Lobry de Bruyn-von Ekenstein Transformation
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Questions and Answers

Why are sugars in alkaline solution considered powerful reducing agents?

  • Due to the presence of free aldehyde or keto groups
  • Due to the formation of enediol intermediates
  • Due to their ability to reduce cupric ions (Cu²⁺) to cuprous ions (Cu⁺)
  • All of the above (correct)
  • What is the common intermediate formed in the Lobry de Bruyn-von Ekenstein transformation for D-glucose, D-fructose, and D-mannose?

  • Ketone
  • Carboxylic acid
  • Enediol (correct)
  • Aldehyde
  • What is the product formed when the aldehyde group of glucose is oxidized?

  • Glucuronic acid
  • Glucaric acid
  • Gluconic acid (correct)
  • Glucose-6-phosphate
  • Which of the following tests is NOT mentioned in the text for identifying the reducing action of sugars?

    <p>Tollens' test</p> Signup and view all the answers

    Which of the following statements is TRUE regarding the reducing property of sugars?

    <p>It is a general reaction and cannot be used for specific identification of sugars.</p> Signup and view all the answers

    In the reaction showing the reduction of cupric ions (Cu²⁺) by sugars, what is the product formed?

    <p>Both cuprous hydroxide and cuprous oxide are formed</p> Signup and view all the answers

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