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Kwara State University

Adegbenro S. Ajani (Ph.D)

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magnetic fields physics Biot-Savart law electromagnetism

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This document provides course outlines and objectives for a week 6 physics class focusing on magnetic fields. It covers topics including the definition of magnetic fields, the Lorentz force, Biot-Savart law, magnetic dipoles, dielectrics, and energy in magnetic fields.

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KWARA STATE UNIVERSITY, MALETE FACULTY OF PURE AND APPLIED SCIENCES DEPARTMENT OF PHYSICS AND MATERIALS SCIENCE COURSE TITLE: GENERAL PHYSICS I (MECHANICS) COURSE CODE: PHY 102 COURSE CREDIT: 2 C UNITS COURSE LECTURER FOR WEEK 6 : Adegbenro S. AJAN...

KWARA STATE UNIVERSITY, MALETE FACULTY OF PURE AND APPLIED SCIENCES DEPARTMENT OF PHYSICS AND MATERIALS SCIENCE COURSE TITLE: GENERAL PHYSICS I (MECHANICS) COURSE CODE: PHY 102 COURSE CREDIT: 2 C UNITS COURSE LECTURER FOR WEEK 6 : Adegbenro S. AJANI (Ph.D) COURSE OUTLINES:Magnetic fields. Lorentz force. Biot-Savart and Ampère’s laws. Magnetic dipoles. Dielectrics. Energy in magnetic fields.Solved problems COURSE OBJECTIVES: By the end of this class, the students should be able to; (i) Discuss the definition of Magnetic field (ii) State the Lorentz law and write the formula for Lorentz force (iii) Explain the Biot-Savart and Ampère’s laws with applications (iv) Discuss the Magnetic dipoles and dielectric. (v) Solve Problems Involving Energy in magnetic fields. Magnetic Fields Biot-Savart Law We know that electromagnetism is an important branch of Physics that deals with electromagnetic force. It typically deals with magnetic force and electric current. Let us know about the law that relates magnetic fields to the electric current – Biot-Savart Law. What is Biot-Savart Law? Biot-Savart’s law is an equation that gives the magnetic field produced due to a current carrying segment. This segment is taken as a vector quantity known as the current element. What is the Formula of Biot-Savart’s Law? Consider a current carrying wire ‘i’ in a specific direction as shown in the above figure. Take a small element of the wire of length ds. The direction of this element is along that of the current so that it forms a vector ids. To know the magnetic field produced at a point due to this small element, one can apply Biot-Savart’s Law. Let the position vector of the point in question drawn from the current element be r and the angle between the two be θ. Then, Where, μ0 is the permeability of free space and is equal to 4π × 10-7 TmA-1. The direction of the magnetic field is always in a plane perpendicular to the line of element and position vector. It is given by the right-hand thumb rule where the thumb points to the direction of conventional current and the other fingers show the magnetic field’s direction. In the figure shown above, the direction of the magnetic field is pointing into the page. Applications of Biot-Savart’s Law Some of Biot-Savart’s Law applications are given below.  We can use Biot–Savart law to calculate magnetic responses even at the atomic or molecular level.  It is also used in aerodynamic theory to calculate the velocity induced by vortex lines. Importance of Biot-Savart Law Following are the importance of the Biot-Savart law:  Biot-Savart law is similar to Coulomb’s law in electrostatics.  The law is applicable for very small conductors too which carry current.  The law is applicable for symmetrical current distribution. Solved Problems on Biot-Savart Law Q1. Determine the magnitude of the magnetic field of a wire loop at the centre of the circle with radius R and current I. Ans: The magnitude of the magnetic field of the wire loop is given as: Q2. A circular coil of radius 5 × 10-2 m and with 40 turns is carrying a current of 0.25 A. Determine the magnetic field of the circular coil at the centre. Ans: The radius of the circular coil = 5 × 10-2 m Number of turns of the circular coil = 40 Current carried by the circular coil = 0.25 A Magnetic field is given as: Q3. Determine the magnetic field at the centre of the semicircular piece of wire with a radius 0.20 m. The current carried by the semicircular piece of wire is 150 A. Ans: The radius of the semicircular piece of wire = 0.20 m Current carried by the semicircular piece of wire = 150 A Magnetic field is given as: More Questions

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