PHY 115 Units and Dimensions 2019 PDF

Summary

This document is a past paper for a physics course, likely PHY 115, at the University of Ilorin. It covers topics in units and dimensions, including fundamental and derived quantities, offering examples and problems for calculation. The document features formulas and calculations related to the physics subject of units and dimensions.

Full Transcript

Physics Department, University of Ilorin PHY 115 UNITS AND DIMENSION Observation and measurement of physical quantities / parameters are the core of scientific activities. Measurement is the act or process of assigning size, or value to a physical quantity. Quantities are measured when we are able...

Physics Department, University of Ilorin PHY 115 UNITS AND DIMENSION Observation and measurement of physical quantities / parameters are the core of scientific activities. Measurement is the act or process of assigning size, or value to a physical quantity. Quantities are measured when we are able to quantify it by assigning value and unit to such quantities or parameters. This is done by the use of measuring equipment- which are mostly based on one physical law or the other. Quantities are categorised into two namely: fundamental quantities and derived quantities (likewise the Units- fundamental units and derived units). Fundamental quantities are quantities upon which other quantities are based while derived quantities are quantities that are obtained from fundamental quantities. Fundamental quantities, units and dimensions Quantity Unit Dimension Length Meter(m) L Time Second(s) T Mass Kilogramme(kg) M Temperature Degree Kelvin(oK) Ɵ or K Electric current Ampere(A) I or A Electric charge Coulomb(C) Q Mole(Amount of substance) Mole(mol) N Luminous intensity Candela(cd) J or C The underlined dimensions are the one adopted for this course. Derived quantities, Units and Dimension Quantity Equation Unit Dimension Velocity π‘‘π‘–π‘ π‘π‘™π‘Žπ‘π‘’π‘šπ‘’π‘›π‘‘ π‘š 𝑠 πΏπ‘‡βˆ’1 π‘‘π‘–π‘šπ‘’ Acceleration π‘£π‘’π‘™π‘œπ‘π‘–π‘‘π‘¦ π‘š 𝑠2 πΏπ‘‡βˆ’2 π‘‘π‘–π‘šπ‘’ Momentum π‘šπ‘Žπ‘ π‘  Γ— π‘£π‘’π‘™π‘œπ‘π‘–π‘‘π‘¦ π‘˜π‘”π‘š 𝑠 π‘€πΏπ‘‡βˆ’1 Force π‘šπ‘Žπ‘ π‘  Γ— π‘Žπ‘π‘π‘’π‘™π‘’π‘Ÿπ‘Žπ‘‘π‘–π‘œπ‘› π‘˜π‘”π‘š 𝑠2 π‘€πΏπ‘‡βˆ’2 Example π‘ž1 π‘ž2 Electrostatic Force = 𝐹 = π‘˜ π‘Ÿ2 1 F=[MLT -2]=[π‘˜π‘„2 πΏβˆ’2 ] This implies: [π‘˜π‘„2 ] = [𝑀𝐿3 π‘‡βˆ’2 ] [k] = 𝑀𝐿3 π‘‡βˆ’2 π‘„βˆ’2 Work done = 𝐹 Γ— 𝑑 = π‘π‘š = 𝑀𝐿2 π‘‡βˆ’2 The relationship between Work done and voltage due to separation of charges is π‘Šπ‘œπ‘Ÿπ‘˜ π‘‘π‘œπ‘›π‘’ = π‘žπ‘‰ , but the dimension of work is [𝑀𝐿2 π‘‡βˆ’2 ] Therefore, [π‘žπ‘‰] = [𝑀𝐿2 π‘‡βˆ’2 ] Implying [V] = [𝑀𝐿2 π‘‡βˆ’2 π‘„βˆ’1 ]. The quantity of heat energy transfer 𝑄 = π‘šπ‘π‘‡, obtain the dimension of the specific heat capacity (c). (Please note that Q is used as the dimension of charge above, quantity of heat is also represented with symbol Q - but not the same as the dimension of charge) The quantity of heat is in Joules β†’ dimension of Q, [𝑄] = [𝑀𝐿2 π‘‡βˆ’2 ] Using 𝑄 = π‘šπ‘π‘‡, implies Q ο€½ [𝑀𝑐𝐾] = [𝑀𝐿2 π‘‡βˆ’2 ], or 𝑀𝐿2 π‘‡βˆ’2 [c] = = 𝐿2 π‘‡βˆ’2 πΎβˆ’1 𝑀𝐾 Optics 𝑆𝑖𝑛 𝑖 Refractive index 𝑛 = 𝑆𝑖𝑛 π‘Ÿ is dimensionless. Wavelength  [L] has the dimension of length and the unit is meter. Questions πΊπ‘šπ‘€ 1. The gravitational force F is given by 𝐹 = , obtain the 𝑅2 dimension of G. 2. Acceleration due to gravity (𝑔), below the earth surface, is given 𝑏𝐺𝑀 by 𝑔 = , obtain the dimension of b. π‘Ÿ3 2 3. The force a current carrying wire will experience when placed in a magnetic field of magnitude B is FB ο€½ BIL , where I is the current passing through the wire and L is the length of the wire that is inside the field. Obtain the dimension of B. SCALAR AND VECTOR QUANTITIES Physical quantities can be grouped into two namely: scalar and vector quantities. SCALAR – A quantity defined only by magnitude e.g. Distance, Speed, Mass. Distance – Shortest space 𝑑π‘₯ π‘œπ‘Ÿ 𝑑 between two points. The unit is in meter or foot. Speed(s) – Rate of change of distance with time and is equal to (distance divided by time) Mass – Quantity of matter in a body and is measured in kg VECTOR – A quantity defined by both magnitude and direction e.g. displacement, velocity, acceleration, force. Displacement – Distance in a defined direction. 𝒅⃑ ΞΈ ---------------------- Velocity – Time rate of chance of displacement or change of distance with time in a given direction. 