Physics 1120: 1D Kinematics Solutions
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Questions and Answers

What equation was substituted into both sides of equation (1) to solve the problem?

  • Δy = v0t - ½gt2 (correct)
  • Δy = v0t + ½gt2
  • Δy = v0t + ½gt2
  • Δy = v0t - ½gt2 + θ
  • What is the correct rearranged form of the equation (v01 - v02 - 1.15g)t2 = -(1.15v01 - 0.66125g)?

  • t2 = (1.15v01 + 0.66125g) / (v02 - v01 + 1.15g)
  • t2 = -(1.15v01 - 0.66125g) / (v01 - v02 - 1.15g)
  • t2 = (1.15v01 - 0.66125g) / (v02 - v01 - 1.15g) (correct)
  • t2 = -(1.15v01 + 0.66125g) / (v01 - v02 - 1.15g)
  • What is the value of t2 obtained after solving the equations in the given text?

  • 2.8997 s
  • 3.1997 s
  • 0.2997 s
  • 1.2997 s (correct)
  • What is the final height h when the balls collide?

    <p>7.31 m</p> Signup and view all the answers

    Which quantity represents the unknowns in the problem described in the text?

    <p>Δy and t</p> Signup and view all the answers

    What equation was used to replace t1 in the solution process?

    <p>t1 = t2 + 1.15</p> Signup and view all the answers

    How many steps were involved in determining the final time values t1 and t2?

    <p>2</p> Signup and view all the answers

    Which equation was used to calculate the final height h in the problem?

    <p>h = v01t1 - ½g(t1)2</p> Signup and view all the answers

    What value is used for the acceleration in the problem described in the text?

    <p>g</p> Signup and view all the answers

    What is the correct term on the right side of the equation (v01 - v02 - 1.15g)t2 = -(1.15v01 - 0.66125g) after rearrangement?

    <p>-(1.15v01 - 0.66125g)</p> Signup and view all the answers

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