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Questions and Answers
In a clipping circuit using an ideal diode, resistor, and battery (VB) connected to the N side of the diode, what determines when the diode begins to conduct?
In a clipping circuit using an ideal diode, resistor, and battery (VB) connected to the N side of the diode, what determines when the diode begins to conduct?
- The diode conducts only when Vi(t) is exactly equal to VB.
- The diode conducts regardless of the relationship between Vi(t) and VB.
- The diode conducts when the input voltage Vi(t) is less than VB.
- The diode conducts when the voltage at the P side (Vi(t)) is higher than the voltage at the N side (VB). (correct)
For a clipper circuit utilizing a constant voltage drop diode (VDO), how does the output voltage (V0(t)) behave when the input voltage (Vi) is less than VB + VDO?
For a clipper circuit utilizing a constant voltage drop diode (VDO), how does the output voltage (V0(t)) behave when the input voltage (Vi) is less than VB + VDO?
- V0(t) is held constant at VDO.
- V0(t) equals Vi(t). (correct)
- V0(t) equals VB + VDO.
- V0(t) is clamped to zero volts.
In a transfer characteristic plot of a clipping circuit, what does a horizontal line segment indicate?
In a transfer characteristic plot of a clipping circuit, what does a horizontal line segment indicate?
- The diode is transitioning between conducting and non-conducting states.
- The output voltage is constant, indicating the clipping region. (correct)
- The input voltage is constant.
- The diode is in non-conducting state.
Consider a clipping circuit with a triangular input voltage (Vi) of 16V peak, a 4V battery, and a diode with VDO of 0.7V. What happens when Vi exceeds 3.3V?
Consider a clipping circuit with a triangular input voltage (Vi) of 16V peak, a 4V battery, and a diode with VDO of 0.7V. What happens when Vi exceeds 3.3V?
In a circuit with two diodes and two batteries, how do the polarities of the diodes impact the circuit's behavior with a sinusoidal input voltage?
In a circuit with two diodes and two batteries, how do the polarities of the diodes impact the circuit's behavior with a sinusoidal input voltage?
How does the relationship between VB1 and VB2 (voltage sources) affect the symmetry of the waveform in a two-diode clipper circuit?
How does the relationship between VB1 and VB2 (voltage sources) affect the symmetry of the waveform in a two-diode clipper circuit?
In a clipper circuit with ideal diodes, D1 and D2, and batteries of 2V and 4V respectively, what happens when the input voltage Vi is between 0V and 2V?
In a clipper circuit with ideal diodes, D1 and D2, and batteries of 2V and 4V respectively, what happens when the input voltage Vi is between 0V and 2V?
In a clipper circuit where D1 conducts, given i = (Vi - 2) / 20k and Vo = 2 + i * R2, how does the output voltage (Vo) change with the input voltage (Vi)?
In a clipper circuit where D1 conducts, given i = (Vi - 2) / 20k and Vo = 2 + i * R2, how does the output voltage (Vo) change with the input voltage (Vi)?
What is the key difference in the output waveform of clipper circuits with ideal diodes versus those with constant voltage drop diodes?
What is the key difference in the output waveform of clipper circuits with ideal diodes versus those with constant voltage drop diodes?
In a clamper circuit, what is the primary function of the circuit components (capacitor, resistor, and diode)?
In a clamper circuit, what is the primary function of the circuit components (capacitor, resistor, and diode)?
What is the typical relationship between the discharging time constant (RC) and the time period of the input voltage in a clamper circuit?
What is the typical relationship between the discharging time constant (RC) and the time period of the input voltage in a clamper circuit?
In a clamper circuit with a square wave input (V and -V) and an ideal diode, what is the output voltage (Vo) during the positive half cycle?
In a clamper circuit with a square wave input (V and -V) and an ideal diode, what is the output voltage (Vo) during the positive half cycle?
For a clamper circuit with an asymmetrical square wave input (20V and -5V) and a non-ideal diode with a 0.7V drop, what is the role of the positive half cycle?
For a clamper circuit with an asymmetrical square wave input (20V and -5V) and a non-ideal diode with a 0.7V drop, what is the role of the positive half cycle?
If a clamper circuit has a 2V reverse bias and an input with +5V in the negative half cycle, what is the approximate output voltage (Vo) on the negative side, considering a 0.7V diode drop?
If a clamper circuit has a 2V reverse bias and an input with +5V in the negative half cycle, what is the approximate output voltage (Vo) on the negative side, considering a 0.7V diode drop?
What is the primary advantage of using Zener diodes in clamping circuits?
What is the primary advantage of using Zener diodes in clamping circuits?
When a Zener diode is used in a clamping circuit, and the input voltage is greater than Vz + VDO in the reverse bias, what happens?
When a Zener diode is used in a clamping circuit, and the input voltage is greater than Vz + VDO in the reverse bias, what happens?
In a clipper circuit using Zener diodes, what determines the output voltage when the input voltage is in the positive half cycle and exceeds Vz + VDO?