𝑣 = 𝑑/𝑑 = 𝑑𝑠/𝑑𝑑 = 𝑑π‘₯/𝑑𝑑 𝒖⃑ ΞΈ ---------------------- Acceleration - rate of change of velocity with time. π‘Ž = 𝑑𝑣/𝑑𝑑 π‘Žβƒ‘ 3 Force – Rate of change of momentum with time. This can be shown (later) to be the product of mass and acceleration. Addition and Subtraction of Scalars - Addition and subtraction of scalar quantity is done like numbers. Sum of d1 and d2 = d1 + d2 d1 d2 Difference between d4 and d3 is equal to d4-d3 d3 d4 – d3 d4 Note – Scalars have magnitude only e.g. mass, length, time, density, energy while Vectors have magnitude and direction. Displacement is characterized by length and direction. 𝐴𝐡⃗ is net the effect and is independent of the path taken to go from A to B. Vectors: Considering the net displacement say from A to C through AB followed by BC. The sum is not an algebraic sum Other example includes: b C Force, Velocity, Acceleration B r E Electric field strength a B Magnetic induction A The symbols for vectors are bold face letters or letters with arrow, i.e., 𝔸 or 𝐴⃗. The magnitude is represented by the modulus, i.e., the magnitude of vector 𝐴⃗ is |𝐴⃗| Vectors can be expressed in vector notation or in magnitude and the angle the vector makes with positive x-axis. In vector notation, a 2D vector, e.g., 𝐴⃗ can be written as 𝐴⃗ = 𝐴π‘₯ 𝑖 + 𝐴𝑦 𝑗 4 where Ax is the x-component of the vector, Ay is the y-component of the vector while 𝑖 and 𝑗 are the unit vectors. In terms of magnitude and angle / direction, vector 𝐴⃗ can be expressed as |𝐴⃗ |, ΞΈ. Magnitude of vector 𝐴⃗ Ay Aο€½ Ax2  Ay2 ,  ο€½ tan ο€­1 Ax Ay A  Ax x- and y- components of a vector can be obtained from the magnitude and angle representation of the vector. Ax ο€½ A cos  , Ay ο€½ A sin  Therefore, vector A can also be expressed as 𝐴⃗ = 𝐴 cos πœƒ 𝑖 + 𝐴 sin πœƒ 𝑗 Addition of Vectors The addition of two vectors can be written as r ο€½a b PROPERTIES OF VECTORS 5 Cumulative Law: 𝒂⃗ + 𝒃⃗ = 𝒃⃗ + 𝒂⃗ = 𝒓⃗ b r a a b π‘¨π’”π’”π’π’„π’Šπ’‚π’•π’Šπ’π’ π‘³π’‚π’˜ βˆ’ 𝑖.𝑒.𝑖𝑛𝑑𝑒𝑝𝑒𝑛𝑑𝑒𝑛𝑑 π‘œπ‘“ π‘œπ‘Ÿπ‘‘π‘’π‘Ÿ π‘œπ‘“ π‘”π‘Ÿπ‘œπ‘’π‘π‘–π‘›π‘”, π‘‘β„Žπ‘’ π‘ π‘’π‘š π‘œπ‘“ π‘£π‘’π‘π‘‘π‘œπ‘Ÿπ‘  𝑖𝑠 π‘‘β„Žπ‘’π‘ π‘Žπ‘šπ‘’ 𝒂⃑ + 𝒃⃑ + 𝒄⃑ = 𝒂⃑ + 𝒃⃑ + 𝒄⃑ 𝒃⃑ 𝒂⃑ + 𝒃⃑ 𝒃⃑ + 𝒄⃑ 𝒄⃑ 𝒂⃑ + 𝒃⃑ + 𝒄⃑ Subtraction - For a vector b one can define another vector ο€­ b that is of the same magnitude with b but of opposite direction as shown below. βˆ’ 𝒃⃑ + 𝒃⃑ Then, a ο€­ b ο€½ a  (ο€­ b ) π‘‡β„Žπ‘’π‘› π‘Žβƒ‘ βˆ’ 𝑏⃑ = π‘Žβƒ‘ + βˆ’ 𝑏⃑ π‘‰π‘’π‘π‘‘π‘œπ‘Ÿ 𝑖𝑠 β„Žπ‘œπ‘Ÿπ‘–π‘§π‘œπ‘›π‘‘π‘Žπ‘™ π‘Žπ‘›π‘‘ 𝑖𝑑𝑠 π‘šπ‘Žπ‘”π‘›π‘–π‘‘π‘’π‘‘π‘’ 5 𝑒𝑛𝑖𝑑𝑠 π‘£π‘’π‘π‘‘π‘œπ‘Ÿ 𝑏 𝑖𝑠 450 π‘“π‘Ÿπ‘œπ‘š π‘‘β„Žπ‘’ β„Žπ‘œπ‘Ÿπ‘–π‘§π‘œπ‘›π‘‘π‘Žπ‘™ Example: vector a is along the horizontal and its magnitude is 5 