Movement of Charged Molecules

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Questions and Answers

When a charged molecule is placed in an electric field, a force acts upon it due to the electric field's ______ and the molecule's charge.

strength

The force experienced by a charged molecule in an electric field is given by the equation f=-q(______/d), where q is the net charge of the molecule.

∆E

According to Stokes' Law, the frictional force (F) acting on a molecule suspended in solution is given by F = 6Ï€______rv, where r is the molecule's radius and v is its velocity.

n

Stokes' Law indicates that the frictional force on a molecule is directly proportional to the solution's viscosity, the molecule's radius, and the ______ at which the molecule migrates.

<p>velocity</p> Signup and view all the answers

When the force generated by the electric field balances the frictional force, the ______ of the molecule can be derived.

<p>velocity</p> Signup and view all the answers

The derived velocity of the molecule, considering both electric and frictional forces, is given by V=q∆E/6π______rvd.

<p>n</p> Signup and view all the answers

The velocity of a molecule is directly proportional to its charge and the electric field strength, but ______ proportional to the particle size.

<p>inversely</p> Signup and view all the answers

The relationship V=q∆E/6πnrvd illustrates that a higher ______ of the solution will result in a lower migration velocity of the molecule.

<p>viscosity</p> Signup and view all the answers

In the velocity equation V=q∆E/6πnrvd, 'd' represents the ______ between the electrodes.

<p>distance</p> Signup and view all the answers

Balancing the electrical and frictional forces on a molecule allows us to understand its ______ in a solution, which is influenced by both molecular properties and the solution environment.

<p>migration</p> Signup and view all the answers

Flashcards

Force on a Charged Molecule in Electric Field

The force (F) experienced by a charged molecule in an electric field is directly proportional to the net charge (q) of the molecule and the potential difference (∆E) across two electrodes, and inversely proportional to the distance (d) between the electrodes. F = q(∆E/d).

Stokes' Law of Frictional Force

The frictional force (F) on a molecule moving in a solution. It's proportional to the viscosity (n) of the solution, the radius (r) of the molecule, and the velocity (v) at which the molecule migrates. F = 6Ï€nrv.

Molecule Migration Velocity

The molecule's migration velocity when the electrical force balances the frictional force. It’s directly proportional to the charge (q) and electric field strength (∆E), and inversely proportional to particle size (r), viscosity (n), and distance between electrodes (d). V=q∆E/6πnrvd

Study Notes

  • When a charged molecule is in an electric field, a force acts upon it, based on the electric field's strength and the molecule's charge.
  • The force is given by: f=- q (∆E/d)
  • q = net charge of the molecule.
  • ∆E = potential difference across two electrodes.
  • d = distance between the electrodes.
  • When a molecule is suspended in a solution, the interaction between the molecule and the solution influences its movement.
  • According to Stokes' Law, the frictional force (F) is: F = 6Ï€nrv
  • Where n = viscosity of the solution.
  • r = radius of the molecule.
  • v = velocity at which the molecule migrates.
  • Frictional force opposes the force generated by the electric field.
  • When these forces balance, the molecule's velocity is: V=q∆E/6Ï€nrvd
  • The molecule's velocity is directly proportional to the charge and field strength.
  • The molecule's velocity is inversely proportional to the particle size and the viscosity of the solution.

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