Graphs of Circular Functions PDF

Summary

This document provides detailed explanations and solutions for various trigonometric functions, including sine, cosine, secant, cosecant, tangent, and cotangent. It covers topics such as domain, range, amplitude, and period for these functions.

Full Transcript

GRAPHS OF CIRCULAR FUNCTIONS Graph: 𝑦 = sin 𝑥 Graph: 𝑦 = cos 𝑥 The domain of both 𝑦 = asin 𝑏(𝑥 − 𝑐) + 𝑑 and 𝑦 = 𝑎 cos 𝑏(𝑥 − 𝑐) + 𝑑 is the set of real numbers or (−∞, ∞). The range of both 𝑦 = asin 𝑏(𝑥 − 𝑐) + 𝑑 and 𝑦 = 𝑎 cos 𝑏(𝑥 − 𝑐) + 𝑑 is 𝑑 − 𝑎 , 𝑑 + 𝑎. The number 𝑎 is the amplitude of...

GRAPHS OF CIRCULAR FUNCTIONS Graph: 𝑦 = sin 𝑥 Graph: 𝑦 = cos 𝑥 The domain of both 𝑦 = asin 𝑏(𝑥 − 𝑐) + 𝑑 and 𝑦 = 𝑎 cos 𝑏(𝑥 − 𝑐) + 𝑑 is the set of real numbers or (−∞, ∞). The range of both 𝑦 = asin 𝑏(𝑥 − 𝑐) + 𝑑 and 𝑦 = 𝑎 cos 𝑏(𝑥 − 𝑐) + 𝑑 is 𝑑 − 𝑎 , 𝑑 + 𝑎. The number 𝑎 is the amplitude of the graphs of 𝑦 = 𝑎 sin 𝑏(𝑥 − 𝑐) + 𝑑 and 𝑦 = 𝑎 cos(𝑏(𝑥 − 𝑐)) + 𝑑. The period of 𝑦 = 𝑎 sin 𝑏(𝑥 − 𝑐) + 𝑑 and 2𝜋 𝑦 = 𝑎 cos 𝑏(𝑥 − 𝑐) + 𝑑 is. 𝑏 Find the domain, range, amplitude, and period of 𝑦 = − 2 sin(3𝑥 + 𝜋). Solution: Note that 𝑦 = −2 sin 3𝑥 + 𝜋 can be written as 𝑦 = 𝜋 𝜋 − 2 sin 3 𝑥 +. This means that 𝑎 = −2, 𝑏 = 3, 𝑐 = − , and 3 3 𝑑 = 0. Domain: (−∞, ∞) Range: 𝑑 − 𝑎 , 𝑑 + 𝑎 = 0 − −2 , 0 + −2 = −2,2 Amplitude: 𝑎 = −2 = 2 2𝜋 2𝜋 2𝜋 Period: = = 𝑏 3 3 Find the domain, range, amplitude, and period of 𝜋 𝑦 = −2 cos −2𝑥 + −1 4 Solution: 𝜋 Note that 𝑦 = −2 cos −2𝑥 + − 1 can be written as 𝜋 4 𝑦 = −2 cos −2 𝑥 − − 1. This means that 𝑎 = −2, 𝑏 = −2, 𝜋 8 𝑐 = , and 𝑑 = −1. 