5 Questions
A 2.0 kg object moving at 4.0 m/s collides with a 3.0 kg object moving at 2.0 m/s in the opposite direction. If the objects stick together, what is the velocity of the combined object after the collision?
Using the law of conservation of momentum, we can set up the equation: (2.0 kg)(4.0 m/s) + (3.0 kg)(-2.0 m/s) = (5.0 kg)v, where v is the final velocity. Solving for v, we get v = 0.8 m/s.
A 50 kg gymnast is standing still on a frictionless floor. She then pushes off the floor with her foot and starts moving at 2.0 m/s. What is the velocity of the floor after the gymnast pushes off?
Since the gymnast is on a frictionless floor, there is no external force acting on the system. The total momentum of the gymnast and floor is conserved. Since the initial momentum of the floor is 0, the final momentum of the floor must be equal to the initial momentum of the gymnast. Therefore, the velocity of the floor is -0.04 m/s.
A 0.5 kg ball moving at 5.0 m/s collides with a stationary 0.2 kg ball. If the balls stick together, what is the velocity of the combined object after the collision?
Using the law of conservation of momentum, we can set up the equation: (0.5 kg)(5.0 m/s) = (0.5 kg + 0.2 kg)v, where v is the final velocity. Solving for v, we get v = 3.33 m/s.
A 10 kg object moving at 3.0 m/s collides with a stationary 5 kg object. If the objects bounce off each other, what is the velocity of the 10 kg object after the collision?
Since the objects bounce off each other, we can use the law of conservation of momentum to find the velocity of the 10 kg object after the collision. Let's assume the velocity of the 10 kg object after the collision is v. Then, the velocity of the 5 kg object after the collision is -(3.0 m/s - v). Using the law of conservation of momentum, we can set up the equation: (10 kg)(3.0 m/s) = (10 kg)v + (5 kg)(-(3.0 m/s - v)). Solving for v, we get v = 2.0 m/s.
A 20 kg object moving at 2.0 m/s collides with a stationary 10 kg object. If the objects stick together, what is the percentage change in momentum of the system?
The initial momentum of the system is (20 kg)(2.0 m/s) = 40 kg m/s. The final momentum of the system is (20 kg + 10 kg)(v), where v is the final velocity. Using the law of conservation of momentum, we can set up the equation: (20 kg)(2.0 m/s) = (30 kg)v, where v = 1.33 m/s. The final momentum of the system is (30 kg)(1.33 m/s) = 40 kg m/s. Therefore, the percentage change in momentum is 0%.
Practice solving problems related to conservation of momentum, a fundamental concept in physics. This quiz covers various scenarios and applications of momentum conservation. Improve your understanding and skills with these exercises and solutions.
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