Physics 1120: 1D Kinematics Solutions

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10 Questions

What equation was substituted into both sides of equation (1) to solve the problem?

Δy = v0t - ½gt2

What is the correct rearranged form of the equation (v01 - v02 - 1.15g)t2 = -(1.15v01 - 0.66125g)?

t2 = (1.15v01 - 0.66125g) / (v02 - v01 - 1.15g)

What is the value of t2 obtained after solving the equations in the given text?

1.2997 s

What is the final height h when the balls collide?

7.31 m

Which quantity represents the unknowns in the problem described in the text?

Δy and t

What equation was used to replace t1 in the solution process?

t1 = t2 + 1.15

How many steps were involved in determining the final time values t1 and t2?

2

Which equation was used to calculate the final height h in the problem?

h = v01t1 - ½g(t1)2

What value is used for the acceleration in the problem described in the text?

g

What is the correct term on the right side of the equation (v01 - v02 - 1.15g)t2 = -(1.15v01 - 0.66125g) after rearrangement?

-(1.15v01 - 0.66125g)

This quiz provides solutions for 1D kinematics problems in Physics 1120. It covers topics such as acceleration, average velocity, and time calculations. Practice identifying points where velocity is zero and sketching diagrams for better visualization.

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