8 Domain: (−∞, ∞) Range: 𝑑 − 𝑎 , 𝑑 + 𝑎 = −1 − −2 , −1 + −2 = −3,1 Amplitude: 𝑎 = −2 = 2 2𝜋 2𝜋 2𝜋 Period: = = =𝜋 𝑏 −2 2 Graph: 𝑦 = sec 𝑥 Graph: 𝑦 = csc 𝑥 The domain of 𝑦 = 𝑎 csc 𝑏(𝑥 − 𝑐) + 𝑑 is the set of 𝑥 ∈ ℝ: sin 𝑏 𝑥 − 𝑐 ≠ 0 = 𝑘𝜋 𝑥 ∈ ℝ: 𝑥 ≠ 𝑐 + , 𝑘 ∈ ℤ. 𝑏 The domain of 𝑦 = 𝑎 sec 𝑏(𝑥 − 𝑐) + 𝑑 is the set of 𝑥 ∈ ℝ: cos 𝑏 𝑥 − 𝑐 ≠ 0 = 𝑘𝜋 𝑥 ∈ ℝ: 𝑥 ≠ 𝑐 + , 𝑘 is an odd integer. 2𝑏 The range of both 𝑦 = 𝑎 csc 𝑏(𝑥 − 𝑐) + 𝑑 and 𝑦 = 𝑎 sec 𝑏(𝑥 − 𝑐) + 𝑑 is (−∞, 𝑑 − 𝑎 ሿ ∪ 𝑑 + 𝑎 ,∞. The period of both 𝑦 = 𝑎 csc(𝑏(𝑥 − 2𝜋 𝑐)) + 𝑑 and 𝑦 = 𝑎 sec 𝑏(𝑥 − 𝑐) + 𝑑 is. 𝑏 The asymptotes of 𝑦 = 𝑎 csc 𝑏(𝑥 − 𝑐) + 𝑑 𝑘𝜋 are 𝑥 = 𝑐 + , 𝑘 ∈ ℤ. 𝑏 The asymptotes of 𝑦 = 𝑎 sec 𝑏(𝑥 − 𝑐) + 𝑑 𝑘𝜋 are 𝑥 = 𝑐 + , 𝑘 is an odd integer. 2𝑏 Find the domain, range, amplitude, and period of 𝑦 = −2 sec(3𝑥 + 𝜋) Solution: Note that 𝑦 = −2 sec(3𝑥 + 𝜋) can be written as 𝜋 𝜋 𝑦 = −2 sec 3 𝑥 +. This means that 𝑎 = −2, 𝑏 = 3, 𝑐 = − , 3 3 and 𝑑 = 0. 𝑘𝜋 Domain: 𝑥 ∈ ℝ: 𝑥 ≠ 𝑐 + 2𝑏 , 𝑘 is an odd integer = 𝜋 𝑘𝜋 𝑥 ∈ ℝ: 𝑥 ≠ − + ,𝑘 is an odd integer 3 6 Range: −∞, 𝑑 − 𝑎 ∪ 𝑑 + 𝑎 , ∞ = −∞, 0 − −2 ∪ ሾ0 + −2 , ∞) = −∞, −2 ∪ 2, ∞ Solution: 2𝜋 2𝜋 2𝜋 Period: = = 𝑏 3 3 𝑘𝜋 Asymptotes: 𝑥 = 𝑐 + 2𝑏 , 𝑘 is an odd integer; thus, the asymptotes 𝜋 𝑘𝜋 are 𝑥 = − + ,𝑘 is an odd integer 3 6 Find the domain, range, amplitude, and period 𝜋 of 𝑦 = −2 csc(−2𝑥 − ) − 1 4 Solution: 𝜋 Note that 𝑦 = −2 csc(−2𝑥 − )− 1 4 𝜋 can be written as 𝑦 = −2 csc −2 𝑥 + − 1. This means that 8 𝜋 𝑎 = −2, 𝑏 = −2, 𝑐 = − , and 𝑑 = −1. 