In a clipper circuit using Zener diodes, what determines the output voltage when the input voltage is in the positive half cycle and exceeds Vz + VDO?
What is the main purpose of a clamper circuit?
What is the main purpose of a clamper circuit?
In practical applications, what distinguishes the function of clipper circuits from that of clamper circuits?
In practical applications, what distinguishes the function of clipper circuits from that of clamper circuits?
What general category do clipping and clamping circuits fall under?
What general category do clipping and clamping circuits fall under?
Flashcards
Clipping and Clamping Circuits
Clipping and Clamping Circuits
Circuits using diodes, resistors, and capacitors to shape waveforms.
Clipping Circuits
Clipping Circuits
Circuits that limit or remove portions of a signal's waveform.
Clamping Circuits
Clamping Circuits
Circuits that shift the DC voltage level of a signal without changing its shape.
Ideal Diode - Non-conducting
Ideal Diode - Non-conducting
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Ideal Diode - Conducting
Ideal Diode - Conducting
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Transfer Characteristic
Transfer Characteristic
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Clipper Circuits (General)
Clipper Circuits (General)
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Vo = (Vi / 2) + 1
Vo = (Vi / 2) + 1
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Clamper Circuits
Clamper Circuits
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Discharging Time Constant (RC)
Discharging Time Constant (RC)
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Square Wave Input
Square Wave Input
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Ideal Zener Diodes
Ideal Zener Diodes
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Zener Diode Breakdown
Zener Diode Breakdown
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Output Voltage Plot (Vo)
Output Voltage Plot (Vo)
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Study Notes
Clipping and Clamping Circuits
- Waveforms are shaped using diodes, resistors, and capacitors.
- Clipping circuits are used to limit or clip parts of a signal.
- Clamping circuits shift the DC voltage level of a signal.
- These circuits are also known as wave shaping circuits.
- Applications include communications and control/instrumentation circuits.
Clippers Using Ideal Diodes
- An ideal diode has a threshold voltage of zero and zero forward resistance.
- One such circuit contains an ideal diode, a resistor R, and a battery VB connected to the N side of the diode.
- Output voltage V0(t) for a given input Vi(t) is determined by first establishing when the diode conducts.
- Conduction happens when the voltage at the P side (Vi(t)) exceeds the voltage at the N side (VB).
- When Vi(t) < VB, the diode is off, behaving as an open circuit.
- Therefore, when the diode is not conducting, V0(t) = Vi(t).
- Diode conducts when Vi(t) > VB.
- When the diode conducts, V0(t) = VB because the ideal diode drop is zero.
- The input voltage waveform's upper portion above VB is clipped off.
Clippers using Constant Voltage Drop Diodes
- A real diode has a voltage drop VDO, 0.7V for silicon.
- rD (resistance of the diode) is ignored in comparison to resistance R.
- Replace the diode by its equivalent model: a battery showing the drop VDO along with an ideal diode.
- Diode conducts when Vi > VB + VDO.
- When the diode conducts, V0(t) = VB + VDO.
- When Vi < VB + VDO, the diode does not conduct, therefore V0(t) = Vi(t).
- The upper portion of the input voltage waveform above VB + VDO is clipped off.
- A diode drop results in more of the upper portion being clipped.
Transfer Characteristics
- Transfer characteristic is a plot showing output voltage (Vo) versus input voltage (Vi).
- Output and input voltages are equal until Vi < VB + VDO, showing a linear relationship with a slope of 1 passing through the origin.
- When Vi > VB + VDO, the output voltage is constant at VB + VDO.
- Describes conducting and non-conducting states.
Example Circuit with Triangular Input
- Circuit uses a 4V battery, connected with its positive terminal to the P side of the diode, and a triangular input voltage (Vi) of 16V peak value.
- VDO is 0.7V.
- Condition for conduction is determined by comparing the voltage at the P and N sides of the diode.
- The diode conducts when Vi is less than 4 - VDO (3.3V).
- When the diode conducts, the output voltage is clipped at 3.3V.
- When Vi > 3.3V, the diode does not conduct, and V0 = Vi.
- Lower portion of the waveform is clipped.
Circuit with Two Diodes and Two Batteries
- Circuit uses two diodes (D1, D2) and two batteries (VB1, VB2) connected with certain polarities.
- Input voltage (Vi) is sinusoidal.
- Constant voltage drop model is used for the diodes.
- The diodes are replaced by their constant voltage drop models.
- VB1 and VB2 initially reverse biasing the diodes.
- Diode D1 conducts only during the input voltage's positive half cycle; diode D2 conducts only during the negative half cycle.
- D1 conducts when Vi > VB1 + VDO.
- In the diode's positive half cycle, D2 does not conduct.
- In the negative half cycle, magnitude of Vi > magnitude of VB2 + VDO.
- The output voltage waveform is determined by analyzing when each diode conducts.
Clipper Circuits
- Portions of a waveform are clipped away by clipper circuits, both upper and lower.
