Atomic Mass and Avogadro's Number Quiz
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Questions and Answers

What is the mass of 1 atom of C-12 expressed in atomic mass units (amu)?

  • 6.022 x 10^23 amu
  • 11.8726 amu
  • 1.992657 x 10^-23 amu
  • 12.00 amu (correct)
  • What term is used to refer to the quantity of particles of a substance that is equal to Avogadro’s number?

  • Formula units
  • Molecules
  • Mole (correct)
  • Atomic mass
  • Where can the atomic mass of an element be found?

  • Molecules
  • Moles
  • Atomic mass units
  • Number of protons and neutrons (correct)
  • What is the average atomic mass of C?

    <p>12.01173638 amu</p> Signup and view all the answers

    What is the average atomic mass of K?

    <p>39.0983 amu</p> Signup and view all the answers

    What is used to find the average mass of an element and molecules to solve stoichiometric problems?

    <p>Moles</p> Signup and view all the answers

    What is the value of Avogadro’s constant?

    <p>6.022 x 10^23 particles</p> Signup and view all the answers

    What is the formula mass of Na₃PO₄?

    <p>163.94 amu</p> Signup and view all the answers

    What is the molecular mass of carbon dioxide (CO₂)?

    <p>44.01 amu</p> Signup and view all the answers

    How many moles are there in 460.0 g of sodium?

    <p>10 moles</p> Signup and view all the answers

    How many sodium atoms are there in 460.0 g of sodium?

    <p>$1.2044 x 10^{24}$ atoms</p> Signup and view all the answers

    Determine the number of atoms and the mass of 0.85 mole of copper.

    <p>$3.4115 x 10^{23}$ atoms, 20 g</p> Signup and view all the answers

    How many grams and atoms of hydrogen are present in 65 grams of glucose (C₆H₁₂O₆)?

    <p>$3.6072 x 10^{24}$ atoms, 24 g</p> Signup and view all the answers

    What does Avogadro’s Law govern?

    <p>The relationship between the number of gas particles and the volume they occupy</p> Signup and view all the answers

    What is the simplest positive integer ratio of atoms present in a compound called?

    <p>Empirical formula</p> Signup and view all the answers

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