Limit Calculus Quiz
16 Questions
11 Views

Limit Calculus Quiz

Created by
@JudiciousStarfish

Podcast

Play an AI-generated podcast conversation about this lesson

Questions and Answers

What can be concluded about the degrees of the numerator and denominator?

  • The degree of the denominator is less than the degree of the numerator.
  • The degree of the denominator is greater than the degree of the numerator. (correct)
  • The degree of the denominator is equal to the degree of the numerator.
  • The degrees of the numerator and denominator cannot be compared.
  • What is the limit of the sequence $u_n = \frac{n}{n^2 + 1}$ as $n$ approaches infinity?

  • 1
  • 0 (correct)
  • Infinity
  • Undefined
  • Using the properties of the cosine function, what is the range of $\cos\frac{\pi}{n}$?

  • All real numbers
  • 0 to 1
  • -1 to 1 (correct)
  • -1 to 0
  • Given the inequality $- \frac{n}{n^2 + 1} \leq v_n \leq \frac{n}{n^2 + 1}$, what can be inferred about $v_n$ as $n$ approaches infinity?

    <p>It approaches 0.</p> Signup and view all the answers

    Which statement accurately represents the limit behavior of $\lim_{n \to \infty} u_n = \lim_{n \to \infty} \frac{\frac{1}{n}}{1 + \frac{1}{n^2}}$?

    <p>The limit exists and equals 0.</p> Signup and view all the answers

    How does the sequence $u_n$ behave as $n$ goes to infinity?

    <p>It approaches 0.</p> Signup and view all the answers

    What is the implication of the inequality $-1 \leq \cos\frac{\pi}{n} \leq 1$ in the context of sequences?

    <p>The sequence remains bounded within [-1, 1].</p> Signup and view all the answers

    What happens to the term $\frac{n}{n^2 + 1}$ as $n$ tends to infinity?

    <p>It tends to 0.</p> Signup and view all the answers

    What is the limit of $v_n$ as $n$ approaches infinity?

    <p>0</p> Signup and view all the answers

    Which term in the Taylor series expansion for $\cos x$ contributes to the limit calculation as $x$ approaches 0?

    <p>$-\frac{x^2}{2}$</p> Signup and view all the answers

    In the limit expression for $\lim_{n \rightarrow \infty} v_n$, what does the term $\frac{\pi^2}{2 n^3}$ represent?

    <p>A negligible adjustment to the limit</p> Signup and view all the answers

    What substitution is made for $x$ in the expression $\cos\frac{\pi}{n}$ when applying Taylor expansion?

    <p>$\frac{\pi}{n}$</p> Signup and view all the answers

    Which of the following represents the approximation for large $n$ in the calculation of $\frac{n}{n^2 + 1}$?

    <p>$\frac{1}{n}$</p> Signup and view all the answers

    What does $o\left( \frac{1}{n^2} \right)$ indicate in the context of limit evaluation?

    <p>It represents a term that vanishes</p> Signup and view all the answers

    Which of the following correctly identifies the behavior of $v_n$ as $n$ increases indefinitely?

    <p>It approaches zero</p> Signup and view all the answers

    What is the main consequence of using Taylor series expansion for evaluating limits involving trigonometric functions?

    <p>It allows for approximating the function near a point</p> Signup and view all the answers

    Study Notes

    Limit Analysis

    • The degree of the numerator ( n ) is 1, and the degree of the denominator ( n^2 + 1 ) is 2.
    • The degree of the denominator is greater than that of the numerator.
    • As ( n ) approaches infinity, both ( \frac{n}{n^2 + 1} ) and ( \frac{1}{n} ) converge to 0.
    • Therefore, ( \lim_{n \to \infty} u_n = 0 ).

    Inequality Method

    • The property of cosine states ( -1 \leq \cos\left( \frac{\pi}{n} \right) \leq 1 ).
    • ( v_n ) is bounded by the inequalities ( -\frac{n}{n^2 + 1} \leq v_n \leq \frac{n}{n^2 + 1} ).
    • As ( n ) approaches infinity, ( \lim_{n \to \infty} \frac{n}{n^2 + 1} = 0 ).
    • Thus, ( \lim_{n \to \infty} v_n = 0 ).

    Taylor Expansion Approach

    • The Taylor series expansion of cosine around 0 gives ( \cos x = 1 - \frac{x^2}{2} + o(x^2) ).
    • When substituting ( x = \frac{\pi}{n} ), it gives ( \cos\left( \frac{\pi}{n} \right) = 1 - \frac{\left( \frac{\pi}{n} \right)^2}{2} + o\left( \frac{1}{n^2} \right) ).
    • The expression for ( v_n ) derives as ( v_n = \frac{n\left( 1 - \frac{\pi^2}{2n^2} + o\left( \frac{1}{n^2} \right) \right)}{n^2 + 1} ).
    • Simplification leads to ( v_n \approx \frac{1}{n} - \frac{\pi^2}{2n^3} + o\left( \frac{1}{n^3} \right) ).
    • Consequently, ( \lim_{n \to \infty} v_n = 0 ).

    Key Concepts

    • Understanding limits of sequences when comparing degrees of numerators and denominators.
    • Application of inequalities to establish bounds on sequences.
    • Utilizing Taylor series for approximating function behavior near specific points of interest.

    Studying That Suits You

    Use AI to generate personalized quizzes and flashcards to suit your learning preferences.

    Quiz Team

    Related Documents

    Limit Calculation PDF

    Description

    Test your understanding of limits in calculus with this quiz. Focus on the degrees of numerators and denominators to determine their relationship. Can you identify whether the degree of the numerator is greater, equal, or less than that of the denominator?

    More Like This

    Basic Limit Laws in Calculus
    4 questions
    Calculus Limit Problem
    5 questions

    Calculus Limit Problem

    PalatialMulberryTree9169 avatar
    PalatialMulberryTree9169
    Limit Concepts in Calculus
    5 questions
    Use Quizgecko on...
    Browser
    Browser