AC Circuits, Transformers, and Transmission Lines
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Questions and Answers

A sinusoidal current is given by $i(t) = 10\cos{(\omega t + 30^\circ)} A$. What is the RMS value of the current and its phasor representation in polar form?

  • $I_{rms} = 10 A$, $I = 10 \angle 30^\circ A$
  • $I_{rms} = 7.07 A$, $I = 10 \angle 30^\circ A$
  • $I_{rms} = 10 A$, $I = 7.07 \angle 30^\circ A$
  • $I_{rms} = 7.07 A$, $I = 7.07 \angle 30^\circ A$ (correct)

A voltage is described by the equation $v(t) = 170\cos{(\omega t - 45^\circ)} V$. Determine the approximate rectangular representation of the RMS voltage phasor.

  • $120.2 - j120.2 V$ (correct)
  • $170 - j170 V$
  • $60 - j60 V$
  • $85 - j85 V$

In an electrical circuit, which of the following statements best describes the contribution of reactive components to impedance?

  • Inductors and capacitors contribute to the imaginary part of impedance due to the phase shift between voltage and current. (correct)
  • Inductors and capacitors only affect the magnitude, but not the phase, of the impedance.
  • Both inductors and capacitors contribute solely to the real part of the impedance.
  • Inductors contribute to the real part of impedance, while capacitors contribute to the imaginary part.

A Ward-Leonard system controls a motor. If the generator output voltage ($E_o$) decreases while the generator field voltage ($E_s$) remains constant, what is the likely effect on the motor's speed and torque, assuming armature resistance is non-negligible?

<p>Speed and torque both decrease. (A)</p> Signup and view all the answers

In a Ward-Leonard system, what happens to motor speed if the generator's field voltage ($E_s$) is increased, assuming the motor back EMF remains constant and other parameters are unchanged?

<p>Motor speed increases. (D)</p> Signup and view all the answers

What is the primary reason for using higher voltage levels in long-distance transmission lines?

<p>To minimize voltage drop and line losses. (A)</p> Signup and view all the answers

In areas with extreme weather conditions, what factor is most important in the design of transmission line conductors?

<p>The conductor's ability to withstand thermal expansion and mechanical stress. (B)</p> Signup and view all the answers

Why is aluminum commonly used for aerial transmission lines?

<p>It is lighter, less expensive, and has good conductivity. (A)</p> Signup and view all the answers

What is the main purpose of the steel reinforcement in ACSR conductors?

<p>To provide additional mechanical strength for longer spans. (D)</p> Signup and view all the answers

If Transformer A has core losses($P_{core}$) of 180W and Transformer B has core losses of 200W, and both have an apparent power (S) of 600 VA, which transformer absorbs more reactive power?

<p>Transformer A absorbs more reactive power. (C)</p> Signup and view all the answers

How does increased iron loss in a transformer affect the reactive power absorbed by its core, assuming the apparent power remains constant?

<p>Decreases the reactive power absorbed. (D)</p> Signup and view all the answers

Two transformers, A and B, have the same apparent power rating. If transformer A has lower core losses than transformer B, what can be concluded about their reactive power absorption?

<p>Transformer A absorbs more reactive power than transformer B. (D)</p> Signup and view all the answers

If a transmission line needs to be upgraded to carry more power without increasing the voltage, what adjustments might be necessary based on provided considerations?

<p>Use a conductor material with higher conductivity and ensure it can handle increased thermal stress. (C)</p> Signup and view all the answers

Given an armature resistance of $17 imes 10^{-3} \Omega$ and a source voltage of 750V, if the back EMF ($E_o$) is 420V, what is the armature current?

<p>19,411.8 A (B)</p> Signup and view all the answers

With a back EMF ($E_o$) of 420V and an armature current of 19411.8 A, what is the power supplied to the motor armature?

<p>8,152,956 W (C)</p> Signup and view all the answers

If a motor runs at 570 r/min with a back EMF of 350V, what is its speed when the back EMF is increased to 420V, assuming a linear relationship?

<p>684 r/min (D)</p> Signup and view all the answers

With a power input of $8153 imes 10^3 W$ and a speed of 684 r/min, what is the motor torque?

<p>113.8 kN.m (A)</p> Signup and view all the answers

Given a source voltage of 370V and a back EMF of 400V, with an armature resistance of $17 imes 10^{-3} \Omega$, what is the armature current, and what does the sign indicate?

<p>-2941.2A, indicating reverse direction (C)</p> Signup and view all the answers

If the back EMF ($E_o$) is 400V and the armature current is -2941.2A, what is the power to the motor armature?

<p>-1176.5 kW (A)</p> Signup and view all the answers

What does a negative armature current typically indicate in a motor?

<p>The motor is acting as a generator, with current flowing back into the source. (D)</p> Signup and view all the answers

Flashcards

What is $I_{max}$?

The peak value of an alternating current (AC) waveform.

What is $I_{rms}$?

The root mean square value of an alternating current (AC), calculated as $I_{max} / \sqrt{2}$.

What is phasor representation?

A way to represent a sinusoidal waveform using magnitude and phase angle.

What is rectangular form?

Representation of a complex number as Re + jIm, where Re is the real part and Im is the imaginary part.

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Which components cause impedance's imaginary part?

Inductors and capacitors introduce a phase shift between voltage and current, resulting in an imaginary component of impedance.

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Environmental Considerations

Local conditions impacting design and materials.

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Voltage and Power Capacity

Designing lines to handle voltage and power needs, using higher voltage for long distances to cut losses.

