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Geometry Problem: Perpendicular Bisector of a Line Segment

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Geometry Problem: Perpendicular Bisector of a Line Segment

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Questions and Answers

What is the condition for two triangles to be congruent according to the SAS rule?

Two sides and one angle not included between them

Two sides and one angle included between them (correct)

Two angles and one side included between them

Three sides and no angle

If a point P lies on the perpendicular bisector of a line segment AB, what can be concluded?

P is equidistant from A and B (correct)

P is farther from A than B

P is not equidistant from A and B

P is closer to A than B

What is the condition for a point to be the mid-point of a line segment?

The point is the intersection of the line segment with another line

The point is closer to one end of the line segment

The point is farther from one end of the line segment

The point is equidistant from the ends of the line segment (correct)

What is the relationship between Δ PCA and Δ PCB in the given figure?

Δ PCA is congruent to Δ PCB Signup and view all the answers

What is the conclusion that can be drawn about two triangles with two angles and one side included between them?

The two triangles are not congruent Signup and view all the answers

What is the purpose of constructing two triangles with two angles and one side included between them?

To observe the importance of equal angles in the SAS rule Signup and view all the answers

What is the result of cutting out two triangles and placing one on the other in the given figure?

The two triangles completely overlap Signup and view all the answers

What is the relationship between the distances PA and PB in the given figure?

PA is equal to PB Signup and view all the answers

What is the condition for a line to be the perpendicular bisector of a line segment?

The line passes through the mid-point of the line segment Signup and view all the answers

What is the conclusion that can be drawn about two triangles with two sides and one angle not included between them?