Mathematics Chapter on Averages and Profit
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Questions and Answers

What is the average of the first 57 natural numbers?

  • 25.5
  • 40.5 (correct)
  • 36.5
  • 28.5
  • What price should the item have been sold for to earn a profit of 20% after losing 30% when sold for Rs. 8442?

  • Rs. 12806 (correct)
  • Rs. 14472
  • Rs. 15686 (correct)
  • Rs. 13472
  • What is the volume of metal used for a spherical shell with an outer radius of 13 cm and thickness of 3 cm? Use $ rac{22}{7}$ for $ ext{pi}$.

  • 3191 $cm^{3}$
  • 3024 $cm^{3}$ (correct)
  • 3016 $cm^{3}$
  • 1197 $cm^{3}$
  • If an item worth Rs. 10000 is sold for Rs. 8442, what is the loss percentage?

    <p>15.8%</p> Signup and view all the answers

    What will be the additional volume of a spherical shell if the thickness is increased to 5 cm while keeping the outer radius at 13 cm?

    <p>2895 $cm^{3}$</p> Signup and view all the answers

    Study Notes

    Finding the Average

    • The average of the first 57 natural numbers can be calculated by using the formula: (n+1)/2 , where n is the number of natural numbers.
    • In this case, n is 57, so the average would be (57+1)/2 = 29.

    Calculating Profit and Loss

    • The selling price of the item is Rs. 8442, and the loss suffered is 30%.
    • To calculate the cost price, we can use the formula: Cost Price = Selling Price / (1 - Loss Percentage/100)
    • The cost price would be Rs. 8442 / (1-30/100) = Rs. 12060
    • To earn a profit of 20%, the selling price should be: Selling Price = Cost Price * (1 + Profit Percentage/100)
    • The required selling price would be Rs. 12060 * (1+20/100) = Rs. 14472.

    Calculating Volume of a Spherical Shell

    • The outer radius of the shell is 13 cm, and the thickness is 3 cm.
    • This means the inner radius of the shell is 13 cm - 3 cm = 10 cm.
    • The volume of the metal used can be calculated by finding the difference between the volume of the outer sphere and the volume of the inner sphere.
    • The formula for the volume of a sphere is (4/3)πr³, where r is the radius.
    • The volume of the outer sphere is (4/3)π(13)³ = 9203 cm³
    • The volume of the inner sphere is (4/3)π(10)³ = 4190 cm³
    • The volume of the metal used is 9203 cm³ - 4190 cm³ = 5013 cm³

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    Description

    This quiz covers key concepts related to calculating averages, profit and loss, and the volume of a spherical shell. It includes essential formulas and calculations, providing a practical application of mathematical principles. Test your understanding and calculation skills through various problems.

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