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Thermal Expansion

Material endures expansion without sagging.

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Aluminum in Transmission Lines

Aluminium offers lightness, affordability, and good conductivity

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ACSR

Steel-reinforced aluminum conductor: strong for long spans.

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Q_m

Transformers A and B reactive power absorbed by core of transformers.

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P_core

Transformers A and B iron losses.

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P_core influence

Transformer B reactive power absorbed by the core is slightly lower than that of transformer A because Transformer B has higher iron losses

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Armature Current (I)

Current flowing through the motor armature, determined by voltage difference and resistance. A negative value indicates reverse flow.

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Power to Armature (P)

The power delivered to the motor's armature, calculated from back EMF and armature current.

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Motor Speed (n)

The rotational speed of the motor, influenced by the back EMF and a proportional constant.

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Motor Torque (T)

The rotational force produced by the motor, related to the power and speed. Measured in Newton-meters (N.m).

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Core Resistance (Rm)

The equivalent resistance representing core losses in a transformer. Calculated using source voltage and core loss power.

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Reactive Power (Qm)

The reactive power associated with magnetizing the transformer core. Calculated using apparent power and core loss power.

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Magnetizing Reactance (Xm)

The inductive reactance representing the magnetizing characteristics of the transformer core.

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Core Loss Current (If)

The current responsible for core losses in the transformer, determined by core resistance and voltage.

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Study Notes

  • These notes cover AC circuit calculations, transformer analysis, and transmission line design considerations.

AC Circuit Calculations

  • Given a current i(t) = 237 cos(ωt + 75°) A, the maximum current (Imax) is 237 A.
  • The RMS current (Irms) is calculated as Imax / √2, resulting in 167.6 A.
  • In polar form, the current is represented as I = 167.6 ∠75° A.
  • In rectangular form, the current is I = 43.4 + j161.9 A, where 43.4 is the real part and 161.9 is the imaginary part.
  • Given a voltage v(t) = 321.7 cos(ωt + 25°) V, the maximum voltage (Vmax) is 321.7 V.
  • The RMS voltage (Vrms) is calculated as Vmax / √2, resulting in 227.5 V.
  • In polar form, the voltage is represented as V = 227.5 ∠25°.
  • In rectangular form, the voltage is V = 206 + j96.1 V, where 206 is the real part and 96.1 is the imaginary part.

Impedance in Electrical Circuits

  • In an electrical circuit, the imaginary part of the impedance is contributed by reactive components, specifically inductors and capacitors.
  • These components introduce a phase shift between voltage and current.
  • This phase shift leads to the imaginary part of the total impedance.

Motor and Generator System Analysis

  • A 4500kW, 350V variable-speed motor is powered by a 1500kW generator using a Ward-Leonard control system.
  • The combined resistance of the motor and generator armature circuit is 17mΩ.
  • The motor operates at its nominal speed of 570 r/min when the output voltage, Eo = 1000V.
  • With Es = 750V and Eo = 420V, the armature current (I) is calculated as (Es - Eo) / R = 19411.8 A.
  • The power to the motor armature at Eo = 420V is P = Eo * I = 8152956 W.
  • The motor speed at Eo = 420V is n = 684 r/min.
  • The motor torque at Eo = 400V is T = 113.8 kN·m.
  • With Es = 370V and Eo = 400V, the armature current (I) is -2941.2A, where the negative sign indicates the current direction.
  • The power to the motor armature at Eo = 400V is P = 1235.3 kW.
  • The motor speed at Eo = 420V is n = 684 r/min.
  • The motor torque at Eo = 420V is T = 17.2 kNm.

Transformer Analysis

  • The transformer is imperfect in its core.
  • The ideal transformer circuit diagram includes an imperfect core, with parameters listed in a table.
  • Given data for Transformer A: source voltage Vg = 120V, exciting current Io = 5A, and core loss power Pcore = 180W.
  • The core resistance (Rm) of Transformer A is calculated as Vg^2 / Pcore = 80.0 Ω.
  • The reactive power (Qm) of Transformer A is calculated as √(S^2 - Pcore^2) = 572.36 VAR.
  • The magnetizing reactance (Xm) of Transformer A is calculated as Vg^2 / Qm = 25.16 Ω.
  • The core losses current (If) is calculated as Vg / Rm = 1.5A.
  • The magnetizing current (Im) is calculated as Vg / Xm = 4.77A.
  • The total exciting current (Io) is verified as √(If^2 + Im^2) = 5 A.
  • Given another transformer B with the same parameters as transformer A but with iron losses of 200W.
  • The reactive power absorbed by the core of transformer B is lower than that of transformer A.
  • Transformer B has higher iron losses (Pcore, B = 200W) than Transformer A (Pcore, A = 180W).

Aerial Transmission Line Design

  • The local environment affects the line design and materials used, especially in areas prone to high winds or extreme temperatures.
  • The transmission line should handle the required voltage and power capacity for the service area; higher voltage levels are used for long-distance transmission to minimize voltage drop and line losses.
  • In areas prone to high winds or extreme temperatures, conductors need to be designed for additional mechanical stress and withstand thermal expansion without sagging excessively.
  • The choice of conductor material affects the line's efficiency, durability, and cost; aluminum is commonly chosen for aerial transmission lines due to being lighter, less expensive, and having good conductivity.
  • Steel-reinforced aluminum conductor (ACSR) is often used, which is strong enough for long spans.

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Description

Explore AC circuit calculations, including RMS and peak values of current and voltage. Understand impedance, transformer analysis and transmission line design considerations. Learn to convert between polar and rectangular forms.

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