8 𝑘𝜋 𝜋 𝑘𝜋 Domain: 𝑥 ∈ ℝ: 𝑥 ≠ 𝑐 + 𝑏 ,𝑘 ∈ ℤ = 𝑥 ∈ ℝ: 𝑥 ≠ − 8 + 2 ,𝑘 ∈ℤ Range: −∞, 𝑑 − 𝑎 ∪ 𝑑 + 𝑎 , ∞ = −∞, −1 − −2 ∪ ሾ−1 + −2 , ∞) = −∞, −3 ∪ 1, ∞ Solution: 2𝜋 2𝜋 Period: = =𝜋 𝑏 −2 𝑘𝜋 Asymptotes: 𝑥 = 𝑐 + ,𝑘 𝑏 ∈ ℤ; thus, the asymptotes are 𝜋 𝑘𝜋 𝑥= − + ,𝑘 ∈ℤ 8 2 Graph: 𝑦 = tan 𝑥 Graph: 𝑦 = cot 𝑥 The domain of 𝑦 = 𝑎 cot 𝑏(𝑥 − 𝑐) + 𝑑 is the set of 𝑥 ∈ ℝ: sin 𝑏 𝑥 − 𝑐 ≠ 0 = 𝑘𝜋 𝑥 ∈ ℝ: 𝑥 ≠ 𝑐 + , 𝑘 ∈ ℤ. 𝑏 The domain of 𝑦 = 𝑎 tan 𝑏(𝑥 − 𝑐) + 𝑑 is the set of 𝑥 ∈ ℝ: cos 𝑏 𝑥 − 𝑐 ≠ 0 = 𝑘𝜋 𝑥 ∈ ℝ: 𝑥 ≠ 𝑐 + , 𝑘 is an odd integer. 2𝑏 The range of both 𝑦 = 𝑎 cot 𝑏(𝑥 − 𝑐) + 𝑑 and 𝑦 = 𝑎 tan 𝑏(𝑥 − 𝑐) + 𝑑 is (−∞, ∞). The period of both 𝑦 = 𝑎 cot(𝑏(𝑥 − 𝜋 𝑐)) + 𝑑 and 𝑦 = 𝑎 tan 𝑏(𝑥 − 𝑐) + 𝑑 is. 𝑏 The asymptotes of 𝑦 = 𝑎 cot 𝑏(𝑥 − 𝑐) + 𝑑 𝑘𝜋 are 𝑥 = 𝑐 + , 𝑘 ∈ ℤ. 𝑏 The asymptotes of 𝑦 = 𝑎 tan 𝑏(𝑥 − 𝑐) + 𝑑 𝑘𝜋 are 𝑥 = 𝑐 + , 𝑘 is an odd integer. 2𝑏 1 Graph: 𝑦 = tan 2𝑥 2 Solution: 1 1 In 𝑦 = tan 2𝑥 , 𝑎 = , 𝑏 = 2, 𝑐 = 0, and 𝑑 = 0. 2 2 𝑘𝜋 Domain: 𝑥 ∈ ℝ: 𝑥 ≠ 𝑐 + , 𝑘 is an odd integer = 2𝑏 𝑘𝜋 𝑥 ∈ ℝ: 𝑥 ≠ , 𝑘 is an odd integer 4 Range: −∞, ∞ Solution: 𝜋 𝜋 𝜋 Period: = = 𝑏 2 2 𝑘𝜋 Asymptote: 𝑥 = 𝑐 + , 𝑘 is an odd integer; thus, the 2𝑏 𝑘𝜋 asymptotes are 𝑥 = , 𝑘 is an odd integer 4 𝑥 Graph: 𝑦 = 2 cot 3 Solution: 𝑥 1 In 𝑦 = 2 cot , 𝑎 = 2, 𝑏 = , 𝑐 = 0, and 𝑑 = 0. 3 3 𝑘𝜋 Domain: 𝑥 ∈ ℝ: 𝑥 ≠ 𝑐 + 𝑏 ,𝑘∈ℤ = 𝑥 ∈ ℝ: 𝑥 ≠ 3𝑘𝜋, 𝑘 ∈ ℤ Range: −∞, ∞ Solution: 𝜋 𝜋 Period: = 1 = 3𝜋 𝑏 3 𝑘𝜋 Asymptote: 𝑥 = 𝑐 + ,𝑘∈ ℤ; thus, the asymptotes are 𝑏 𝑥 = 3𝑘𝜋, 𝑘 ∈ ℤ

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