Gauss's Law and Electric Fields Quiz

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Questions and Answers

What assumption is crucial when applying Gauss's law to determine the electric field around the central portions of a long wire?

  • The wire must be made of a specific material
  • The wire must be short
  • The wire must have a finite length
  • The wire must be infinitely long (correct)

In Gauss's law, why are end effects ignored when considering the electric field around the central portions of a long wire?

  • To simplify calculations (correct)
  • To account for the wire's ends
  • To complicate the analysis
  • To account for different materials

What type of charge distribution is assumed for an infinite plane sheet when applying Gauss's law?

  • Non-uniform surface charge density
  • Uniform surface charge density (correct)
  • Line charge distribution
  • Point charges

In the context of Gauss's law, why do the electric field lines on certain faces of a Gaussian surface not contribute to the total flux?

<p>The electric field lines are parallel to those faces (D)</p> Signup and view all the answers

What is the direction of the unit vector normal to surface 1 of a Gaussian surface surrounding an infinite plane sheet?

<p>-x direction (D)</p> Signup and view all the answers

When considering a Gaussian surface around an infinite plane sheet, which sides contribute to the net flux as per Gauss's law?

<p>Faces 1 and 2 (B)</p> Signup and view all the answers

What is the significance of considering a rectangular parallelepiped or cylindrical surface as a Gaussian surface around an infinite plane sheet?

<p>It simplifies calculations and aids symmetry (B)</p> Signup and view all the answers

Why does the electric field not depend on y and z coordinates around an infinite plane sheet when applying Gauss's law?

<p>Due to symmetry (C)</p> Signup and view all the answers

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Study Notes

Assumptions and Limitations

  • The assumption of an infinitely long wire is crucial for applying Gauss's law
  • Without this assumption, the electric field (E) cannot be taken as normal to the curved part of the cylindrical Gaussian surface
  • Eq. (1.32) is approximately true for the electric field around the central portions of a long wire, where end effects can be ignored

Electric Field due to a Uniformly Charged Infinite Plane Sheet

  • The electric field (E) due to a uniformly charged infinite plane sheet does not depend on y and z coordinates
  • The direction of E at every point is parallel to the x-direction
  • The Gaussian surface can be a rectangular parallelepiped or a cylindrical surface
  • The flux through the Gaussian surface is 2EA, and the electric field lines are parallel to the x-axis
  • The electric field (E) is given by E = σ / (4πε0r²)

Electric Field due to a Uniformly Charged Thin Shell

  • The electric field outside the shell is as if the entire charge of the shell is concentrated at its centre
  • The electric field (E) outside the shell is E = q / (4πε0r²)
  • The electric field inside the shell is zero (E = 0) due to Gauss's law
  • This result confirms the 1/r² dependence in Coulomb's law

Gauss's Law

  • Gauss's law states that the total electric flux through a closed surface is proportional to the charge enclosed within the surface
  • The term q on the right side of Gauss's law includes the sum of all charges enclosed by the surface
  • The electric field on the left side of Gauss's law is due to all charges, both inside and outside the surface
  • The Gaussian surface can be chosen to facilitate easier calculation of the electrostatic field when the system has some symmetry

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