units, vector b makes angle 45Β° with the horizontal and its of magnitude 4 units while 6 vector c makes angle 30Β° with the vertical axis and its magnitude is 3 units. Compute a b ο€­ c. Unit Vector: This is a vector of magnitude 1 in a particular direction. For example,  in 1D, vector π‘Žβƒ— = 2.5π‘Ž = 2.5𝑖, where 2.5 is the magnitude and a or 𝑖 is the unit vector. 𝒂⃑ 𝒋 a π’Š π‘ˆβƒ—π‘Ž U=1 π’Œ Sum of Two Vectors (𝒂⃗ 𝒂𝒏𝒅 𝒃⃗) 𝒓⃑ = 𝒂⃑ + 𝒃⃗ π‘»π’˜π’ 𝒗𝒆𝒄𝒕𝒐𝒓 𝒂⃑ + 𝒃⃗ 𝒂𝒓𝒆 𝒆𝒒𝒖𝒂𝒍 π’Šπ’‡ π’•π’‰π’†π’Šπ’“ π’„π’π’“π’“π’†π’”π’‘π’π’π’…π’Šπ’π’ˆ π’„π’π’Žπ’‘π’π’π’†π’π’•π’” 𝒂𝒓𝒆 𝒆𝒒𝒖𝒂𝒍 𝒂𝒏𝒅 π’Šπ’•π’” 𝒓𝒆𝒔𝒖𝒍𝒕𝒂𝒏𝒕 𝒗𝒆𝒄𝒕𝒐𝒓 π’Šπ’” 𝒓⃑, i.e., 𝒓𝒙 = 𝒂𝒙 + 𝒃𝒙 , π’“π’š = π’‚π’š + π’ƒπ’š π‘Ÿπ‘¦ 𝒓= π’“πŸπ’™ + π’“πŸπ’š , π‘‘π‘Žπ‘›πœƒ = (in magnitude and direction / angle) π‘Ÿπ‘₯ π‘Ÿβƒ— = π‘Ÿπ‘₯ 𝑖 + π‘Ÿπ‘¦ 𝑗 (in vector notation) EXAMPLE – Three coplanar vectors are expressed with respect to a certain rectangular coordinates system of a given reference frame as 𝒂⃑ = πŸ’π’Šβƒ‘ βˆ’ 𝒋 𝒃⃑ =βˆ’ πŸ‘π’Š + πŸπ’‹βƒ‘ 𝒄⃑ =βˆ’ πŸ‘π’‹βƒ‘ 𝑻𝒉𝒆 π’„π’π’Žπ’‘π’π’π’†π’π’•π’” 𝒂𝒓𝒆 π’ˆπ’Šπ’—π’†π’ π’Šπ’ π’‚π’“π’ƒπ’Šπ’•π’“π’‚π’“π’š π’–π’π’Šπ’•π’”. π‘­π’Šπ’π’… 𝒕𝒉𝒆 𝒗𝒆𝒄𝒕𝒐𝒓 𝒓 π’˜π’‰π’Šπ’„π’‰ π’Šπ’” 𝒕𝒉𝒆 π’”π’–π’Ž 𝒐𝒇 𝒕𝒉𝒆𝒔𝒆 𝒗𝒆𝒄𝒕𝒐𝒓𝒔. 𝒓𝒙 = 𝒂𝒙 + 𝒃𝒙 + 𝒄𝒙 = πŸ’ βˆ’ πŸ‘ + 𝟎 = 𝟏 7 π’“π’š = π’‚π’š + π’ƒπ’š + π’„π’š =βˆ’ 𝟏 + 𝟐 βˆ’ πŸ‘ =βˆ’ 𝟐 𝒓⃑ = π’Šβƒ‘π’“π’™ + π’‹βƒ‘π’“π’š 𝒓⃗ = π’Šβƒ‘ βˆ’ πŸπ’‹βƒ‘ and can be represented as shown below π‘Ίπ’Šπ’π’„π’† π’Žπ’‚π’ˆπ’π’Šπ’•π’–π’…π’† 𝒓 = π’“πŸπ’™ + π’“πŸπ’š = 𝟏+πŸ’ ΞΈ = πŸ“ = 𝟐.πŸπŸ’ -2 The angle the vector makes with positive x-axis is 360ο‚° ο€­ . 1 𝐴𝑛𝑔𝑙𝑒 π‘šπ‘Žπ‘‘π‘’ π‘€π‘–π‘‘β„Ž π‘π‘œπ‘ π‘–π‘‘π‘–π‘£π‘’ π‘₯ βˆ’ π‘Žπ‘₯𝑖𝑠 π‘šπ‘’π‘Žπ‘ π‘’π‘Ÿπ‘’π‘‘ π‘π‘œπ‘’π‘›π‘‘π‘’π‘Ÿπ‘π‘™π‘œπ‘π‘˜π‘€π‘–π‘ π‘’ 2 π‘‡π‘Žπ‘›βˆ’1 ( βˆ’ ) = 296.57Β° 1 MULTIPLICATION OF VECTORS One can not add vector and scalar in each task. One can add and multiply vectors with vectors. One can also multiple a vector by a scalar. Three Kinds – a) Multiplication of a vector by scalar b) Multiplication of 2 vectors yielding scalar (dot product) c) Multiplication of 2 vectors yielding vectors (cross product), etc. VECTOR-SCALAR MULTIPLICATION Scalar k, can be used to multiply vector π‘Žβƒ— to have Product = π‘˜ π‘Žβƒ‘ A new vector with magnitude (k | a |) will have the same direction as π‘Žβƒ— 1 βˆ’ π‘Ž 𝑛𝑒𝑀 π‘£π‘’π‘π‘‘π‘œπ‘Ÿ π‘€π‘–π‘‘β„Ž π‘šπ‘Žπ‘”π‘›π‘–π‘‘π‘’π‘‘π‘’ π‘˜ π‘‘π‘–π‘šπ‘’π‘  π‘Žπ‘  π‘Žβƒ—. π‘†π‘Žπ‘šπ‘’ π‘‘π‘–π‘Ÿπ‘’π‘π‘‘π‘–π‘œπ‘› π‘Žπ‘  π‘Žβƒ—. πΆβ„Žπ‘’π‘π‘˜ βˆ’ 𝑖𝑓 π‘˜ 𝑖𝑠 + 𝑣𝑒 To divide by scalar, multiply by reciprocal of k 8 1.