Bond Angle Deviation in Water
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Questions and Answers

What is the primary reason for the deviation of the bond angle in water from the ideal tetrahedral angle of 109.5 degrees?

  • The weak interaction between the hydrogen and oxygen atoms
  • The covalent bonding between the oxygen and hydrogen atoms
  • The attractive forces between the hydrogen atoms
  • The strong repulsion between the lone pairs on the oxygen atom (correct)
  • Which factor significantly contributes to the smaller bond angle of water (104.5 degrees) compared to the ideal tetrahedral angle (109.5 degrees)?

  • The attractive forces between lone pairs
  • The strong repulsion between bonding pairs
  • The strong repulsion between lone pairs (correct)
  • The weak repulsion between lone pairs
  • If the lone pairs on the oxygen atom in water had the same repulsive force as the bonding pairs, what would be the expected bond angle?

  • 180 degrees
  • 90 degrees
  • 109.5 degrees (correct)
  • 104.5 degrees
  • What is the relationship between the repulsion among electron pairs and the bond angle in a molecule?

    <p>Greater repulsion leads to a smaller bond angle. (D)</p> Signup and view all the answers

    Why does the concept of hybridization explain the difference in bond angles between an ideal tetrahedral molecule and water?

    <p>Hybridization dictates the shape of a molecule based on the arrangement of electron pairs. (A)</p> Signup and view all the answers

    Flashcards

    Water Bond Angle

    The bond angle in water is 104.5 degrees due to electron pair repulsion.

    Lone Pair Repulsion

    Lone pairs exert stronger repulsion than bonding pairs, influencing angles.

    Ideal Bond Angle

    The ideal bond angle for sp³ hybridization is 109.5 degrees.

    Electron Pair Geometry

    Electron pairs arrange to minimize repulsion, influencing molecular shape.

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    Hybridization

    The concept explaining the formation of different molecular shapes.

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    Study Notes

    Reasons for the Bond Angle Deviation in Water

    • Water (H₂O) molecule has a bent or V-shaped structure.
    • The ideal bond angle for sp³ hybridization is 109.5 degrees.
    • In water, the bond angle is 104.5 degrees.

    Explanation of Deviation

    • The central oxygen atom in water has two bonded hydrogen atoms and two lone pairs of electrons.
    • These lone pairs are negatively charged and repel each other strongly due to their close proximity in space.
    • The presence of lone pairs exerts more repulsive force than bonding pairs.
    • This stronger repulsion between lone pairs forces the bonded hydrogen atoms closer together to minimize the repulsion.
    • Consequently, the bond angle reduces from the ideal tetrahedral bond angle of 109.5 degrees to 104.5 degrees in water.

    Summary of Factors Influencing Bond Angle

    • Electron-pair Repulsion: Lone pairs exert more repulsion than bonding pairs.
    • Bond angles: The greater the repulsion among electron pairs (whether bonding or lone pairs), the smaller the bond angle.
    • Geometry: The electron pairs (lone pairs and bonded pairs) arrange themselves in a way to minimize repulsion, resulting in a specific molecular geometry.
    • Hybridization: The concept of hybridization explains the different kinds of molecular shapes, like the tetrahedral arrangement in water's case.
    • Repulsion: The repulsion between lone pairs and bonded pairs leads to a distorted shape, ultimately determining the observed bond angle.

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    Description

    This quiz explores the reasons for the bond angle deviation in water (H₂O), focusing on its bent structure and the influence of lone pairs of electrons. Learn how the bond angle in water reduces from the ideal 109.5 degrees to 104.5 degrees due to electron pair repulsion. Test your understanding of molecular geometry and electron interactions.

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