Physics 1120: 1D Kinematics Solutions
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Questions and Answers

What equation was substituted into both sides of equation (1) to solve the problem?

  • Δy = v0t - ½gt2 (correct)
  • Δy = v0t + ½gt2
  • Δy = v0t + ½gt2
  • Δy = v0t - ½gt2 + θ

What is the correct rearranged form of the equation (v01 - v02 - 1.15g)t2 = -(1.15v01 - 0.66125g)?

  • t2 = (1.15v01 + 0.66125g) / (v02 - v01 + 1.15g)
  • t2 = -(1.15v01 - 0.66125g) / (v01 - v02 - 1.15g)
  • t2 = (1.15v01 - 0.66125g) / (v02 - v01 - 1.15g) (correct)
  • t2 = -(1.15v01 + 0.66125g) / (v01 - v02 - 1.15g)

What is the value of t2 obtained after solving the equations in the given text?

  • 2.8997 s
  • 3.1997 s
  • 0.2997 s
  • 1.2997 s (correct)

What is the final height h when the balls collide?

<p>7.31 m (B)</p> Signup and view all the answers

Which quantity represents the unknowns in the problem described in the text?

<p>Δy and t (A)</p> Signup and view all the answers

What equation was used to replace t1 in the solution process?

<p>t1 = t2 + 1.15 (D)</p> Signup and view all the answers

How many steps were involved in determining the final time values t1 and t2?

<p>2 (B)</p> Signup and view all the answers

Which equation was used to calculate the final height h in the problem?

<p>h = v01t1 - ½g(t1)2 (B)</p> Signup and view all the answers

What value is used for the acceleration in the problem described in the text?

<p>g (C)</p> Signup and view all the answers

What is the correct term on the right side of the equation (v01 - v02 - 1.15g)t2 = -(1.15v01 - 0.66125g) after rearrangement?

<p>-(1.15v01 - 0.66125g) (C)</p> Signup and view all the answers

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