with electric potential V(x, y), equipotential curves have constant V(x, y)
  • In 3D, equipotential surfaces are described by V(x, y, z) = constant
  • The potential V is constant on an equipotential surface, and for a small displacement dl parallel: dV = -E · dl = 0
  • E must be zero or perpendicular to every dl parallel to the surface, meaning E is normal to the surface
  • Electric field lines are normal to equipotential ones they intersect
  • The field lines in the plane of the charges are represented by red lines, intersections by blue lines
  • Equipotential surfaces are 3D, at each crossing of equipotential/field line, the two are perpendicular

Equipotential properties

  • Electric field lines are perpendicular pointing from high to low potentials
  • Equipotential surfaces from point charge form concentric spheres; constant electric field forms planes perpendicular
  • The tangential component of Electric field along the equipotential surface is zero, no work is done while moving charge
  • No work needed for a particle along equipotential surface

Studying That Suits You

Use AI to generate personalized quizzes and flashcards to suit your learning preferences.

Quiz Team

Description

Explores the electric potential on the axis of a uniformly charged disk, focusing on approximations for distances much larger than the disk's radius. It covers the potential function's behavior, the use of binomial expansion, and the meanings of key variables like surface charge density.

More Like This

Use Quizgecko on...
Browser
Browser