- The waveform may not be symmetrical, depending on the magnitudes of VB1 and VB2 (voltage sources).
- The waveform will be symmetrical if VB1 and VB2 are equal.
- The waveform will be asymmetrical if VB1 is higher than VB2, or vice versa.
- The diode conducts when Vi is greater than VB1 + VDO, clamping the voltage to VB1 + VDO.
- When Vi is less than VB1 + VDO, the diode does not conduct, and Vo equals Vi.
- In the negative half cycle, when Vi is greater than VB2 + VDO, diode D2 conducts, and the voltage is VB2 + VDO.
- Output voltage plot (Vo) shows the clipped waveform.
Example Clipper Circuit with Ideal Diodes
- Diodes (D1 and D2) are ideal, therefore voltage drop is zero and resistances are ignored.
- The circuit includes two batteries: 2V and 4V, which reverse bias the diodes.
- Vi is 6 sin(ωt) with a peak value of 6V.
- From 0 to 2V, both D1 and D2 are OFF (not conducting).
- Output voltage (Vo) equals input voltage (Vi) when Vi is less than 2V.
- When Vi is greater than 2V, D1 conducts, and current flows in the circuit.
Calculating Voltage When D1 Conducts
- Voltage drop across two points is 2V plus i * R2.
- i = (Vi - 2) / (10k + 10k) = (Vi - 2) / 20k.
- When D1 turns ON, Vo = 2 + i1 * R2 = (Vi / 2) + 1.
- If Vi is 6V, then Vo = (6 / 2) + 1 = 4V.
- D2 does not conduct up to -4V in the negative half cycle.
- D2 conducts when the negative voltage is greater than 4V.
- Since D2 is ideal, the voltage is -4V when D2 is ON.
Combining Waveforms of the Clipper Circuit
- From 0 to 2V, input and output are the same.
- At input 6V, output is 4V.
- The circuit doesn't conduct until the negative half cycle is greater than 4V, then the voltage is -4V.
- Unlike constant voltage drop in earlier circuits, the output is clipped but with a slope.
Transfer Characteristic
- From 0 to 2V, output and input voltage are the same in a straight line with slope 1.
- Output is at 4V (the voltage at the output) when greater than 2V, from this point to Vi at 6V.
- Diode D2 is not conducting, so in the negative half cycle (again up to -4V), input and output voltage are the same.
- When crossing -4V, diode D2 conducts, and the output voltage (Vo) is -4V.
Clamper Circuits
- Clamper shifts the DC level of a waveform to a different value.
- A Sinusoidal waveform's average DC value of zero can be changed.
- A simple clamper includes a capacitor (C), a resistor (R), and a diode.
- The discharging time constant (RC) is very large compared to the time period of the input voltage.
Clamper Circuit Operation with Square Wave Input and Ideal Diode
- Square wave input with voltages V and -V.
- In the positive half cycle, the diode is forward biased.
- The capacitor charges to a voltage of V.
- Charging time constant is almost zero, and the capacitor has negligible resistance.
- In the negative half cycle, the diode is reverse biased by a voltage of twice V.
- Output voltage (Vo) is zero in the positive half cycle.
- In the negative half cycle, Vo is -2V.
Clamper Circuit with Asymmetrical Square Wave and Non-Ideal Diode
- Diode has a 0.7 voltage drop.
- Asymmetrical square wave input: 20V in the positive half cycle and -5V in the negative half cycle.
- The diode is reverse biased and does not conduct in the positive half cycle.
- There is no current, and the voltage drop across the resistance is zero.
Clamper Circuit Analysis
- 2V reverse biases the diode.
- Positive half cycle of 20V is applied, reverse biasing the diode and making it non-conducting.
- In the negative half cycle, +5V is forward biasing the diode.
- The N point has 2.7V total potential, while this point has +5V.
- Applying Kirchhoff’s voltage law: Vo - 0.7 - 2 + 5 = 0.
- Vo = -5 + 2.7 = -2.3V on the negative side.
- Zero voltage on the positive half cycle and clipped at -2.3V on the negative side.
Zener Diodes for Clamping
- Zener diodes are used for both clipping and clamping.
- Ideal Zener diodes have a diode drop (VDO) in the forward direction and a Zener voltage (Vz).
- One Zener diode is reverse biased when the input voltage is in the positive half cycle and the other acts like a normal diode.
- The Zener diode breaks down when the input voltage is greater than Vz + VDO.
- The voltage across the two points is Vz + VDO.
- In the negative half cycle, the first diode is reverse biased, and the next is forward biased.
- If the input voltage is greater than Vz + VDO in the reverse bias, there is conduction, and the is Vz + VDO.
- Output voltage is clipped at ±(Vz + VDO).
- Draw an approximate equivalent circuit with Zener voltage and diode drop for analysis.
Applications
- Clipper and clamper circuits have pratical uses.
- Clippers clip portions of the waveform.
- Clampers shift or clamp the DC voltage level of the waveform to some other value.
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