Calculating Head Pressure Quiz

What is the head pressure exerted by 6 ft of a liquid material with a specific gravity of 1.2 in an open tank?

How much pressure is produced by 10 ft of liquid with a specific gravity of 0.8g in a closed vessel with 5 psi of nitrogen pressure on top?

What is the pressure gauge reading located 4 ft from the bottom of an open tank with a liquid level of 12 ft and specific gravity of 1.1?

How much head pressure is exerted by 8 ft of a liquid material with a specific gravity of 1.2 in an open tank?

If a liquid with a specific gravity of 1.1 is 12 ft high in an open tank, what would be the head pressure at the bottom of the tank?

Calculating Head Pressure

Head pressure is calculated by multiplying the height of the liquid column by its specific gravity.
The formula for head pressure is: Head Pressure = Height x Specific Gravity
Head pressure is measured in psi (pounds per square inch).
The specific gravity of a liquid is its density relative to water.
A specific gravity of 1.2 means the liquid is 1.2 times denser than water.

Example Calculations

Example 1: 6 ft of liquid with a specific gravity of 1.2 exerts a head pressure of 7.2 psi (6 ft x 1.2 = 7.2 psi).
Example 2: 8 ft of liquid with a specific gravity of 1.2 exerts a head pressure of 9.6 psi (8 ft x 1.2 = 9.6 psi).
Example 3: 10 ft of liquid with a specific gravity of 0.8 in a closed vessel with 5 psi of nitrogen pressure on top produces a total pressure of 13.47 psi (10 ft x 0.8 = 8 psi, 8 psi + 5 psi = 13.47 psi).
Example 4: A pressure gauge located 4 ft from the bottom of an open tank with a liquid level of 12 ft and a specific gravity of 1.1 will read 8.8 psi (12 ft - 4 ft = 8 ft, 8 ft x 1.1 = 8.8 psi).

Test your knowledge on calculating head pressure in liquids. This quiz covers the formula for head pressure, specific gravity, and practical examples to enhance your understanding. It's a great resource for students and professionals alike in fluid mechanics.