π‘Žβƒ— π‘˜ VECTOR-VECTOR MULTIPLICATION I. Scalar (or dot.) II. Vector (or cross Γ— ) SCALAR PRODUCTS π‘Žβƒ—.𝑏⃗ = π‘Žπ‘ cos πœƒ 𝑀hπ‘’π‘Ÿπ‘’ π‘Ž 𝑖𝑠 𝑑h𝑒 π‘šπ‘Žπ‘”π‘›π‘–π‘‘π‘’π‘‘π‘’ π‘œπ‘“ π‘Žβƒ—, 𝑏 𝑖𝑠 𝑑h𝑒 π‘šπ‘Žπ‘”π‘›π‘–π‘‘π‘’π‘‘π‘’ π‘œπ‘“ 𝑏⃗ π‘Žπ‘›π‘‘ cos πœƒ 𝑖𝑠 𝑑h𝑒 π‘π‘œπ‘ π‘–π‘›π‘’ π‘œπ‘“ 𝑑h𝑒 π‘Žπ‘›π‘”π‘™π‘’ 𝑏𝑒𝑑𝑀𝑒𝑒𝑛 𝑑h𝑒 π‘‘π‘€π‘œ π‘£π‘’π‘π‘‘π‘œπ‘Ÿπ‘ . 𝑇h𝑒𝑠, π‘ π‘π‘Žπ‘™π‘Žπ‘Ÿ π‘π‘Ÿπ‘œπ‘‘π‘’π‘π‘‘ π‘π‘Žπ‘› 𝑏𝑒 π‘Ÿπ‘’π‘”π‘Žπ‘Ÿπ‘‘π‘’π‘‘ π‘Žπ‘  𝑑h𝑒 π‘π‘Ÿπ‘œπ‘‘π‘’π‘π‘‘ π‘œπ‘“ 𝑑h𝑒 π‘šπ‘Žπ‘”π‘›π‘–π‘‘π‘’π‘‘π‘’ π‘œπ‘“ π‘œπ‘›π‘’ π‘£π‘’π‘π‘‘π‘œπ‘Ÿ π‘Žπ‘›π‘‘ 𝑑h𝑒 π‘π‘œπ‘šπ‘π‘œπ‘›π‘’π‘›π‘‘ π‘œπ‘“ 𝑑h𝑒 π‘œπ‘‘hπ‘’π‘Ÿ 𝑖𝑛 𝑑h𝑒 π‘‘π‘–π‘Ÿπ‘’π‘π‘‘π‘–π‘œπ‘› π‘œπ‘“ 𝑑h𝑒 π‘“π‘–π‘Ÿπ‘ π‘‘. For example, the dot product of vector a and vector b , i.e., 𝑐 = π‘Žβƒ—.𝑏⃗ can be obtained if a and b are explicitly defined. For a ο€½ a x i  a y j and b ο€½ bx i  by j , a. b ο€½ ( a x i  a y j ).(bx i  by j ) ο€½ a x bx  a y by Since, i.i ο€½ j. j ο€½ 1, and i. j ο€½ j.i ο€½ 0 This implies that a xbx  a y by ο€½ a.b cos The equation above can be used to obtain the angle between two vectors. Example 1: Calculate the angle between two vectors ο€­ 3i  4 j and 2i  3 j Solution: Using π‘Žπ‘₯ 𝑏π‘₯ + π‘Žπ‘¦ 𝑏𝑦 = π‘Ž.𝑏 cos πœƒ 9 ο€­ 6  12 ο€½ 32  4 2. 2 2  32 cos  6 6 ο€½ 5 ο‚΄ 13 cos  ;  ο€½ cos ο€­1 ο€½ cos ο€­1 0.3328 18.0277  ο€½ 70.56ο‚° VECTOR PRODUCT 𝑐⃗ = π‘Žβƒ— Γ— 𝑏⃗ Magnitude of vector 𝑐⃗ can be written as c ο€½ ab sin  where ΞΈ is the angle between a and b Example Calculate the angle between two vectors ο€­ 3i  4 j and 2i  3 j using magnitude c ο€½ ab sin . Solution i j k (ο€­3i  4 j ) ο‚΄ ( 2i  3 j ) ο€½ ο€­ 3 4 0 ο€½ i (0) ο€­ j (0)  k (ο€­9 ο€­ 8) ο€½ ο€­17k 2 3 0 Therefore using c ο€½ ab sin  , note that magnitude of ο€­17 k is 17. 17 17 ο€½ 18.0277 sin  ,  ο€½ sin ο€­1 ο€½ sin ο€­1 0.9430 ο€½ 70.56 18.0277  is the angle between a and b. By definition, the direction of 𝐢, the cross βƒ— product of a and b is perpendicular to the plane formed by a and b or the plane that contains a and b 10 c c 𝒃⃑ b 𝒂⃑ b 𝒂 𝒂⃑ 𝒄' = 𝒃⃑ Γ— 𝒂⃑ π‘Žβƒ— Γ— 𝑏⃗ is pronounced as "π‘Žβƒ— cross 𝑏⃗" 𝑏⃗ Γ— π‘Žβƒ— β‰  π‘Žβƒ— Γ— 𝑏⃗ π‘Žβƒ— Γ— 𝑏⃗ =βˆ’ 𝑏⃗ Γ— π‘Žβƒ— For cross product, i ο‚΄ j ο€½ k , j ο‚΄ k ο€½ i , k ο‚΄ i ο€½ j , i ο‚΄ k ο€½ ο€­ j , j ο‚΄ i ο€½ ο€­ k , k ο‚΄ j ο€½ ο€­i π‘π‘’π‘π‘Žπ‘’π‘ π‘’ π‘šπ‘Žπ‘”π‘›π‘–π‘‘π‘’π‘‘π‘’ π‘œπ‘“ π‘Žπ‘π‘ π‘–π‘›πœƒ = π‘π‘Žπ‘ π‘–π‘›πœƒ 𝑏𝑒𝑑 π‘‘β„Žπ‘’ π‘‘π‘–π‘Ÿπ‘’π‘π‘‘π‘–π‘œπ‘›π‘  π‘Žπ‘Ÿπ‘’ π‘œπ‘π‘π‘œπ‘ π‘–π‘‘π‘’. Examples of such cross products include – Torque, angular momentum, force of a moving charge in a magnet, flow of electromagnetic energy. Vector Products Tensor – generated by multiplying each of three components of one vector by the three components of another vector. Tensor 2nd Rank – Has nine numbers associated with it. Vector – Three numbers Scalar – One Example of Tensors – Mechanical and Electrical Stress, Moments, Products of Inertia, Strain. PROPERTIES OF VECTORS What happens to the laws of physics when simple operations such as translation and rotation of coordinates are performed? Coordinate system π‘₯,𝑦,𝑧 π‘‰π‘’π‘π‘‘π‘œπ‘Ÿπ‘  π‘Žβƒ—, 𝑏⃗, π‘Ÿβƒ— 11 π‘…π‘’π‘™π‘Žπ‘‘π‘–π‘œπ‘›π‘ β„Žπ‘–π‘ 𝑏𝑒𝑑𝑀𝑒𝑒𝑛 π‘‘β„Žπ‘’π‘š π‘Ÿβƒ— = π‘Žβƒ— + 𝑏⃗ 𝐡𝑦 π‘’π‘Žπ‘Ÿπ‘™π‘–π‘’π‘Ÿ π‘‘π‘’π‘“π‘–π‘›π‘–π‘‘π‘–π‘œπ‘› π‘œπ‘“ π‘ π‘’π‘š π‘Ÿπ‘₯ = π‘Žπ‘₯ + 𝑏π‘₯ π‘Ÿπ‘¦ = π‘Žπ‘¦ + 𝑏𝑦 π‘Ÿπ‘§ = π‘Žπ‘§ + 𝑏𝑧 Consider a New coordinate system π‘₯,𝑦,𝑧 with properties I. Origin does not coincide with the origin of the first coordinate system π‘₯,𝑦,𝑧 – Translation II. Its three axes are not parallel to the corresponding axes in the first system – Rotation Representation of vectors π‘₯,𝑦,π‘Ÿ in the new system would in general prove to be different. Let’s put them in primes. The relationship between them however would be: π‘Ÿπ‘₯ ' = π‘Žπ‘₯ ' + 𝑏𝑧 ' π‘Ÿ 𝑦 ' = π‘Ž 𝑦 ' + 𝑏𝑦 ' π‘Ÿπ‘§ ' = π‘Žπ‘§ ' + 𝑏𝑧 ' And, the relationship π‘Ÿβƒ— = π‘Žβƒ— + 𝑏⃗ 𝑠𝑑𝑖𝑙𝑙 β„Žπ‘œπ‘™π‘‘π‘  Consequently, it may be said that relations among vectors are invariant (unchanged) with respect to translation or rotation of coordinates. I.e. the laws of physics are unchanged when we rotate or translate the reference system. M y x i j Z k y’ 𝑗 Z ’ π‘˜ 𝑖 x’ M’ M’ 12 (a) is left handed (b) is right handed The other is a mirror image of one 𝑖𝑛 π‘Ž 𝑖 Γ— 𝑗 =βˆ’ π‘˜ 𝑏 𝑖×𝑗=π‘˜ VIOLATION (1956) Decay of some elementary particles showed that the result was independent of the handedness whether left or right. i.e., the experiment and its mirror image would yield different results. This leads to question on the symmetry of physical laws. 13

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